... : shown in figure System and Control Ngo Quang Hieu LOGO Nhận dạng thông số hệ thống K =∆ δ τ = 1. 5(t63% − t28% ) θ = t63% − τ System and Control Ngo Quang Hieu LOGO Nhận dạng thông số hệ thống...
... Earl of Suffolk, Grand Treasurer of England under James I., bears witness that in the one year, 16 15, fifty-two flasks, bladders, and tarred vessels, containing mention of sinking ships, were brought...
... bridging, or MAC address, table PC1, with MAC address 11 11. 111 1 .11 11, is connected to Switch SW1’s Fa0 /1 interface PC2, with MAC address 2222.2222.2222, is connected to SW1’s Fa0/2 interface PC3, with ... of switching 17 5 Figure 7- 4 Example of switch forwarding logic 17 6 Figure 7- 5 Example of switch filtering logic 17 7 Figure 7- 6 Example of how a switch learns MAC addresses 17 8 Table 7- 2 Summary ... logic is that simple 17 7 18 28xbook.fm Page 17 8 Thursday, July 26, 20 07 3 :10 PM 17 8 Chapter 7: Ethernet LAN Switching Concepts Figure 7- 6 depicts the same network as Figure 7- 4, but before the...
... physical limitations become less relevant 12 Networks are integral in our daily lives http://www.youtube.com/watch? v=fQKNvPn3V8&mode=related&search= 13 14 Examples of Today’s Popular Communication ... easy to 10 Networks Supporting the Way We Live http://www.youtube.com/watch?v= CQzUsTFqtW0 Today’s networks carry between many different types of devices: Voice video streams Text graphics 11 The ... individuals can also build their own wikis to capture collected knowledge on a particular subject 17 Podcasting Podcasting is an audio-based medium that originally enabled people to record audio...
... Sum: 11 0 010 1 011 0 010 10 1s complement: 0 011 00 010 011 010 1 Total: 11 111 011 111 111 11 What if there is an error? UDP does nothing to recover the error It is up to the application layer protocol (example ... 0 011 010 10 011 010 1 Total: 11 111 111 111 111 11 UDP checksum provides error detection, any changed bits or missing segments Simplified explanation (see RFC 10 71 for more details): Sender UDP adds 16 bit ... Total at the receiver will be 11 111 111 111 111 11 34 UDP Checksum (FYI) 15 16 Client Server 31 16-bit Source Port Number 16 -bit Destination Port Number 16 -bit UDP Length 16 -bit UDP Checksum Time Data...
... dotted-decimal format, 10 .0.0.0 is the network portion of the IP address Example 2: Using the second mask (255.255.0.0): 000 010 10.0 010 0 010 .00 010 111 .10 00 011 0: IP address 11 111 111 .11 111 111 .00000000.00000000: ... (host) on that network Some examples of subnet masks follow Example 1: 11 111 111 .00000000.00000000.00000000 written in dotted decimal is 255.0.0.0 Example 2: 11 111 111 .11 111 111 .00000000.00000000 written ... consider the following examples: Example 1: Using the first mask (255.0.0.0): 000 010 10.0 010 0 010 .00 010 111 .10 00 011 0: IP address 11 111 111 .00000000.00000000.00000000: network mask 000 010 10.00000000.00000000.00000000...
... prepositions See pages 12 7 12 8 for notes about the most common prepositional idioms about above across after against around at before behind below beneath beside (continued) 11 7 Parts of Speech: ... 15 In comparisons, add -er or -est to short modifiers For longer words, use more/the most or less/the least before the modifier 16 Do not use double comparisons 17 Do not use double negatives 18 ... wants to join the committee 11 9 Verb Review If English is your second language, a quick review of verb conjugation and usage rules might be in order Turn to Chapter 11 for an overview of verb forms,...
... v bng: (7- 9) (7 -10 ) (7 -11 ) 13 3 kdq = knkr (7 -12 ) S ca dõy qun mt pha: Dõy qun mt pha gm mt hoc nhiu nhỏnh ng nht ghộp song song ú s ca mt pha l s ca mt nhỏnh song song (hỡnh 7- 6) Hỡnh 7- 6 Dõy ... TP Bi 7 .1 Cho mỏy phỏt in cú p =1, ng kớnh stator D=0,7m, T cm trung bỡnh Btb1 = 0,8 T, chiu di tớnh toỏn stator l = 1, 3m Cho bit tr s B tb3 = 0,325Btb1; Btb5 = 0 ,15 Btb1 Hóy tớnh cỏc s E1, E3, ... = kr1, tc l h s ca súng c bn, bc ca s ú cú th biu th nh sau: Z = 2mqk ú: k = 1, 2, 3, ; m: s pha; q: s rónh ca mt pha di mt cc t Vỡ: 2mq = Z/p nờn (7 -19 ) tr thnh: (7 -19 ) 13 5 Z = Z k p (7- 20)...
... bã täng chëu nẹn) Tỉïc A = A0, tỉì (7 - 4) âỉåüc: N.e - A R n b h Fa’ = ; R a '.(h − a' ) Tỉì (7 - 5) âỉåüc: Fa = (7 - 6) N + α R n b h + R a ' Fa ' ; Ra (7 - 7) Biãút M, N, b, h, Ra, Ra’, Rn, ... håüp lỉûc vng nẹn trng våïi trng tám Fa’) Tỉì h0 N.e’ = Fa Ra (h0- a’); ⇒ Σ (7 - 10 ) N.e' Fa = R a (h − a' ) (7 - 11 ) Nãúu α > α0 chỉïng t Fa’ â cọ l quạ nh, khäng â nãn xem Fa’ l chỉa biãút ... âiãưu kiãûn: Q ≤ k0Rnb.h0 ; (Giäúng cáúu kiãûn chëu ún) (7 - 13 ) V nãúu tha mn âiãưu kiãûn: Q ≤ k1Rkb.h0 - 0,2N k1 = 0,6 Cáúu kiãûn dảng k1 = 0,8 Cáúu kiãûn dảng bn Thç khäng phi toạn theo lỉûc...