... lắc sau va chạm. Áp dụng đsauWkA=22 1 Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 1 CÁCDẠNGBÀITẬPVẬTLÝ 12 Chuyên đề 1: Hạt nhân nguyên tử Dạng 1: Tính năng lượng phản ứng A + B → C + ... giác vì dòng điện lớn)Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 10 Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 3+ Tìm A = 222ωvx+(hay từ cơ năng E = 22 1 kA) + Tìm ω= mk(con lắc lò ... H = 11 1222 1 2coscosϕϕsIUIUPP=+ Nếu điện trở thuần các cuộn dây nhỏ thì 2 1 2 1 NNee=2 1 2 1 NNEE=⇒+ Nếu các cuộn dây có điện trở thuần : 1 exem như nguồn thu 11 11 riue−=...
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LUYỆN THI ĐẠI HỌC MÔN VẬTLÝ Email: Jackie9x.spb@gmail.com 1 HỆ THỐNG LÝ THUYẾT VÀ CÁCDẠNGBÀITẬPVẬTLÝ10 * Tóm tắt lý thuyết * Công thức tính nhanh * Cácdạngbàitập và phƣơng pháp ... 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... lực. B. CÁCDẠNGBÀITẬP1. Cân bằng của vật chịu tác dụng của các lực không song song * Công thức Điều kiện cân bằng của vật chịu tác dụng của các lực không song song: 1 F+2F+...
... 2002cos23= - 10 0 2 (V). 5. Ta có: u 1 = 220 = 2202cos (10 0 πt 1 + 6) cos (10 0 πt 1 + 6) = 22 = cos(4) . Vì u đang tăng nên ta nhận nghiệm (-) 10 0 πt 1 + 6 = - 4 t 1 = ... 2) (V). 9. Ta có: e = - N’= 15 0 .10 0 22 .10 sin (10 0 t - 4) = 300cos (10 0 t - 34) (V). 2. Tìm một số đại lƣợng trên các loại đoạn mạch xoay chiều * Các công thức: Cảm kháng, dung ... SÁNG KIẾN KINH NGHIỆM Năm học 2 011 – 2 012 I. Đánh giá, xếp loại của HĐKH trường THPT Nguyễn Văn Linh 1. Tên đề tài: PHƯƠNG PHÁP GIẢI CÁCDẠNGBÀITẬPVẬTLÝ 12 PHẦN DÒNG ĐIỆN XOAY CHIỀU....
... 3,55 .10 10 hạt. B). 3,40 .10 10 hạt. C). 3,75 .10 10 hạt. D).3,70 .10 10 hạt.Giải- Số hạt nhân ngun tử có trong 1 gam 226Ra là : N0 = 212 3 10 . 6646, 210 . 022,6.226 1 .==ANAm hạt .- Suy ... theo đơn vị Jun làA. 6,7 .10 -13 J B. 6,7 .10 -15 J C. 6,7 .10 -17 J D. 6,7 .10 -19 JTóm tắt: Giải;000 ,12 umC= C12 3 He;0 015 ,4 um=α Năng lượng phá vở một hạt C12 thành 3 hạt He 9Suy ... Al27 13 là bao nhiêu ?A. 13 . B. 14 . C. 27. D. 40. 9.4 Các nuclôn trong hạt nhân nguyên tử Na23 11 gồmA. 11 prôtôn. B. 11 prôtôn và 12 nơtrôn.C. 12 nơtrôn. D. 12 prôtôn và 11 nơtrôn. 29Bài...
... 40 Bài 204 Vật có trong lợng P = 10 0 N đợc treo bởi hai sợi dây OA và OB nh hình vẽ.Khi vật cân thì AOB = 12 00. Tính lực căng của 2 dây OA và OB. Hình 41 Bài 205 18 BT vậtlýlớp10 Bài 10 . ... trọng lực của hệ khi vật A di chuyển trên mặt phẳng nghiêng đợc một quÃng l = 2m.Bỏ qua ma sát. Lấy g = 10 m/s2. Bài 327. 31 BT vậtlýlớp10 Bài 15 2. Một vật khối lợng 1kg đợc kéo trên sàn ... ợc200m. Tính: 1. Lực thắng.2. Thời gian đầu máy đi đợc quÃng đờng 200m trên.Lấy g = 10 m/s2. 13 BT vậtlýlớp10 áp dụng: M = 4m, v0 = 2m/s, à = 0,2, l = 1m, g = 10 m/s2. Bài 292Từ một...
