Ngày tải lên :
16/03/2014, 19:20
... u2 ) and (v1 , v2 ) are both long Since (u1 , u2 ) and (v1 , v2 ) must both contain c, either u1 ends in c and v1 starts in c, or else v2 ends in c and u2 starts in c Case u1 ends in c and v1 ... must have |uv|a ≤ and |uv|b ≤ Case |uv|c ≥ Since |u|c ≤ and |v|c ≤ 2, we must have |u|c ≥ and |v|c ≥ Also, ψ(uv) ∈ [−2, 2] × [−2, 2] implies that |uv|a ≥ and |uv|b ≥ Since u and v are short, it ... vm−1,2 ) Lemma If u and v are short strings and ψ(uv) ∈ [−2, 2] × [−2, 2], then |uv|d ≤ for each d ∈ {a, b, c} Proof Since u and v are short, we have |u|a ≤ 4, |u|b ≤ 4, |u|c ≤ and |v|a ≤ 4, |v|b...