... Biology, 3( 12) , 22 29 -22 38 doi: e 422 10.1371/journal.pbio.0030 422 Moynihan, M (1971) Successes and failures of tropical mammals and birds American Naturalist, 105(944), 371-& doi: 10.1086 /28 2731 Nelson, ... 019-057 2. 1 Introduction………………………………….…………………… .25 2.2MaterialsandMethods ………….………………… ……… 22 2. 3 Results………………………….………………………………… .29 2. 3 Discussions…………………………………………………….….38 2. 4 References ... permitted and/ or prohibited species 2.2MaterialsandMethods2. 2.1 Obtaining the international list of ornamental fish The species list of Axelrod (20 06) and Hensen (20 10) were scanned and converted...
... 1.1 72 GeV W= 1 .23 2 GeV W = 1 .29 2 GeV 20 40 60 80 20 40 60 80 100 120 140 160 20 40 60 80 ejfdeg] Figure The RLT response at W = 11 72, 123 2and 129 2 GeV 123 2 MeV is a preliminary datum from the 20 01 ... Suppl 94, 26 9 (20 01) [hep-lat/0011 025 ] 22 J Speth, O Krehl, S Krewald, and C Hanhart, Nucl Phys A 680, 328 (20 00) 23 S Capstick and P R Page, Phys Rev D 60, 111501 (1999) 24 T Barnes and F E Close, ... Phys Rev D 22 , 28 38 (1980) M Oettel, M Pichowsky, and L von Smekal, Eur Phys J A 8, 25 1 (20 00); J C Bloch, C D Roberts, and S M Schmidt, Phys Rev C , 06 520 7 (20 00); M Oettel, R Alkofer, and L von...
... Needed An Introduction to the Linear Regulator 2. 1 2.22. 3 2. 3.1 2. 3 .2 2.3.3 Basic Linear Regulator Operation 11 General Linear Regulator Considerations 12 Linear Power Supply Design Examples 14 Elementary ... Supplies 20 5 Common Error Amplifier Compensation Techniques 20 6 Single-pole Compensation 20 7 Single-pole Compensation with In-band Gain Limiting 21 1 Pole-zero Compensation 21 2 2- Pole 2- Zero Compensation ... Supplies 23 2 D .2 Selecting the Core Material and Style 23 6 vii viii Contents Appendix E Noise Control and Electromagnetic Interference E.1 E .2 E.3 E.4 The Nature and Sources of Electrical Noise 24 1...
... = 2) is given by u(x, t) = 4( 2 − 2 )[( 2 − 2 ) + 2 cosh (2 22 ) + 2 cosh (2 1 ξ1 )] 2 1 , (3.39) [( 2 − κ1 ) cosh(κ1 ξ1 + 22 ) + ( 2 + κ1 ) cosh( 22 − κ1 ξ1 ) ]2 where ξi = x − 4 2 t ... = 6w2 + z w = 2w3 + zw + a w = w w2 d − + (aw2 + b) + cw3 + w z z w w = 3w3 w2 b2 + + 4zw2 + 2( z − a)w − 2w 2w w = w 2( w = (2. 16) w (w − 1 )2 w dw(w + 1) b + )− + (aw + ) + c + 2w w − z z2 w ... equation for (2. 4a), v1,x = −ikv1 + qv2 (2. 5a) v2,x = ikv2 + rv1 (2. 5b) where q, r are functions of x, t and for (2. 4b) we consider v1,t = Av1 + Bv2 (2. 6a) v2,t = Cv1 + Dv2 , (2. 6b) where A,...
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