dap an chi tiet chuyen vinh lan 3 2013

... có: 23 23 32 23 3 23 3 23 8)8(8lim)8lim(nnnnnnnnnnnn++++−+=−+0,52 3 2 3 2222 3 23 32 23 2)81()81(8lim8)8(8limnnnnnnnnnnnnn++++=++++=0,5 3 81)81()81(8lim 3 3 3 =++++=nn0,5IIIPhương ... +++=+≥−+⇔≥−+0,25 3 12427444. 3 . 3 . 3 4444 3 ==≥aaaa0,25Dấu “=” xảy ra khi và chi khi a = 412, b = 21240,25SỞ GIÁO DỤC VÀ ĐÀO TẠO VĨNH PHÚC ĐỀ THI KHẢO SÁTCHUYÊN ĐỀ LỚP 11 LẦN 3 TRƯỜNG ... F,I, N, J với nhau ta được thi t diện là lục giác MEFINJ . 0,5Câu VTa có: 4)()(2)(2ababbabbab ≤−⇔−≥−+, dấu “=” xảy ra khi a = 2b0,25Từ 33 44 33 34)(1 3 124)(1aaaaaabaababaaba...

... c = 1, x = 3 - 3, y = 1, z = 1 Ta có : abc = 3 + 3 3, xyz = 3- 3 3, a+ x = 6, b + y = 2, c + z = 2 Từ đó : 3 3 3 3 3 3 3+ 3 3- 3 6.2.2 2 3    (đpcm). 0,50 0,50 Câu 5a. (2,0) ... + 3y2z2 -1 8x = 6. Câu 4. (3, 0 điểm) a) Cho x, y, z, a, b, c là các số dương. Chứng minh rằng: 3 3 3 abc + xyz (a + x)(b + y)(c + z) . b) Từ đó suy ra : 3 3 3 3 3 3 3 3 3 2 3  ... giáo dục - đào tạo hà nam kỳ thi tuyển sinh vào lớp 10 thpt chuyên Năm học 2009 - 2 010 Môn thi : toán (Đề chung) đề chính thức Thời gian làm bài: 120 phút (Không kể thời gian giao đề) Bài...

... x=-1cm lần 1 theo chi u âm tương ứng góc quét 04 30 180 30 240 3 πα= + + = = Suy ra thời gian : 2( ) 3 t sαω∆ = = Vậy thời gian cần tìm: 2 6 038 (20 13 1).1 ( ) 3 3t s= − + = ... 13 (2)112 13 N U UN UU U+= =− Lần 3: 1 11 12 2 212 3 (3) 25 3 U UN UN U U−= =+ Lấy (2) chia (1) vế theo vế 11125 13 30012NNN+== → = Lấy (1) chia (3) ... Laiman, Banlme và Pasen lần lượt là: 21 32 43 ; ;λ λ λ Áp dụng công thức tính các mức năng lượng : m nmnhcE Eλ= − ta có: 5 2 1 121 11 1 3 2 2 1 2 3 32 2 2 3 4 3 343...

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... TRƯỜNG ĐHSP HÀ NỘI ĐỀ THI THỬ ĐẠI HỌC LẦN THỨ V NĂM 2013 TRƯỜNG THPT CHUYÊNCâu 1: Đốt cháy hoàn toàn m gam một ancol đa chức X tạo ra ... và Y đều có 2e ở lớp ngoài cùng. B. Bán kính nguyên tử và bán kính ion của Y đều lớn hơn X. C. Chúng đều có oxit cao nhất và hợp chất khí với hiđro. D. Chúng đều là kim loại mạnh và đều có ... A. Tất cả các muối cacbonat đều tan trong nước. B. Tất cả các muối cacbonat đều bị nhiệt phân tạo ra oxit kim loại và cacbon đioxit. C. Tất cả các muối cacbonat đều bị nhiệt phân, trừ muối...

