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ieee project topics for computer science engineering 2012

Vic broquard   c++ for computer science and engineering

Vic broquard c++ for computer science and engineering

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... C++ for Computer Science and Engineering Vic Broquard Copyright 2000, 2002, 2003, 2006 by Vic Broquard All rights reserved No part of this book may be reproduced or transmitted in any form without ... substantially longer to perform.) Thus, it is the ability of the modern computer to perform reliably and to perform at great speed that has made it so powerful Introduction to Programming Computers have ... was formally standardized by ISO (International Standards Organization) This means that now your C++ program can be written and compiled on any computer platform (PCs, minicomputers, mainframe computers)...
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Challenges faced by information technology students in reading english for computer science

Challenges faced by information technology students in reading english for computer science

Khoa học xã hội

... learned for years, others for years and the rest has learnt for years In the department of information technology at our college, they engage in ESP course, it means English for Computer Science, ... challenges in learning reading ESP for computer science, the questionnaires were designed for students Then data were analyzed and the information was displayed in the form of tables III.4 Summary ... examine the areas of challenges in reading comprehension of English for Computer Science for second-year students in the department of information technology at Nghe An JTTC To be more specific, the...
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Tài liệu Discrete Math for Computer Science Students doc

Tài liệu Discrete Math for Computer Science Students doc

Cao đẳng - Đại học

... Our algorithm performs a certain set of multiplications For any given i, the set of multiplications performed in lines through can be divided into the set S1 of multiplications performed when j ... multiplications performed when j = 2, and, in general, the set Sj of multiplications performed for any given j value Each set Sj consists of those multiplications the inner loop carries out for a particular ... using the formula for n is is straightforward to show that n n−1 = n (n − 2) However this proof just uses blind substitution and simplification Find a more conceptual explanation of why this formula...
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Mathematics for Computer Science pot

Mathematics for Computer Science pot

Sức khỏe giới tính

... in computer science Generally, induction is used to prove that some statement holds for all natural values of a variable For example, here is a classic formula: 26 Induction I Theorem 12 For ... simplification Therefore, P (n) is true for all natural n by induction, and the theorem is proved Induction was helpful for proving the correctness of this summation formula, but not helpful for discovering ... seems very reasonable! But, of course, there is room for disagreement about what consitutes a reasonable axiom For example, one of Euclid’s axioms for geometry is equivalent to the following: Axiom...
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Mathematics for Computer Science pptx

Mathematics for Computer Science pptx

Cao đẳng - Đại học

... of numbers of the form rn, where r is a positive real number and n N Well ordering commonly comes up in Computer Science as a method for proving that computations won’t run forever The idea is ... proposition for each possible set of truth values for the variables For example, the truth table for the proposition “P AND Q” has four lines, since there are four settings of truth values for the ... false for n D c but true for all nonnegative integers n < c But (2.1) is true for n D 0, so c > This means c is a nonnegative integer, and since it is less than c, equation (2.1) is true for c...
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Logic For Computer Science Foundations of Automatic Theorem Proving potx

Logic For Computer Science Foundations of Automatic Theorem Proving potx

Cao đẳng - Đại học

... for constructing formal proofs of formulae algorithmically This book is designed primarily for computer scientists, and more generally, for mathematically inclined readers interested in the formalization ... decision procedures for testing the validity of quantifier-free formulae are presented This book grew out of a number of class notes written for a graduate course in logic for computer scientists, ... Theorem for Prenex Formulae, 344 xx TABLE OF CONTENTS PROBLEMS, 353 7.6 ∗ 7.7 Skolem-Herbrand-G¨del’s Theorem for Formulae in NNF, 355 o 7.6.1 Skolem-Herbrand-G¨del’s Theorem in Unsatisfiability o Form,...
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concrete mathematics a foundation for computer science phần 1 pdf

concrete mathematics a foundation for computer science phần 1 pdf

Kỹ thuật lập trình

... expression for the quantity of interest For the Tower of Hanoi, this is the recurrence (1.1) that allows us, given the inclination, to compute T,, for any n Find and prove a closed form for our ... “simple” closed form For example, the product of the first n integers, n!, has proved to be so important that we now consider it a basic operation The formula ‘n!’ is therefore in closed form, although ... inequalities, together with the trivial solution for n = 0, yield To =O; T, = 2T+1 +l , Yeah, yeah lseen that word before (1.1) for n > (Notice that these formulas are consistent with the known values...
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concrete mathematics a foundation for computer science phần 2 pptx

