toán cao cấp tập 1 nguyễn đình trí
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... 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 ... 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 ... Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 22 :13 :22 ICT 2 012 12 7.0.0 .1 downloaded 60384.pdf at Thu Aug 16 ...
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... nhiˆe`ubiˆe´n 10 99 .1 D-a.oh`amriˆeng 11 09 .1. 1 D-a.o h`am riˆeng cˆa´p1 11 09 .1. 2 D-a.o h`am cu’a h`am ho..p 11 19 .1. 3 H`am kha’vi 11 19 .1. 4 D-a.o h`am theo hu.´o.ng 11 29 .1. 5 ... bi.ch˘a.n trˆen. Thˆa.tvˆa.y:an= 1 5 +1 + 1 52 +1 + 1 53 +1 + ···+ 1 5n +1 < 1 5+ 1 52+ ···+ 1 5n= 1 5− 1 5n +1 1 − 1 5= 1 4 1 − 1 5n< 1 4·Nhu.vˆa.y d˜ay and˜achodo.ndiˆe.u ... 1) 16 . an= n −3√n3− n2.(DS. 1 3) 17 . an= 1 − 2+3− 4+5−···−2n√n2 +1+ √4n2 +1 .(DS. − 1 3) 18 . an= 1 1 · 2+ 1 2 · 3+ ···+ 1 n(n +1) .Chı’dˆa˜n.´Ap du.ng 1 n(n +1) = 1 n− 1 n...
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... − 1+ i22n +1 1 − 1+ i2·Ta cˆa`n t´ınh 1+ i22n +1 = 1+ i222n=i22n=i2n22n= 1 22n·Do d´oσ = 1 − 1 22n 1 − 1+ i2=2 1 − 1 22n 1 − i× 1+ i 1+ i= 1 ... = 1+ 1+ i2 1+ 1+ i22 1+ 1+ i222··· 1+ 1+ i22n.Gia’i. Nhˆan v`a chia biˆe’uth´u.cd˜achov´o.i1− 1+ i2ta c´oσ = 1 − 1+ i22n2 1 − 1+ i2= 1 − 1+ i22n +1 1 ... chı’khia2+ b2− 1 (a +1) 2+ b2=0⇐⇒ a2+ b2 =1. B`AI TˆA.PT´ınh 1. (1 + i)8− 1 (1 − i)8 +1 · (DS. 15 17 )2. (1+ 2i)3+ (1 2i)3(2 − i)2− (2 + i)2· (DS. − 11 4i)3.(3 −...
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... d´oP (z)=a0zn+ a 1 zn 1 + ···+ an 1 z + an= a0zn+ a 1 zn 1 + ···+ an 1 z + an= a0(z)n+ a 1 (z)n 1 + ···+ an 1 z + an= a0(z)n+ a 1 (z)n 1 + ···+ an 1 z + an= P (z).T`u.d´oc˜ung ... chia:z2z 1 =a 1 a2+ b 1 b2a2 1 + b2 1 + ia 1 b2− a2b 1 a2 1 + b2 1 ·C´AC V´IDU.V´ı d u. 1. 1 +T´ınh in.T`u.d´och´u.ng minh r˘a`nga) in+ in +1 + in+2+ in+3=0;b) ... 1 (a +1) 2+ b2=0⇐⇒ a2+ b2 =1. B`AI TˆA.PT´ınh 1. (1 + i)8− 1 (1 − i)8 +1 · (DS. 15 17 )2. (1+ 2i)3+ (1 2i)3(2 − i)2− (2 + i)2· (DS. − 11 4i)3.(3 − 4i)(2 − i)2+i−(3+4i)(2...
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