. 10 0,03 *(Cu-Y) = 10 18,8. 10 10, 4. 10 0,03 = 10 8,37 ; In = K3K4K5 h3 + K3h2 = 10 3,55 *(Cu-In) = 10 17,9. 10 10, 4. 10 3,55 = 10 3,95 Với *(Cu-In). Fe(SCN)2+ = 10 3,03 C 6,13 .10 3 3 .10 5 [ ] (6,13 .10 3 3 .10 5 + x) x (3 .10 5 x) x = 3,98 .10 6 [Fe(SCN)2+] = 3 .10 5 3,98 .10 6 = 2,602 .10 5 > 6 .10 6 : Vậy. h2 + K3h = 10 16 42 10 10 + 10 11 16 = 10 6,45 Fe = 11 + h¯1 = 1 1 + 10 2 17 .10 5 = 10 2,83 Al = 11 + 'h¯1 = 11 + 10 5 .10 5 = 12 *FeY...