... g = 10 m/s2 .a. Tính vận tốc cuối cùng của vật và nêm khi H = 1m và H = 1, 2m .b. Tính v0 min để vật trượt qua nêm khi H = 1, 2m. Bài 3 41 27450 BµI TËP VËT LÍ LíP 10 Hå §¨ng S¬n Bài 10 0 Một ... Lấy g= 10 m/s2. Hỏi 1. Sau bao lâu vật đến chân dốc ? 2. Vận tốc của vật ở chân dốc. Bài 15 8 Giải lại bài toán trên khi hệ số ma sát giữa vật và mặt phẳng nghiêng là k = 0,2. Bài 15 9 Một vật trượt ... do Lấy g = 10 m/s2 Bài 15 5 Một lực kế, có treo vật khi đứng yên chỉ 20n. Tìm số chỉ của lực kế khi: 1. Kéo lực kế lên nhanh dần với gia tốc 1m/s29 O 5 10 15 20 v(m/s)t(s)3020 10 450 BµI...
... khi vật cân bằng ta có mg.sinα = k.0l∆+ E = 222222 1 2 1 2 1 2 1 AmkAkxmvEEtđω==+=+Hữu Nghĩa CÁCDẠNGBÀITẬPVẬTLÝ 12 Website: xomcodon.tk 1 CÁCDẠNGBÀITẬPVẬTLÝ 12 Chuyên đề 1: ... H = 11 1222 1 2coscosϕϕsIUIUPP=+ Nếu điện trở thuần các cuộn dây nhỏ thì 2 1 2 1 NNee=2 1 2 1 NNEE=⇒+ Nếu các cuộn dây có điện trở thuần : 1 exem như nguồn thu 11 11 riue−= ... Nghĩa CÁCDẠNGBÀITẬPVẬTLÝ 12 Website: xomcodon.tk 7 -Hai đầu cố định: l = k2λ, k bó , k bụng , (k +1) nút - Một đầu tự do : l = 2)2 1 (λ+k , k bó, (k +1) nút , ( k +1) bụng - Vật...
... thì: 2 1 2 1 NNee=2 1 2 1 NNEE=⇒- Nếu các cuộn dây có điện trở thuần: 1 e xem như nguồn thu: 11 11 riue−= ,2exem như nguồn phát: 2222riue+=. Vậy: 2 1 222 11 12 1 NNriuriuee=+−= ... chu kì 1: 1 2 1 ax 1 1 1 1, :2T mBmg hay mglhEE Eα= = = + Cơ năng chu kì 2: 222 ax 2 1 2 1 , :2T mBmg hay mglEhE Eα= = =- Độ giảm cơ năng sau 1 chu kì: 2 2 1 2 1 ( )2Emglα ... lập : 1 22222=+ωAvAx ⇒ v = 22xA−ω và: A = 222ωvx+- Lực kéo về: 5 CÁCDẠNGBÀITẬPVẬTLÝ 12 Chuyên đ 1 : Động lực học vật rắn Các công thức cơ bản cần nhớ: 1. Tốc...
... 12 :L nt L 12 12 L L LZ Z Z L L L + 12 1 2 1 2 12 12 1 2 1 2 11111 1/ / :LLLL L L L LZZLLL L Z LZ Z Z Z Z L L L L L + 12 12 12 1 2 1 2 11 ... lƠm nh sau: + đ222đW = n W 11 ( 1) 1 22W = W + W 1 2ttAkA n kx xkAn + đ2 2 2 222đW = n W 11 1 1 1 2 2( 1) 2 2( 1) W = W + W2ttkkA mv kA v ... vi ngun 1: 12 1 2ddk . Suy ra: 1 122d d k đim M dao đng ngc pha vi ngun 1: 12 1 (2 1) ddk . Suy ra: 1 12(2 1) d d k...