... b: Ibr = PFe 10 3. I r1 = 3. U 478 + 3. 14 ,3. 0,1 233 = 0, 839 A 3. 220 4) Sc in ng E1 : E1 = U I.x1 = 220 14 ,3. 0 ,33 7 = 215,2 A k1 = 6.w1 k d 6.80.0,925 = = 11,68 Z2 38 I2 = SVTH: PHAN VN KIấN I2 ... Z2 = 38 rónh 2) ng kớnh ngoi rụto D: D = D = 23, 5 2.0,07 = 23, 36 cm SVTH: PHAN VN KIấN 34 LP: H IN C K3 N MễN HC MY IN GVHD: NGUYN VN H 3) Bc rng rụto t2: t2 = D' 23, 36 = = 1, 931 cm Z2 38 ... rụto r2 : 2.rv 2.0, 933 .10 = 0 ,31 51.10 + = 0,487.10-4 2 0 ,32 9 zp 180.2 = sin = 0 ,32 9 Vi : = sin z2 38 r2 = rtd + 8) H s quy i : 4.m1 ( w1 k d ) ì 3. (80 ì 0,925) = = = 1 730 Z2 38 9) in tr rụto...