... ΡbΟ = 39 3, 13 + + 110, 43 + 219, 03 = − 63, 67( KJ ) ∆G = ∆GCΟ2 + ∆GΡb − ∆GCΟ − ∆GΡbΟ = 39 4,00 + + 137 ,14 + 198,14 = −67,72( KJ ) ln Κ Ρ = − ∆G 67,72.1000 = = 27 ,33 RΤ 8 ,31 4.298 → Κ Ρ = e 27 ,33 = 7,4.1011 ... Τ + 5 ,3 d ln Κ Ρ 5020 1,75 ∆Η =− − = dΤ 2 ,30 3Τ 4,575Τ Τ ⇔ ∆Η = −22966,5 − 3, 476Τcal b) Ο ∆G700 = −22971, 83 + 3, 477.700 ln 700 + 5 ,3. 700 = 33 17.2cal 33 ∆Η Ο = −22966,5 − 3, 476.700 = −2 539 9,7cal ... ng: a /3 mol a /3 mol Cân b ng: 2a /3 mol 2a /3 mol Kn = K X = KC = 2) N u h n h p → (a / 3) 2 (2a / 3) 2 mol a /3 mol mol a /3 mol a /3 mol C2H5OH a /3 mol = 0,25 u g m mol Este n mol nư c 29 CH3COOC2H5...