... E1is the intersection of {E1, E2,. . .,Ek+1} and the points of one of the e-graphs, and point Ek+1is the intersection of {E1, E2, . . . , Ek+1} and the points of the other of the e-graphs.Theorem ... K1 and K2are identical. This can happen onlyifn−22is even (since if K1 and K2are identical, then the number of edges in K1 and K2is the same, thus the sum of the number of edges in ... the points on the other arc of the e-graph in clockwisedirection, so {e1, e2} = {X1Y1, XmYm}. (Note that the number of points on the two arcs of the e-graph is the same since they...