A textbook of Computer Based Numerical and Statiscal Techniques part 6 pptx
A textbook of Computer Based Numerical and Statiscal Techniques part 6 pptx
... between 0 .65 7 and 0 .66 5.Eighth approximation: The eighth approximation to the root is given by 80 .65 7 0 .66 50 .66 12x+==From last two approximations, i.e.,70 .6 65x= and 80 .6 61x= ... positive.Therefore f (0 .67 3) is positive and f(0 .65 7) is negative so the root lies between 0 .65 7 and 0 .67 3.ALGEBRAIC AND TRANSCENDENTAL EQUATION41Seventh approximation: The seventh approximation to the ... (approximation) a and b (where (a > b)) such thatf (a) . f(b) < 0.Step 2: Evaluate the mid point x1 of a and b given by x1 = 12 (a + b) and also evaluatef(x1).Step 3: If f (a) ....
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A textbook of Computer Based Numerical and Statiscal Techniques part 19 pptx
... the argument half waybetween the arguments at q and r is +B A, 24 where A is the arithmetic mean of q and r and B is arithmeticmean of 3q – 2p – s and 3r – 2s – p.Sol. Given A is the arithmetic ... r and s corresponds to argument a, a + h, a + 2h and a + 3h respectivelythen the value of the argument lying half way between a + h and a + 2h will be a + h + 2h i.e., a + 32hHence ,a ... series of which 23 .6 is the6th term. Find the first and tenth terms of the series.xy34 5 6 7 8 94.8 8.4 14.5 23 .6 36. 2 52.8 73.9174 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES (a) Here,...
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A textbook of Computer Based Numerical and Statiscal Techniques part 20 pptx
... 18) 26 −− −−×− + ×−= 235 – 24 .65 – 10. 766 25 – 1.0 766 25= 235 – 36. 492875= 198.507 { 198∴ Total no. of candidates who obtained fewer than 70 marks are 198.Example 6. The area A of a circle of ... of candidates who obtained marks between certain limitsare as follows:MarksNo of candidates−−−−−0192039405 960 798099. 41 62 65 50 17Find no. of candidates who obtained fewer than 70 marks.Sol. ... maturing at the age of 63 :45 50 55 60 65 ( .) 114.84 96. 16 83.32 74.48 68 .48AgePremium in Rs[Ans. 70.585152] 6. The values of annuities are given for the following ages. Find the value of annuity...
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A textbook of Computer Based Numerical and Statiscal Techniques part 30 pptx
... dxa xdxa xdxa xdx 111135/2 2 40120000x dxa xdxa xdxa xdx=++∫∫∫∫or Simplifying above equations, we get12001201222332234523457aa a aaaaaa++=++ =++=284 COMPUTER BASED NUMERICAL ... NUMERICAL AND STATISTICAL TECHNIQUES Minimax polynomial approximation: Let f(x) be continuous on [a, b] and it isapproximated by the polynomial Pn (x) = a 0 + a 1x + +a nxn , then the minimax ... bnnaa a a a wxdx a xwxdx a xwxdx wxfxdx() () () () ()2101 bb b bnnaa a a a xw x dx a x w x dx a x w x dx xw x f x dx++++ =∫∫ ∫ ∫() () () ()()1201 bb bbnnnnnaa aa a x w...
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A textbook of Computer Based Numerical and Statiscal Techniques part 35 pptx
... numerical solutions of differential equations. In researches,especially after the advent of computer, the numerical solutions of the differential equations havebecome easy for manipulations. Hence, ... (Proved)PROBLEM SET 6. 21. Use Trapezoidal rule to evaluate 130xdx∫ consisting five sub-intervals. [Ans. 0. 26] 2. Calculate an approximate value of integral /20sinxdxπ∫, by using Trapezoidal rule.[Ans. ... = 0 .69 315452. Ans. 6. 10 EULER-MACLAURIN’S FORMULAThis formula is based on the expansion of operators. Suppose () (),Fx fx∆= then an operator 1−∆,called inverse operator, is defined as...
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A textbook of Computer Based Numerical and Statiscal Techniques part 40 pptx
... sensitiveto small changes in A and B i.e., small change in A or B causes a large change in the solution of the system. On the other hand if small changes in A and B give small changes in the solution,the ... NUMERICAL AND STATISTICAL TECHNIQUES largest coefficient of y. We continue this process till last equation. This procedure is known aspartial pivoting. In general, the rearrangement of equation ... approximations: 1.075,x = 2.524y = and 2. 765 z = correct to three decimals. Ans.8 .6. 2 Guass-Seidel MethodThis is a modification of Gauss-Jacobi method. As before, the system of the linear equations....
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A textbook of Computer Based Numerical and Statiscal Techniques part 41 pptx
... taking suitable scale when the value of x are given at equally spaced intervals.Let h be the width of the interval at which the values of x are given and let the origin of x and y be taken ... a x b x=+∑∑∑ (5)The equation ()3 and ()4 are known as normal equations.On solving equations ()3 and ()4, we get the value of a and b. Putting the value of a and b in equation ... best values for a and b using the observedvalues of v and p. Thus the general problem is to find a suitable relation or law that may existbetween the variables x and y from a given set of...
