gujarati 2004 basis econometrics 4th edition mcgraw hill irwin cuốn sách này có phiên bản tiếng việt do chương trình giảng dạy kinh tế fulbright biên dịch
... Damodar N Gujarati (2004) , Basis Econometrics, 4th edition, McGraw- HillIrwin (cuốn sáchcóphiêntiếngviệtChươngtrìnhgiảngdạykinhtếFulbrightbiên dịch) Griffiths, W.E, Hill, C.R and Judge ... báo kinhtế Nội dung chi tiết: Chương mở đầu: TỔNG QUAN VỀ KINHTẾ LƯỢNG Kinhtế lượng gì? Mối quan hệ Kinhtế lượng môn học Phương pháp luận kinhtế lượng Đối tượng, nội dung Kinhtế lượng Chương ... Giáo trìnhKinhtế lượng, Nhà xuất Tài Câu hỏi tập kinhtế lượng Tài liệu tham khảo Nguyễn Quang Dong, Nguyễn Thị Minh (2012), Giáo trìnhKinhtế lượng, Nhà xuất Kinhtế Quốc dân Damodar N Gujarati...
... định kinhtế dự án Suất chiết khấu thