... IBD andthe used numberof surrounding markers (windows size) in haplotypes on the average numberof haplotypes inthe base population and non-base haplotypes are shown in Table Increasing window ... probability inthe marker intervals surrounding the QTL position, i.e the QTL was often mapped in one ofthe neighbouring intervals (Fig and 4) Window sizes ofand 12 generally yielded the highest ... 2100 animals Therefore, applying the standard clustering limit of 0.95 already decreased thenumberof haplotypes to 10% ofthe initial number Accuracy and bias of predicted total breeding values...
... UNIVERSTIES , MORE TRAINING PROBLEMS According to the Ministry of Education and Training (MOET), the galloping increaseinthenumberof universities has led to low training quality at many universities ... Ngoc, head ofthe Department of Information and Technology under 12 the Ministry of Education and Training The development and application of ICT was an essential part of reforming thenational ... the nation And finally, the fifth project will reform the existing financial structure ofthe sector, including tuition fees to make them more in line with reality In this school year, the Ministry...
... blocked into six main regions in Vietnam After conducting the test, the result show that during this 6-year period, despite the changes in both numberofstudentsand teachers, thenumberofstudents ... explains the reason for unchanged numberofstudents per teacher over the years However, compared with the world’s standard (15-20 students/ teacher) andthe goal of Ministry of Education and Training ... facilities and equipments for teaching Conclusion In conclusion, the report carried out on the purpose of dealing with a statistics question: whether there exist any differences inthenumberof students...
... Consequently, Japan has the largest amount of cash and deposits inthe world Household Assets in Major Countries % 100 Cash and deposits Insurance and pension Securities excluding stocks Stocks and other equities Others ... from 2007, consumers became more risk averse, and deposits began to increase once again. In Japan, the ongoing trend toward a declining birthrate and an aging population is making it increasingly difficult ... Massive amount of Deposits the Largest Balance of Deposits inthe World The Bank has the largest amount of deposits inthe world, even in comparison with overseas banks, and is one ofthe world’s largest financial institutions...
... Since then temozolomide plus radiotherapy has become the international standard of care for the brain cancer glioblastoma, leading to a pronounced increasein survival Informing and influencing ... for the future, pioneering the development and provision of relevant training in our Institutes and Centres and working in partnership where possible - Maintain our current investment in training ... raise the quality of our basic research in our Institute and grant-funded research - Invest further andincrease capacity in imaging research andin more sophisticated in silico and mouse models of...
... construction, and management of training institutions Outside ofthe MoH, the Cabinet Office andthe Ministry of Finance control the annual budget for all ministries The Ministry of Education andthe Ministry ... across the five years of scale-up including expanding thenumberof nursing bachelors and masters students graduating from the University of Zambia from 35 to 50 students annually and introducing ... computer lab, and dining hall, in addition to the maximum numberof faculty per staff office and house [13] Thenational quality standard ratios for thenumberofstudents per tutor and clinical teacher...
... [24] The probability of selecting an institution was inversely proportional to thenumberof institutions in its stratum and proportional to its numberof beds Eight subjects were picked at random ... (number of subjects inthe institution /number of available beds), andthe answer refusal rate (higher in psychiatric centres) In 1998, 2,075 institutions were selected and 155 of them (7.5%) refused ... [29] On the other hand, we did study representative samples of subjects from both the community and institutions Another issue concerns the small numberof subjects who declared themselves blind,...
... image processing at the Naval Academy in Brest In 1992 he joined the Engineering School ENSIETA of Brest, where he held the positions of Senior Researcher and Head ofthe Electronics and Informatics ... behavior ofthe four criteria, with respect to the dynamic range ofthe amplitudes ofthe two sinusoids (Figure 6a) and to the whiteness ofthe noise (Figure 6b) S/N ratios of 10 dB and 15 dB, ... evaluated from the point of view ofthe supported dynamic range ofthe harmonic component magnitudes, of its behavior against white and colored noise, andofthe required computing time We 1187...
... tourists go abroad for travelling in a decade and Australians share of marketing for Japanese tourists Between 1985 and 1995 Japanese tourists travelling abroad was dramatically increased In 85 there ... does what is required of her in terms of task fulfilment, andthe message can be followed, but the weaknesses in grammatical control andin spelling cause difficulty for the reader Complex sentence ... Therefore in 1995 there were about 15 millions people went abroad I am going to write about the other chart, which is Australians share of Japaneses tourist market This is also between 1985 and...
... observation of their dependences A project was realized inthe Krunộ hory Mts involving a part aimed at the assessment of game damage from the data oftheNational Forest Inventory ofthe Czech ... was investigated in each height regeneration class as well as thenumberof trees damaged by browsing of terminal shoot, by fraying or by peeling and browsing by ungulate game Peeling and browsing ... 90% of this group) inthe open space, below the stand the other deciduous tree species, maple and beech, are behind the spruce Table The occurrence of tree species in regeneration Numberof regeneration...