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A textbook of Computer Based Numerical and Statiscal Techniques part 46 pptx
... the type and nature of the variations in the data.2. The segregation and study of the various components is of paramount importance to a businessman in the planning of future operations and in ... 1 = 64 .41978 2 58 + 3.4 × 2 = 64 .8Example 8. Fit a straight-line trend equation by the method of least square and estimate the trendvalue.Year 1 961 1 962 1 963 1 964 1 965 1 966 1 967 1 968 Values ... BASED NUMERICAL AND STATISTICAL TECHNIQUES If quarterly data are given, first find quarterly totals for each quarter and the averagesfor the four-quarter of the years. To find these averages,...
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A textbook of Computer Based Numerical and Statiscal Techniques part 50 pptx
... 0.147=4 76 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Sol. Mean ChartMean of 10 sample mean 44244.210 10xX ===∑Mean Range of 10 sample ranges 585.810 10RR ===∑As we have, ... removed.478 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES whether there are any assignable causes. If assignable causes found, the process should bere-adjusted to remove assignable cause.2052042032022012001991981971 96 195Sample ... cause.2052042032022012001991981971 96 195Sample Mean0 2 4 6 8 10 12Sample NumberMean ChartFIG. 11.19Range Chart108 6 420Sample Range0 5 10 15Sample NumberFIG. 11.20Example 3. In a glass factory, the task of quality...
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A textbook of Computer Based Numerical and Statiscal Techniques part 58 pptx
... i);break;}}}return 0;}ArraysThe declarationint i;declares a single variable, named i, of type int. It is also possible to declare an array of severalelements. 564 COMPUTER BASED NUMERICAL ... ewhere v is any vairable (or anything like a[ i]), op is any of the binary arithmetic operators, and e is any expression.558 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES printf("can’t compute ... performance.Function BasicsIt has a name that you call it by, and a list of zero or more arguments or parameters that you handto it for it to act on or to direct its work; it has a body containing the actual...
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Từ khóa: the appropriate application of computer aided design and manufacture techniques in silicone facial prostheticsdistance calculations based on molecules described by a vector of 1 apos s and 0 apos sebook a textbook of assaying for the use of those connected with mines by cornelius beringer and john jacob beringerbreak the map into regions based upon a combination of management goals sources and habitatsa brief history of computer music languages and systems the synergy between technology and creativitya culture of creativity design education and the creative industriesa study of perceptual learning styles and achievementa period of slow economic growth and high inflationa period of robust economic growth and high employmenthistory of computer based control systemsstructure and interpretation of computer programs abelson and sussman mit pressa summary of the first two and a half partspath—a foundation of file based i othe morality of hiv aids a comparison of russian orthodox church and secular ngo approachessusceptibility testing protocols for antibiograms and preventive surveillance a continuum of data collection analysis and presentationBáo cáo quy trình mua hàng CT CP Công Nghệ NPVNghiên cứu sự hình thành lớp bảo vệ và khả năng chống ăn mòn của thép bền thời tiết trong điều kiện khí hậu nhiệt đới việt namNghiên cứu tổ chức chạy tàu hàng cố định theo thời gian trên đường sắt việt namđề thi thử THPTQG 2019 toán THPT chuyên thái bình lần 2 có lời giảiGiáo án Sinh học 11 bài 13: Thực hành phát hiện diệp lục và carôtenôitGiáo án Sinh học 11 bài 13: Thực hành phát hiện diệp lục và carôtenôitNGHIÊN CỨU CÔNG NGHỆ KẾT NỐI VÔ TUYẾN CỰ LY XA, CÔNG SUẤT THẤP LPWAN SLIDEQuản lý hoạt động học tập của học sinh theo hướng phát triển kỹ năng học tập hợp tác tại các trường phổ thông dân tộc bán trú huyện ba chẽ, tỉnh quảng ninhTrả hồ sơ điều tra bổ sung đối với các tội xâm phạm sở hữu có tính chất chiếm đoạt theo pháp luật Tố tụng hình sự Việt Nam từ thực tiễn thành phố Hồ Chí Minh (Luận văn thạc sĩ)Nghiên cứu, xây dựng phần mềm smartscan và ứng dụng trong bảo vệ mạng máy tính chuyên dùngNghiên cứu khả năng đo năng lượng điện bằng hệ thu thập dữ liệu 16 kênh DEWE 5000Thơ nôm tứ tuyệt trào phúng hồ xuân hươngThiết kế và chế tạo mô hình biến tần (inverter) cho máy điều hòa không khíBT Tieng anh 6 UNIT 2Tăng trưởng tín dụng hộ sản xuất nông nghiệp tại Ngân hàng Nông nghiệp và Phát triển nông thôn Việt Nam chi nhánh tỉnh Bắc Giang (Luận văn thạc sĩ)Giáo án Sinh học 11 bài 14: Thực hành phát hiện hô hấp ở thực vậtTrách nhiệm của người sử dụng lao động đối với lao động nữ theo pháp luật lao động Việt Nam từ thực tiễn các khu công nghiệp tại thành phố Hồ Chí Minh (Luận văn thạc sĩ)Đổi mới quản lý tài chính trong hoạt động khoa học xã hội trường hợp viện hàn lâm khoa học xã hội việt namHIỆU QUẢ CỦA MÔ HÌNH XỬ LÝ BÙN HOẠT TÍNH BẰNG KIỀMTÁI CHẾ NHỰA VÀ QUẢN LÝ CHẤT THẢI Ở HOA KỲ