concrete mathematics a foundation for computer science phần 2 pptx

Kỹ thuật lập trình

... closed form for f(n) , when n L Provethatf(n)=n-l+f([n/2~)+f(~n/Z])foralln~l 35 Simplify the formula \(n + )‘n! e] mod n 36 Assuming that n is a nonnegative integer, find a closed form for the ... arbitrary positive integer n in the form n = 2m + 1, where < < 2” Give explicit formulas for and m as functions of n, using floor and/or ceiling brackets What is a formula for the nearest integer to a ... v(x+l) Au(x) (2.54) This formula can be put into a convenient form using the shij?! operator E, defined by Ef(x) = f(x+l) Substituting this for v(x+l) yields a compact rule for the difference of...
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concrete mathematics a foundation for computer science phần 3 ppsx

concrete mathematics a foundation for computer science phần 3 ppsx

Kỹ thuật lập trình

... 4) QED for the case m = 12 So far we’ve proved our congruence for prime m, for m = 4, and for m = 12 Now let’s try to prove it for prime powers For concreteness we may suppose that m = p3 for some ... cl(P) = -1; p(pk) = for k > Therefore by (4.52), we have the general formula ifm=pjpz p,; if m is divisible by some p2 (4.57) That’s F If we regard (4.54) as a recurrence for the function q(m), ... write for gcd( m, n), a for m’, and b for -n’.) The Farey series gives us another proof of (4.32), because we can let b/a be the fraction that precedes m/n in 3,, Thus (4.5) is just (4.31) again For...
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concrete mathematics a foundation for computer science phần 4 ppsx

concrete mathematics a foundation for computer science phần 4 ppsx

Kỹ thuật lập trình

... summation formula of the form al, a,, z kbk = CF h, b, 1) AI, AM, '5, , BN (5.127) k’ then we also have al, a,, bl, bn k+l ’ for any integer There’s a general formula for shifting ... ignore convergence if we are using z simply as a formal symbol It is not difficult to verify that formal infinite sums of the form tk3,, (Xkzk form a field, if the coefficients ak lie in a field ... on such formal sums without worrying about convergence; any identities we derive will still be formally true For example, the hypergeometric F( “i ,’ /z) = tkZO k! zk doesn’t converge for any...
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concrete mathematics a foundation for computer science phần 5 pps

concrete mathematics a foundation for computer science phần 5 pps

Kỹ thuật lập trình

... a closed formula for them We haven’t found closed forms for Stirling numbers, Eulerian numbers, or Bernoulli numbers either; but we were able to discover the closed form H, = [“:‘]/n! for harmonic ... -F; = (-l).", for n > (6.103) When n = 6, for example, Cassini’s identity correctly claims that 3.5-tS2 = A polynomial formula that involves Fibonacci numbers of the form F,,+k for small values ... a few things For one, kim’ isn’t a polynomial if j = 0; so we will need to split off that term and handle it separately For another, we’re missing the term k = from the formula for nth difference;...
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concrete mathematics a foundation for computer science phần 6 doc

concrete mathematics a foundation for computer science phần 6 doc

Kỹ thuật lập trình

... exist for negative n Two kinds of “closed forms” come up when we work with generating functions We might have a closed form for G(z), expressed in terms of z; or we might have a closed form for ... that R(0) # 00 can be expressed in the form R(z) = S(z) t T(z), (7.28) where S(z) has the form (7.26) and T(z) is a polynomial Therefore there is a closed form for the coefficients [z”] R(z) Finding ... expressed in terms of n For example, the generating function for Fibonacci numbers has the closed form z/( - z - z2); the Fibonacci numbers themselves have the closed form (4” - $n)/fi The context...
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concrete mathematics a foundation for computer science phần 7 pot

concrete mathematics a foundation for computer science phần 7 pot

Kỹ thuật lập trình

... element of n has the form (T + HT)"HH for some n 0, and each term of T has the form (0 + E)n Therefore by (7.4) we have s = (I-T-HT)-'HH, and the probability generatin.g function for our problem is ... PROBABILITY For example, suppose ,the keys are names, and suppose that there are m = lists based on the first letter of a name: 1, for ,4-F; 2, for G-L; h(name) = 3, for M-R; 4, for !3-Z We start ... form for P~,~ Generalizing your a.nswer to part (a), find a closed form for the probability that exactly k matches are in the other box when an empty one is first th.rown away Find a closed form...
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concrete mathematics a foundation for computer science phần 8 doc