... Using the linearity of CTw , manipulating the series, using the definition (Carl) ofthe q−binomial coefficients, and simplifying, brings the left side of (Sasha ) to be CTw ... complete the proof ofthe theorem, we use lemma to evaluate the inner sum of (SumAnna), then to get A2n (q), we replace n by 2n, and then replace l by l + n, and finally use the binomial theorem ... is odd and r = (n − 1)/2, in which case it is a monomial in q times (1−w)(1+w) , wr+1 and applying CTw kills it all the same, thanks to the symmetry ofthe Chu-Pascal triangle Summing the expression...
... without further explanation THE ELECTRONIC JOURNAL OF COMBINATORICS (1998) , #R20 Thenumberof descendants in random BSTs Thenumberofthe descendants Dn,j ofthe j th node of a BST of size n ... 7(b + 2) 49n6 Thenumberof ascendants of a given node in a LBST As inthe case ofthenumberof ascendants in a random BST, computing the probability that the j th node in a random LBST has ... contain up to b keys; if Pn is thenumberof external nodes or pages in (b) (b) a paged search tree, then In = Pn − is thenumberof internal nodes inthe tree, and these internal nodes are in...
... to the segment containing x, the segment containing x , andthe remaining segment Going round the cycle Ci , starting at x and ending at x, the vertices x, x , y, y , z, z may appear in one of ... (β ln n)k −1 φ(k) In either case, the inequality in part ofthe lemma holds the electronic journal of combinatorics (2000), #R57 Part ofthe lemma follows from the chain of inequalities (β ln ... neighbours in C1 and we can argue the existence of a 6-cycle as inthe previous case Remark: The proof shows that thenumberof Hamilton cycles is within a polynomial factor ofthenumberof two...
... vertices, and (G) denote thenumberof edges In this paper, we construct a graph G having no two cycles with the same length which leads to the following result Theorem Let t = 27720r + 169 (r ≥ 1), then ... 32t − 17t+1 Then f (n) ≥ n + 32t − 1, for n ≥ nt This completes the proof ofthe theorem From the above theorem, we have f (n) − n 2562 √ ≥ 2+ , n 6911 √ 487 which is better than the previous ... Combining this with Boros, Caro, F¨ redi and Yuster’s upper bound, we have u f (n) − n f (n) − n 1.98 ≥ lim sup √ ≥ lim inf √ ≥ 1.5397 n→∞ n n n→∞ lim inf n→∞ the electronic journal of combinatorics...
... + 1, the electronic journal of combinatorics (2001), #N6 giving inequality (a) To prove inequality (b), let M be the submatrix of M consisting of rows βm+1, , m and all columns of M Since ... Disjoint cycles in Eulerian digraphs andthe diameter of interchange graphs, J Combin Theory Ser B, to appear [4] D.W Walkup, Minimal interchanges of (0, 1)-matrices and disjoint circuits in a graph, ... loss of generality, assume v ∗ ∈ A (since otherwise we can interchange the roles of m and n, as we did not impose any cardinality constraints upon them) It clearly suffices to prove the following:...
... given in Fig Then the following lemma is clear, since from the knowledge of σ(B) we can update thenumberof components inthe union B ∪ C Inthe example in Fig we have r(B) = 26, r(C) = and δ(B, ... corresponds to the edge set of a spanning forest of Lkp+1 i=0 The reason is the following Suppose there is a cycle C in B, then it would intersect some ofthe subgraphs Bi The cycle C cannot be inside ... = the electronic journal of combinatorics 10 (2003), #R4 (6.6) 13 Suppose that there is no edge of C belonging to a cycle of Gσ1 ,C Thus, the removal of any edge in C increases thenumber of...
... above argument with the portion of R beginning at um−1 andthe vertex um Theorem Let hp (n) be the minimum numberof distinct hamiltonian paths in a strong tournament of order n Then · β n−3 ... assume the result for all paths Q of order at most m−1 Let Q = u1 u2 · · · um−1 and apply the induction hypothesis using the paths P and Q to obtain a path R satisfying the lemma Next, we repeat the ... vertices of C have in- neighbors in Wt , and at least two vertices of C have out-neighbors in W1 Thus, at least one vertex of C has both in- neighbors in Wt and out-neighbors in W1 Without loss of...
... numberof edges in Γπ,0 equals thenumberof permutations σ that are covered by π inthe strong Bruhat1 order on Sn , andthenumberof edges in Gπ,0 equals the degree ofthe vertex π inthe Hasse2 ... neighbors ofand t must lie inthe union ofthe marked rectangular regions A, B, C, D, and E (but we not need E if we are inthe case ofthe second diagram) Since l and t are adjacent, thenumberof ... case analysis andthe proof of Theorem 1.2 Edge bounds in Gπ,s In this section we prove Theorem 1.3, which gives bounds on the maximum numberof edges in Gπ,s with π ∈ Sn Proof of Theorem 1.3...