... = π34R = 14,3.324.4 = 10, 191 cm → x2 = R – x∗2 = 24 – 10, 191 = 13,8 09 cm → y2 = c + y∗2 = 20 + 10, 191 = 30, 191 cm O2 ( 13,8 09; 30, 191 ); F2 = π.R2/ 4 = 452,16cm2; ... )3(yx33J = (94 9 – 498 7). 0,405 = - 1 635, 39 cm4 Hình1.3b )3(XYJ = )3(yx33J + a3b3F3 = - 1 635, 39 + (21,27).(12,204).78,5 → )3(XYJ = - 1 635, 39 + 20 376 ,95 7 = 18 741,567 ... JU = 94 9 cm4 b = 160 mm Jx = 498 7 cm4 y0 = 8,31 cm tg α = 0,405 d = 20 mm Jy = 1613 cm4 Hình1.2 3010 y0 28,31 47,8513,8 09 30, 19 10, 191 x018,31...