... X l hexapeptit, Ala-Gly-Ala-Val-Gly-Val và Y là tetrapeptit Gly-Ala-Gly-Glu. Thủyphân hoàn toàn m gam hỗn hợp gồm X và Y thu được 4 amino axit, trong đó có 30 gam glyxin và28,48 gam alanin. ... sau đây? A. Na, NaCl, CuO B. Na, CuO, HCl C. NaOH, Na, CaCO3D. NaOH, Cu, NaClCâu 17: Tên thay thế (theo IUPAC) c a (CH3)3C-CH2-CH(CH3)2 là A. 2,2,4-trimetylpentan B. 2,2,4,4-tetrametylbutanC. ... biểu sau: (a) Glucozơ có khả năng tham gia phản ứng tráng bạc(b) Sự chuyển h a tinh bột trong cơ thể người có sinh ra mantozơ(c) Mantorazơ có khả năng tham gia phản ứng tráng bạc(d) Saccarozơ...

... đồng hóa học và ứng dụng bring about changeTHPT Quỳnh Lưu 1 Nghệ An Đề thi thử số 1 (Đề thi gồm có 6 trang)ĐỀ THI THỬ THPT QUỐC GIA LẦN INĂM HỌC 2 014 -2 015 Môn: HÓA HỌCThời gian làm bài: 90 ... thêm.bring about change Cộng đồng hóa học và ứng dụngTHPT Quỳnh Lưu 1 Nghệ An Đề thi thử số 1 (Đề thi gồm có 6 trang)ĐỀ THI THỬ THPT QUỐC GIA LẦN INĂM HỌC 2 014 -2 015 Môn: HÓA HỌCThời gian làm bài: ... HÓA HỌC VÀ ỨNG DỤNGhttp://www.bookgol.com——————— * ———————GIẢI CHI TIẾT ĐỀ THI THỬ ĐHQUỲNH LƯU 1 NGHỆ AN LẦN 1 2 015 Copyrightc 2 015 Tinpee PTTMTinpee PTNgày 15 tháng 2 năm 2 015 Cộng...

... thêm.Trang 4/4- Mã đề thi 213 http://www.bookgol.comCHUYÊN ĐHSP HÀ NỘI Đề thi thử số: 1 (Đề thi gồm có 4 trang)ĐỀ THI THỬ CHUẨN BỊ CHO KÌ THI THPTQUỐC GIA NĂM 2 015 Môn: HÓA HỌCThời gian làm ... CỘNG ĐỒNG HÓA HỌC VÀ ỨNG DỤNGhttp://www.bookgol.com——————— * ———————GIẢI CHI TIẾT ĐỀ THI THỬ ĐHCHUYÊN ĐH SƯ PHẠM HÀ NỘI LẦN 1 2 015 Tổng hợp : Võ Văn Thi nSoạn LATEX : Tinpee ... phát đề) http://www.bookgol.comMã đề thi 213 ĐÁP ÁN RÚT GỌNPhương án A B C DCâu 1. ACâu 2. CCâu 3. DCâu 4. DCâu 5. DCâu 6. DCâu 7. ACâu 8. BCâu 9. BCâu 10 . CCâu 11 . DCâu 12 . DCâu 13 ....

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... Trang 1/18 - Mã đề thi 35 9 TRƯỜNG ĐẠI HỌC VINH TRƯỜNG THPT CHUYÊN LỜI GIẢI CHI TIEEYS ĐỀ THI KSCL LỚP 12 – LẦN I, NĂM 2014 Môn: HÓA HỌC  KHỐI A, B (Thời gian làm bài: ... 2Al(OH) 3  + 3CO2 (3) CO2 + NaAlO2 + H2O  Al(OH) 3  + NaHCO 3 (4) Al 3+ + 3NH 3 + 3H2O  Al(OH) 3  + 3NH4 (5) H2S + Br2  S + 2HBr (6) Na2S2O 3 + H2SO4 ... A. 3, 36 lít. B. 2,24 lít. C. 1,12 lít. D. 4,48 lít. Giải XM = 35 ,2 gam/mol; YM = 13, 8.2 = 27,6 gam/mol. 2 3 OOn12 84n 3 2,,  O2 (M = 32 )O 3 (M = 48) 35 ,2 (35 ,2...