... so.cˆa´p 43 T`u.d´ox 3 =1t 3 − 1, 1+x 3 =t 3 t 3 − 1,x=(t 3 − 1)−1 3 dx = −t2(t 3 − 1)−4 3 dt, x−2=(t 3 − 1)2 3 .Do vˆa.yI 3 = −(t 3 −1)2 /3 t 3 t 3 − 1−5 /3 t2(t 3 − ... 2x2)−2 3 dx.(DS.x2+12√2x2+1)28.dxx4√1+x2.(DS.1 3 x 3 (2x2− 1)√x2+1)29.dxx2(1 + x 3 )5 /3 .(DS. −18x−1(3x + 4)(2 + x 3 )−2 3 ) 30 .dx√x 3 31+4√x 3 .(DS. −2 3 (x− 3 4+1)2) 31 .dx 3 √x2( 3 √x +1) 3 .(DS. ... +1) 3 .(DS. − 3 2( 3 √x +1)2) 32 . 3 √x 3 √x +1dx.(DS. 6u77− 3 5u5+ u 3 −u2,u2= 3 √x +1) 33 .dxx6√x2− 1.(DS.u55−2u 3 3+ u, u =√1 −x−2) 34 .dxx 3 √1+x5.(DS.110lnu2−2u...