các dạng bài tập vật lý 9 chương 1

... αt 1 )= 1+ αt2 1+ αt 1 = 1+ αt2 1 2 1+ αt 1 − 1 2Áp dụng công thức tính gần đúng: (1 + ε)n≈ 1+ nεT2T 1 = 1+ 1 2αt2 1 − 1 2αt 1 Hay:∆TT 1 = 1 2α(t2− t 1 )= 1 2α∆t2.Khi ... năng ở chu kì 1: E 1 = EtB 1 max= mgh 1 ,hayE 1 = 1 2mglα2 1 Cơ năng ở chu kì 2: E2= EtB2max= mgh 1 ,hayE2= 1 2mglα22Độ giảm cơ năng sau 1 chu kỳ: ∆E = 1 2mgl(α2 1 − α22)Th.s ... =A2A 1 =A3A2= ···=AnA(n 1) → A2= qA 1 ,A3= q2A 1 ··· ,An= qn 1 A 1 (vớiq< ;1) Đường đi tổng cộng tới lúc dừng lại:s =2A 1 +2A2+ ···+2An=2A 1 (1 + q + q2+ ···+ qn 1 )=2A 1 SVới:...

... Phương pháp giải các dạng bài tập Vật lý 12 – Phần dòng điện xoay chiều  Trang 2 Người viết: Dương Văn Đổng – Trường THPT Nguyễn Văn Linh, Bình Thuận B - NỘI DUNG CÁC DẠNG BÀI TẬP VỀ DÒNG ... SÁNG KIẾN KINH NGHIỆM Năm học 2 011 – 2 012 I. Đánh giá, xếp loại của HĐKH trường THPT Nguyễn Văn Linh 1. Tên đề tài: PHƯƠNG PHÁP GIẢI CÁC DẠNG BÀI TẬP VẬT LÝ 12 PHẦN DÒNG ĐIỆN XOAY CHIỀU. ... giải các dạng bài tập Vật lý 12 – Phần dòng điện xoay chiều  Trang 3 Người viết: Dương Văn Đổng – Trường THPT Nguyễn Văn Linh, Bình Thuận 9. Từ thông qua 1 vòng dây dẫn là  = 22 .10 cos (10 0t...

... ?A. 16 16 kg B. 17 17 kg C .18 18 kg D. 19 1 9 kg Tóm tắt GiảimU = 234 ,99 u Số hạt nhân nguyên tử 235U trong 1 gam vật chất U là : mMo = 94 ,88 u N = ANAm. = 212 3 10 .5 617 , 210 .02,6.235 1 = ... nhiêu ?A. 13 . B. 14 . C. 27. D. 40. 9. 4 Các nuclôn trong hạt nhân nguyên tử Na23 11 gồmA. 11 prôtôn. B. 11 prôtôn và 12 nơtrôn.C. 12 nơtrôn. D. 12 prôtôn và 11 nơtrôn. 29 Bài 2: người ... MeV…………………………………………………………………………………………………………………………………………………………………………………………………………………… 9. 19 Cho khối lượng các hạt nhân : mAl = 26 ,97 4u ; mα = 4,0 015 u ; mp = 29, 970u ; mn = 1, 0087u và 1u = 93 1, 5 MeV/c2 . Phản ứng : n Al30 15 27 13 +→+Pα sẽ tỏa...

... αt 1 )= 1+ αt2 1+ αt 1 = 1+ αt2 1 2 1+ αt 1 − 1 2Áp dụng công thức tính gần đúng: (1 + ε)n≈ 1+ nεT2T 1 = 1+ 1 2αt2 1 − 1 2αt 1 Hay:∆TT 1 = 1 2α(t2− t 1 )= 1 2α∆t2.Khi ... năng ở chu kì 1: E 1 = EtB 1 max= mgh 1 ,hayE 1 = 1 2mglα2 1 Cơ năng ở chu kì 2: E2= EtB2max= mgh 1 ,hayE2= 1 2mglα22Độ giảm cơ năng sau 1 chu kỳ: ∆E = 1 2mgl(α2 1 − α22)Th.s ... =A2A 1 =A3A2= ···=AnA(n 1) → A2= qA 1 ,A3= q2A 1 ··· ,An= qn 1 A 1 (vớiq< ;1) Đường đi tổng cộng tới lúc dừng lại:s =2A 1 +2A2+ ···+2An=2A 1 (1 + q + q2+ ···+ qn 1 )=2A 1 SVới:...

