Báo cáo toán học: "About division by 1" pptx

... (10)Sylvester treated the Euclidean division by a diﬀerent method, using summations onsubsets of roots (cf. [LP]). We shall for our part interpret now the Euclidean division asproducing a sequence ... )=detSλi+j−i( − )1≤i,j≤.ThenTheorem 1 The k-th remainder in the Euclidean division of σz( ) by 1 isfk(z)=S(k+1)k ( )−1∞i=0ziSk+1+i,(k+1)k−1 ( ) . (6)the electronic ... all related to Euclidean division. As a last example, we illustrate how to write a continued fraction expansion of a series,which one can ﬁnd in the work of Wronski, Chebyschef or Stieltjes.Proposition...

Báo cáo toán học: " Decreased defluorination by using the novel beta cell imaging agent [18F]FE-DTBZ-d4 in pigs examined by PET" docx

... maintained by 2.5% sevofluran. Normoglycemia was confirmed by determining blood glucose content (plasma glucose concentration 4.4 to 7.6 mM). The animal experiments were approved by the local ... constant determined by the ratio between Bmax and Kd. Therefore, BP can be altered without any change in receptor affinity (Kd). By contrast, Bmax can be affected by several factors ... the VMAT2 PET ligand [18F]FE-DTBZ by deuteration to reduce the rate of defluorination. The fluoroethoxy group of [18F]FE-DTBZ can be defluorinated in vivo by an initial enzymatic attack at...

Báo cáo toán học: " decarboxylation catalyzed by phenolic acid decarboxylase from Candida guilliermondii" potx

... were obtained approximately 2- to 5-folds with yields of 40–70% within 2 d by the simple purification procedure as judged by SDS-acrylamide gel electrophoresis (see Additional file 2). Assay ... in a final volume of 1.0 ml. After the reactions were terminated by boiling for 10 min, the products formed were quantified by high-performance liquid chromatography (HPLC) using a packed column ... S (2003) Oxidative stabilization of an alkaliphilic Bacillus α-amylase by replacing single specific methionine residue by site-directed mutagenesis. J Appl Glycosci 50:367–372. Hagihara H,...

Báo cáo toán học: "Crossed products by locally unitary automorphism groups and principal bundles " ppt

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Báo cáo toán học: "On O_{n+1} " potx

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Báo cáo toán học: " A [k, k + 1]-Factor Containing A Given Hamiltonian Cycle" pptx

... +(t−1)(t − 2)≥ (ρ +1)s−ρt +(t−1)ρ (by (5))=(ρ+1)s−ρ>0. (by (4))This contradicts (2).Claim 3. T ∩ W = ∅.Suppose T ⊆ U and n is even. Then for every x ∈ T ,wehaveby(3)n2≤dG(x)≤dH−S(x)+s+2≤ρ+s+1,the ... +32−n2)=(n2−s−52)2+(n2−s−52)(n2+52− 2ρ)+n−5ρ≥ 0. (by n ≥ 6ρ − 1 and Claim 1)This contradicts (2). Therefore Claim 2 is proved.Now putT1:= T ∩ U, T2:= T ∩ W, t1= |T1|,t2:= |T2|. By Claims 2 and 3, we have ... follows from (3) thatn2− ρ − s − 2 ≤−1ifnis even, andn2− ρ − s −32≤−1ifnis odd. (7) By Claim 1 and by the above inequalities, we haveρ ≥ 2. (8)the electronic journal of combinatorics 6...

Báo cáo toán học: "lattice tilings by cubes: whole, notched and extended" potx

... classes of polyhedra tile Rdif translated by an appro-priate lattice. The notched cube (see Figure 1) has already been shown by Stein [St]to tile Rd by a lattice (Conlan [Con] has done this ... notched cube, which is a very explicit function (see (11)). We ﬁnd allthe tilings discovered by Stein, which, by a deeper theorem of Schmerl [Sch], is thecomplete list of possible translational tilings ... of the corners) and show that they admit latticetilings. This has also been been proved by S. Stein by a direct geometricmethod. Finally, we exhibit a new class of simple shapes that admit...

Báo cáo toán học: "Irreducible coverings by cliques and Sperner’s theorem" ppsx

... number of states ofan incompletely speciﬁed Mealy type automaton A by ﬁnding a closed irreducible coveringof the set of states of A by ”maximal compatible sets of states”, which are cliques in thegraph ... from anirreducible covering by cliques of the complementary graphG.2 Main resultWe will evaluate the clique number ω(G)whenG of order n has an irreducible covering by n − k cliques.Theorem ... irreducible coverings by cliques of complete multi-partite graphs, J. of Combinatorial Theory, Series B, 2, 28(1980), 127-141.[9] I. Tomescu, On the number of irreducible coverings by edges of complete...

Báo cáo toán học: "Words restricted by patterns with at most 2 distinct letters" pptx

... alternative, bijective proof of this by generalizing our earlierbijection ρ : [k]n(121) → [k]n(112). Let α ∈ [k]n(vm,l). Recall that αjis a word obtained by deleting all letters 1 through ... Alternatively,multiplying the recursive formula (3) by xn−1/(n − 1)! and summing over n ≥ 1 yieldsddxF112(x; k) = F112(x; k) + (1 + x)ddxF112(x; k − 1).Multiplying this by ykand summing over k ≥ 1, ... f221(n, k), an equivalent resultsince 221 = c(112). This bijective proof is suggested by equation (3) and by the fact thatc(n, n − j) enumerates permutations of n letters with n − j right-to-left...

Báo cáo toán học: "Subsequence containment by involutions" ppt

... ,aj} be the elements of [k] which are mapped by π into [k], with a1<a2< ···<ajif A = ∅.Now assume that j = 0. Because π(ai) ∈ [k] by deﬁnition and π(π(ai)) = ai∈ [k],π(ai) ... on ST.Ofthefµtableaux Qso obtained by letting Qrange over ST, exactly one is the order preserving relabeling of TSTwith the elements of[j]. By the observation above, this choice of ... 5, 6, 7} 8 1 2 5 14{0, 1, 2, 3, 4, 5, 6, 7} 64 1 2 5 14Table 5: Classifying S7 by subsequence containment by involutions.the electronic journal of combinatorics 12 (2005), #R14 9Before proving...

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