... x−2 = (t3 − 1) x3 = Do vˆy a −5 /3 t3 t2 (t3 − 1)− dt = 3 1 t + 2t3 t−2 3 −t+C = C − = t dt − dt = −2 2t3 + 3x =C− · 2x (1 + x3 )2 I3 = − (t3 − 1)2 /3 − t3 dt t3 ´ ıch a a Chu.o.ng 10 T´ phˆn ... + x 3 = t3 ⇒ + x3 = t3x3 ´ ’ ıch o a a a 10.2 C´c l´.p h`m kha t´ l´.p c´c h`m so cˆp a o a 43 T` d´ u o t3 , + x3 = , x = (t3 − 1)− 3 1 t t −1 2 −4 dx = −t (t − 1) dt, x−2 = (t3 − 1) x3 = ... +u+1 35 x+1 ) dx √ x2 − (DS 34 x2 + ) (DS √ 2x2 + √ (DS x 3 (2x2 − 1) x2 + 1) (DS − x−1 (3x + 4)(2 + x3)− ) √ + x3 dx √ √ x2( x + 1 )3 √ x dx √ x+1 √ x3 (DS 33 √ t5 2t3 − + t , t = + x2 /3) (DS...