... lắc sau va chạm. Áp dụng đsauWkA=22 1 Phương Uyên CÁC DẠNG BÀI TẬP VẬT LÝ 12 1 CÁC DẠNG BÀI TẬP VẬT LÝ 12 Chuyên đề 1: Hạt nhân nguyên tử Dạng 1: Tính năng lượng phản ứng A + B → C + ... giác vì dòng điện lớn) Phương Uyên CÁC DẠNG BÀI TẬP VẬT LÝ 12 10 Phương Uyên CÁC DẠNG BÀI TẬP VẬT LÝ 12 3+ Tìm A = 222ωvx+(hay từ cơ năng E = 22 1 kA) + Tìm ω= mk(con lắc lò ... H = 11 1222 1 2coscosϕϕsIUIUPP=+ Nếu điện trở thuần các cuộn dây nhỏ thì 2 1 2 1 NNee=2 1 2 1 NNEE=⇒+ Nếu các cuộn dây có điện trở thuần : 1 exem như nguồn thu 11 11 riue−=...

... Thuận  Phương pháp giải các dạng bài tập Vật lý 12 – Dao động cơ - Sóng cơ, sóng âm  Trang 234. Ta có: A2 = )cos(2 11 2 1 2ϕϕ−−+ AAAA= 5 cm; tanϕ2 = 11 11 coscossinsinϕϕϕϕAAAA−− ... )30cos(20 21 222 1 −++ AAAA = 7 ,9 cm; tanϕ = )30cos(60cos)30sin(60sin020 1 020 1 AAAA++= tan( 41 0).Vậy: x = 7,9cos(5πt + 18 0 41 π) (cm).3. Ta có: A = 0 21 222 1 90 cos2 AAAA ... 2cos (10 πt - 3π) cm. Tính vận tốc trungbình của vật trong 1, 1 giây đầu tiên.Người viết: Dương Văn Đổng – Trường THPT Nguyễn Văn Linh, Bình Thuận  Phương pháp giải các dạng bài tập Vật lý 12 ...

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... vật cân bằng ta có mg.sinα = k.0l∆+ E = 222222 1 2 1 2 1 2 1 AmkAkxmvEEtđω==+=+ Hữu Nghĩa CÁC DẠNG BÀI TẬP VẬT LÝ 12 Website: xomcodon.tk 1 CÁC DẠNG BÀI TẬP VẬT LÝ 12 Chuyên đề 1: ... H = 11 1222 1 2coscosϕϕsIUIUPP=+ Nếu điện trở thuần các cuộn dây nhỏ thì 2 1 2 1 NNee=2 1 2 1 NNEE=⇒+ Nếu các cuộn dây có điện trở thuần : 1 exem như nguồn thu 11 11 riue−= ... Nghĩa CÁC DẠNG BÀI TẬP VẬT LÝ 12 Website: xomcodon.tk 7 -Hai đầu cố định: l = k2λ, k bó , k bụng , (k +1) nút - Một đầu tự do : l = 2)2 1 (λ+k , k bó, (k +1) nút , ( k +1) bụng - Vật...

... thì: 2 1 2 1 NNee=2 1 2 1 NNEE=⇒- Nếu các cuộn dây có điện trở thuần: 1 e xem như nguồn thu: 11 11 riue−= ,2exem như nguồn phát: 2222riue+=. Vậy: 2 1 222 11 12 1 NNriuriuee=+−= ... chu kì 1: 1 2 1 ax 1 1 1 1, :2T mBmg hay mglhEE Eα= = = + Cơ năng chu kì 2: 222 ax 2 1 2 1 , :2T mBmg hay mglEhE Eα= = =- Độ giảm cơ năng sau 1 chu kì: 2 2 1 2 1 ( )2Emglα ... lập : 1 22222=+ωAvAx ⇒ v = 22xA−ω và: A = 222ωvx+- Lực kéo về: 5 CÁC DẠNG BÀI TẬP VẬT LÝ 12 Chuyên đ 1 : Động lực học vật rắn Các công thức cơ bản cần nhớ: 1. Tốc...

