... f(x)=(X(1)^0.6)+(X(2)^0.6)+(X(3)^0 .4) +2*X (4) +5*X(5 ) -4 *X(3 )- X(6) Feasible conditions: (Leave blank for none) 1. X(1)=(X(2 )-3 *X (4) )/3 2. X(3)=2*(X(2)+X(5)) 3. X(6) =4* X (4) 4. X(2 )-3 *X(1 )-3 *X (4) ==0 5. X(3 )-2 *X(2 )-2 *X(5)==0 ... s*,f=0.000000,fm=0.000001,iter=1 048 ,ifun=16 34, t1=0 *,f*,f =4. 3000 54, fm =4. 300150,iter=23 54, ifun =-3 07 14, t1=0 t*, f= 0.000000,iter2=5213 ifun2 =-2 6305,t2=0 fopt=0.000000 0.198 741 ,0.550658,1.7 847 51,1.670850, seed [4] =*, ... flag=1; return(1); } File vào v1.in 1 4 0 4 0.000001 0.000001 10000 2000 0 2000 0 0 1 0 0 0 0 0 1 2 3 0 3. 141 7 0 3. 141 7 0 3. 141 7 0 3. 141 7 123 2 34 345 45 6 567 40 Chương III BÀI TOÁN QUY...