concrete mathematics a foundation for computer science phần 8 doc

Kỹ thuật lập trình

... that R stands for “‘real part.” valid for !.Xz > 9%~ The asymptotic formula for Bernoulli numbers B, in Table 438 illustrates this principle On the other hand, the asymptotic formulas for H,, n!, ... is negative for < x < i and positive for i < x < Therefore its integral, Bdk+~ (x)/(4k+2), decreases for < x < and increases for i < x < Moreover, we have bk+l(l - X) = -&+I (X) , for < x < 1, ... therefore a closed form for gn seems out of the question, and asymptotic information is probably the best we can hope to derive Our first handle on this problem is the observation that < gn for...
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concrete mathematics a foundation for computer science phần 9 pps

concrete mathematics a foundation for computer science phần 9 pps

Kỹ thuật lập trình

... variables Lij for all i # j Setting kii = li’ -Lji for :< i < j < n and using the constraints tifi (lij -iii) = for all i < n allows us to carry out the sums on li, for j < n and then on iii for < i ... hint, we get andasimilarformulafor&,(z) Thustheformulas (ztB;‘(z)‘B[(z)+l)Bt(z)r and (ztE;‘(z)&:(z) + l)&,(z)’ give the respective right-hand sides of (5.61) We must therefore prove that (zwwJm ... of F( a2 + j, a3, , a,,,; b2, , b,; z) for j d, thereby eliminating an upper parameter and a lower parameter Thus, for example, we get closed forms for F( a, b; a - 1; z), F( a, b; a - 2; z),...
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concrete mathematics a foundation for computer science phần 10 docx

concrete mathematics a foundation for computer science phần 10 docx

Kỹ thuật lập trình

... constants Q, B, no, C such that la(n)/ Blf(n)[ for n mc and [b(n)1 Clg(n)l for n no Therefore the left-handfunctionisatmostmax(B,C)(lf(n)l+Ig(n)l),forn3max(~,no), so it is a member of the right ... infinite sum for 1x1,” American Mathematical Monthly 96 (1989), 525-526 602 131 Ronald L Graham, Donald E Knuth, and Oren Patashnik, Concrete 102 Mathematics: A Foundation for Computer Science Addison-Wesley, ... 196-204, 283-285, 306-366 for Bernoulli numbers, 271, 337, 351 for convolutions, 339-350, 355, 407 Dirichlet, 356-357, 359, 418, 437 for Eulerian numbers, 337 exponential, 350-355 for Fibonacci numbers,...
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Factors affecting reading comprehension of English for computer science of the second year students at Vinh Technical Teachers' Training University = Những yếu

Factors affecting reading comprehension of English for computer science of the second year students at Vinh Technical Teachers' Training University = Những yếu

Sư phạm

... relating to the computer science topics such as: History of computer, characteristics and applications of computers, the CPU, memory, hardware and software, the operating systems, computer graphics ... English for Computer Science Thus, within the scope of the study the researcher would like to put forward some recommendations to improve the quality of teaching and learning of English for Computer ... (percentage) and interpretations The information was then displayed in forms of tables and figures 3.5.1 Factors affecting reading English for Computer Science at VTTTU 3.5.1.1 The participants’...
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Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science

Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science

Công nghệ thông tin

... characters Problem 3.5 In this problem, we will be reading in formatted data and generating a report One of the common formats for interchange of formatted data is ’tab delimited’ where each line corresponds ... the desired output program dictionary.o Problem 3.3 Both the for loop and the do-while loop can be transformed into a simple while loop For each of the following examples, write equivalent code ... } dict.h: #include "dict.h" /* data structure for the dictionary */ char * the dictionary[1000]; void load dictionary() { } /* data structure for the dictionary */ char * the dictionary[1000];...
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Tài liệu Feaculty of Computer Science and Engineering Department of Computer Scienc Tutorial 3 Questions pdf

Tài liệu Feaculty of Computer Science and Engineering Department of Computer Scienc Tutorial 3 Questions pdf

Kỹ thuật lập trình

... Faculty of Computer Science and Engineering Department of Computer Science Return element of s is appended into q with the same order For example if q = {1,2,3}, s = {4,5,6} ... middle position when the array is reordered increasingly 2/4 Faculty of Computer Science and Engineering Department of Computer Science Algorithm compute (val a , val n ) Pre n >=0 ... dequeue(q,temp) 3/4 enqueue(Q,temp) return Q End append Faculty of Computer Science and Engineering Department of Computer Science if (subroot is NULL) Allocate subroot Part Binary Tree subroot->data...
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