... 12 :L nt L 12 12 L L LZ Z Z L L L     + 12 1 2 1 2 12 12 1 2 1 2 1 1 1 1 1 1/ / :LLLL L L L LZZLLL L Z LZ Z Z Z Z L L L L L         + 12 12 12 1 2 1 2 1 1 ... lƠm nh sau: + đ222đW = n W 11 ( 1) 1 22W = W + W 1 2ttAkA n kx xkAn      + đ2 2 2 222đW = n W 1 1 1 1 1 2 2( 1) 2 2( 1) W = W + W2ttkkA mv kA v ... *ăNuăMădaoăđngăngcăphaăviăS 1 , S2 thì:  21 dd = (2k + 1)  Suy ra:   21 21d d k   Vi d 1 = d2 ta có:   21 21 2d d k   Gi x lƠ khong cách t M đn AB: d 1 = d2 = 22 12 2SSx=...

... f 1 ; Mạch L2 và C có tần số f2): 2 2 2 2 2 2 1 2 1 2 1 22 2 2 1 2 1 1 1 nt Lnt ntntL T T Tf f f           2 2 2 1 2 // 1 22 2 2 2 2 2// 1 2 // 1 2 1 1 1 1 1 1 ... THI ĐẠI HỌC MÔN VẬT LÝ Email: Jackie9x.spb@gmail.com  1 HỆ THỐNG LÝ THUYẾT VÀ CÁC DẠNG BÀI TẬP VẬT LÝ LTĐH * Tóm tắt lý thuyết * Công thức tính nhanh * Các dạng bài tập và phương ... quanh 1 trục cố định thì Wđ = Wđ2 - W 1 = 1 2I22 - 1 2I2 1 = A 3: Công thức xác định khối tâm của hệ Trong hệ toạ độ đề các Oxyz 1 1 2 2 1 2 1 1 2 2 1 2 1 1 2 2 1 2 ...

... thời gian các dạng bài tập Vật lý là điều cần thiết đối với giáo viên Vật lý để hướng dẫn cho học sinh. Hơn nữa, trong phần điện học, các dạng bài tập nâng cao thường “khó” hơn so với các phần ... giải các bài tập nâng cao phần điện học là thiết thực và hiệu quả. Kết quả cụ thể, năm học này (10 11- 2 012 ), tôi đã tham gia dạy bồi dưỡng các đội tuyển và đã cho các em giải nhiều các dạng bài ... I 1 = 2,8A; I2 = 2,9A; I3 = 1, 2A; I4 = 1, 1A; I5 = 0,1A; I = 4A.b/ PP đặt hệ phương trình có ẩn số là dòng điện:UMN = U 1 + U2 = I 1 .R 1 + I2.R2 = I 1 + I2 = 5,7. (1) ...

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... dng:348 10 0AK min 19 3 min 0AKhc hc 6,625 .10 .3 .10 eU =  0,6625 .10  eU 1, 6 .10 .18 ,75 .10 m. Bài tp minh ha Bài 1 . Mt èn phát ra bc x có tn s f = 10 14 Hz. Bc x này thuc ... D2,5 2,8 = 1, 12 *aa .- Khong cách t vân ti th 3 n vân sáng bc 1: 't3 s1   Dx = x - x = 2 + - = 1, 5 = 1, 5 .1, 12 = 1, 68mm.2aaa (kt hp *). Bài 4.Thí nghim ... 1, 2 mm;  =Dai= 0,48 .10 -6 m; x8 - x3 = 8i – 3i = 5i = 6 mm. Bài 2. Ta có: i = 51 L = 1, 5 mm;  =Dai= 0,5 .10 -6 m; x6 = 6i = 9 mm. Bài 3. Ta có: i =aD= 2 mm; L = (9 – 1) i...

... lớn hơn vật nằm trong giới hạn nhìn rỏ của mắt. LUYỆN THI ĐẠI HỌC MÔN VẬT LÝ Email: Duclongtn95@gmail.com 1 HỆ THỐNG LÝ THUYẾT VÀ CÁC DẠNG BÀI TẬP VẬT LÝ 11 * Tóm tắt lý thuyết ... là fara (F) 1 mF = 10 -3 F. 1 F = 10 -6 F. MNMNMNvvmUqA222 1 .2 1 .  LUYỆN THI ĐẠI HỌC MÔN VẬT LÝ Email: Duclongtn95@gmail.com 6 1 nF = 10 -9 F. 1 pF = 10 -12 F. - Điện ... dSdSCo 4 .10 .9 . 9  Với )F( 10 .85,8.4 .10 .9 1 12 9 mo ; )N.m( 10 .9 4 1 22 9 Cko Trong đó S là diện tích của mỗi bản (phần đối diện); d là khoảng cách giữa...