... dịch A 2nZn2+ + 2nMg2+ 8nN2O 2nH2 hỗn hợ p B BT:N = 0,0 625 mol nNaNO3 = 2nN2O + nNH 4+ = 0,3 625 mol BT:H nNaHSO4 = 10 nNH 4+ + 10 nN2O + 2nH2 = 2, 225 mol nH 2O = nNaHSO4 4nNH4+ 2nH2 = 0,9375mol ... ta co CTTQ ca E la: O2 ,t C2x + 6y H3x +12 y + O x + y +1N x + 2y (2x + 6y )CO + (1, 5x + 6y + 1) H 2O 3x + 12 y + n CO2 = n H 2O 2x + 6y = x = 2 n E = 0, 0658 mol + Ta co: 14 ,88 y = 0, 7353 ... cng co th tỡm c kt qua - Hng t 3: Tỏch cht + T (1) , (2) ta tớnh c: x = 0 ,13 16 mol ; y = 0, 0484 mol; z = 0 ,11 41 mol Vy + Ta tách C2H5O2N(Gly) C2H3ON + H2O va co: tách C6H12O2N2(Lys) C2H3ON...