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proof of result 1

Clause of result

Clause of result

Tiếng anh

... as D patient enough D a so interesting D this many of D few news D to - that D too much D so D few D so interesting that D so young D a lot of D dirty enough for D very D too kind D can’t travel ... cat was _to wait for the mouse to come out A patiently enough B so patient C enough patient 31 She told us story that we all forgot about the time A such an interesting B such interesting ... so an interesting 32 I have never seen people in one place A so much B so many C so much of 33 We have heard about you A so many news B so much news C a lot news 34 They were busy...
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A study of linguistic features of result copular verbs in english and vietnamese

A study of linguistic features of result copular verbs in english and vietnamese

Khoa học xã hội

... 4.3 .1. 9 RCVs talking about a change of politics 4.3 .1. 10 RCVs indicating a change of religion 4.3 .1. 11 RCVs indicating a change of occupation 4.3 .1. 12 RCVs describing changes of quality 4.3 .1. 13 ... p .11 2] 11 12 2.2.2.4 Rules of Realization CHAPTER 2.3.3 Result Copular Verbs METHODS AND PROCEDURES 2.3.3 .1 Result Copular Verbs in English 3 .1 OVERVIEW In their work, Downing and Locke [7, p .12 4] ... change of religion 4.3 .1. 1 RCVs denoting the process of changing 4.3 .1. 8 RCVs indicating a change of occupation 4.3 .1. 2 RCVs denoting the result of changing 4.3 .1. 9 RCVs describing changes of quality,...
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Đề tài

Đề tài " A stable trace formula III. Proof of the main theorems" pptx

Thạc sĩ - Cao học

... established a key reduction in the proof of one of the global theorems In this paper, we shall complete the proof of the theorems We shall combine the global reduction of [II] with the expansions that ... With the proof of Local Theorem in hand, we will see that the expansions of Sections 2–5 reduce immediately to two pairs of simple identities The first pair leads directly to a proof of Global ... the proof of the global theorems We have fixed the integers dder and rder in (1. 1) In this section, we shall apply the induction hypotheses (1. 2)– (1. 5) to the terms in the main expansions of [I,...
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Forest-Backed Bonds Proof of Concept Study: FINAL DRAFT - CIRCULATED TO STEERING GROUP ppt

Forest-Backed Bonds Proof of Concept Study: FINAL DRAFT - CIRCULATED TO STEERING GROUP ppt

Ngân hàng - Tín dụng

... ($/tonne) Roundwood ($/m3) Sawnwood ($/m3) Wood Pulp ($/tonne) 1, 400 1, 200 1, 000 800 600 400 200 19 61 1966 19 71 1976 19 81 1986 19 91 1996 20 01 source data: FAOSTAT | © FAO Statistics Division 2007 | ... 6% 1% 0% 39,2 71 3% 4% 11 0,557 5% ASIA AND PACIFIC 97,377 57% 5% 15 % 12 % 0% 70,979 12 % 7% 206,705 9% LATAM AND CARRIBEAN 18 4,727 17 % 2% 4% 1% 1% 3 51, 249 2% 1% 5 41, 580 2% Total Protection Area 14 % ... Reserved 10 0 77 93.2 37.8 45 70.9 99.4 76 .1 98 53.2 99 .1 20.5 10 0 Community/Ind 13 0.3 5.9 0 0.6 1. 2 16 .5 31. 3 0.9 0 Individual/Firm 0 0 55 9.3 33 0 80 5.3 46 00 97 10 6.5 56.3 19 .8 7.4 15 10 .2 79.5...
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Đề tài

Đề tài " Proof of the Lov´asz conjecture " docx

Thạc sĩ - Cao học

... in [15 ] 9 81 ´ PROOF OF THE LOVASZ CONJECTURE H ∗ (Hom (C2r +1 , Kn )) D2 2n − d1 d1 d1 d1 D1 n−2 d1 d1 d1 d1 n−3 D0 d2 d1 q p d1 d1 d1 2r − 2r − 2r ∗,∗ p,q Figure 4 .1: The E1 -tableau, for E1 ⇒ ... of V (C2r +1 ) The sign of this is ( 1) r ; hence γ([σV (C2r +1 ),2r +1 ]) = ( 1) r [σV (C2r +1 ),2r +1 ] 2r 1, n−2 Lemma 4 .13 E1 = rχ0 + r 1 + χn+r +1 , as a Z2 -module Proof 1, 1 , , τ2r +1, 1 can be ... Z2 Z2 Z2 Table 4 .1 2r 1, 2 2r,2 → E1 is Z[d1 ( 1, r )], and 2d1 ( 1, r ) = d1 (2 1, r ) = If 2r + ≥ 9, d : E1 2r,2 2r ,1 we can compute E1 and E1 completely, since H i (Hom+ (C2r +1 , Kn )) vanish...
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Đề tài

Đề tài " A proof of the Kepler conjecture " pdf

Thạc sĩ - Cao học

... gives a proof of Claim 1. 11 Chapter proves Claim 1. 16 Chapters through give a proof of Claim 1. 13 Chapters through 11 give a proof of Claim 1. 12 Chapters 12 through 14 give a proof of Claim 1. 14 Claim ... consequence of Claims 1. 11 1. 16 Its proof appears in Theorem 5 .11 1. 4 Proofs of the central claims The previous section showed that the main results in the introduction (Theorems 1. 1, 1. 7, and 1. 9) ... hypotheses of Claim 1. 16 are satisfied The conclusion of Claim 1. 16 is the conclusion of Theorem 1. 9 Lemma 1. 20 Assume Claims 1. 11 1. 16 (Theorem 1. 1) holds Then the Kepler conjecture Proof As pointed...
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Đề tài

