... 0 3,384 12 100% 92 , 29% 44 0, 694 %H 100% 7, 71% 18 a mCO2 %C (1,5 ) mH 2O %O = 100% (92 , 29% + 7,71%) = % Khụng cú oxi A ch cú C v H CTPT dng CxHy x: y b (1 ) 92 , 29 7, 71 : 1:1 12 ... 56,2: 84 = 0,669mol Lng CO2 nh nht a = S mol CO2 = 56,2: 197 = 0,285mol 0,285 < nCO2 < 0,6 69 Nu nCO2 = 0,285 mol < nCa(OH)2; Tc l khụng cú phn ng nCaCO3 = nCO2 = 0,285 mol Nu nCO2 = 0,6 69 mol > nCa(OH)2 ... ).M 0,5 n n n (**) - T (*) v (**) => M(0,09M 0,81n) =0 => * M=0 (loi) * 0, 09 M 0,81n = => M = 9n - Vi n=3 ; M = 27 => M l kim loi nhụm (Al) 3,61.3 0, 19. 27 0,05 56.3 2.27 => %mFe = 0,05.56...