Đề tài " A proof of Kirillov’s conjecture " potx

Thạc sĩ - Cao học

... is G invariant Remark 10 .2 As a corollary to Theorem 10 .1 we obtain another proof of Conjecture 1. 1 The proof follows word for word the proof in [Ber, 5.4], and is omitted 10 .2 Scalar product in ... = Without loss of generality we ˜ can assume that a1 ,1 = Then ˜ λA = (r1 − 1) + (r2 + − 2t2 ) − (r1 + − 2t1 ) − (r2 − 1) = 2(t1 − t2 ) ≤ a ˆ Let A2 ,1 = (ˆi,j ) Then by Lemma 6 .11 we have ai,j ... lemmas which are needed for the proof of our “Key Proposition” above We also sketch the proof of Theorem 1. 4 In Section we A PROOF OF KIRILLOV’S CONJECTURE 211 recall some facts about distributions...
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báo cáo hóa học:

báo cáo hóa học: "Design of a complex virtual reality simulation to train finger motion for persons with hemiparesis: a proof of concept study" docx

Điện - Điện tử

... Pinky Day 10 Day 60 Angle (deg) Middle 40 20 -20 0.4 0.8 1. 2 1. 5 1. 9 2.3 0.4 0.7 1. 1 1. 4 1. 7 2 .1 Time (sec) Figure Independent Finger Flexion Independent Finger Flexion Left Panel: Depiction of independent ... promising results from Actual 12 0 Index 60 -60 -12 0 -12 0 12 0 Ring 60 -60 -12 0 -12 0 200 400 Fractionation (deg ) Daily Average Fractionation (deg ) 10 0 http://www.jneuroengrehab.com/content/6 /1/ 28 ... # H133E050 011 ) References Authors' contributions SVA participated in the robotic/VR system design, study Target Actual Middle Fractionation (deg) 12 0 Index 60 -60 -12 0 -12 0 12 0 Ring 60 -60 -12 0...
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Báo cáo hóa học:

Báo cáo hóa học: " Pilot proof of concept clinical trials of Stochastic Targeted (STAR) glycemic control" docx

Hóa học - Dầu khí

... interests Received: 18 May 2 011 Accepted: 19 September 2 011 Published: 19 September 2 011 Evans et al Annals of Intensive Care 2 011 , 1: 38 http://www.annalsofintensivecare.com/content /1/ 1/38 References ... 35 (10 ) :17 38 -17 48 doi :10 .11 86/ 211 0-5820 -1- 38 Cite this article as: Evans et al.: Pilot proof of concept clinical trials of Stochastic Targeted (STAR) glycemic control Annals of Intensive Care 2 011 ... patients Comput Methods Programs Biomed 2 011 Evans et al Annals of Intensive Care 2 011 , 1: 38 http://www.annalsofintensivecare.com/content /1/ 1/38 Page 12 of 12 44 Hann CE, Chase JG, Lin J, Lotz T,...
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Báo cáo hóa học:

Báo cáo hóa học: " Research Article Proof of One Optimal Inequality for " doc

Hóa học - Dầu khí

... for a correction of one part of the proof, and for his improving of the organization of the paper This work was supported by Vega no 1/ 015 7/08 and Kega no 3/7 414 /09 Journal of Inequalities and ... to 1 19 and related references there in The aim of this article is to prove the following Theorem 2 .1 Main Result Theorem 2 .1 Let α ∈ 0, 1/ 2 ∪ 1/ 2, , a / b, a > 0, b > Let p α be a solution of ... 0g or, in virtue of the definition of p 2p p − 3α α − α 2p
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PHRASES AND CLAUSES OF RESULT (CỤM TỪ VÀ MỆNH ĐỀ CHỈ KẾT QUẢ) docx

PHRASES AND CLAUSES OF RESULT (CỤM TỪ VÀ MỆNH ĐỀ CHỈ KẾT QUẢ) docx

Kỹ năng nói tiếng Anh

... nhiều E.g The Smiths had so many children that they formed their own baseball team I had so few job offers that it wasn’t difficult to select one There are so many people in the room that I feel tired ... day that we decided to stay indoors He has such exceptional abilities that everyone is jealous of her There are such beautiful pictures that everybody will want one ...
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Proof of heaven, a neurosurgeons journey into the afterlife   eben alexander

Proof of heaven, a neurosurgeons journey into the afterlife eben alexander

Kỹ năng làm việc nhóm

... The Core 10 What Counts 11 An End to the Downward Spiral 12 The Core 13 Wednesday 14 A Special Kind of NDE 15 The Gift of Forgetting 16 The Well 17 N of 18 To Forget, and to Remember 19 Nowhere ... begun 15 The Gift of Forgetting We must believe in free will We have no choice —ISAAC B SINGER (19 02 19 91) The view of human consciousness held by most scientists today is that it is composed of ... Saturday in 19 75, the rest of the UNC jumpers and I teamed up with some of our friends at a paracenter in eastern North Carolina for some formations On our penultimate jump of the day, out of a D18 Beechcraft...
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Báo cáo toán học:

Báo cáo toán học: "A Short Proof of the Rook Reciprocity" pps

Báo cáo khoa học

... purpose of this note is to provide such a proof The knowledgeable reader will recognize that the main idea is borrowed from [4] Proof Observe that d ( 1) R(B; − x − 1) = ( 1) d B rk ( − x − 1) d−k ... inclusion-exclusion, we see that the resulting configurations in which the set S of rooks on B is nonempty cancel out of the above sum, because they are counted once for each subset of S, with alternating signs ... − x − 1) d−k d k=0 d B ( 1) k rk (x + d − k)d−k = k=0 B First assume x is a positive integer Add x extra rows to [d] × [d] Then rk (x + d − k)d−k is the number of ways of first placing k rooks...
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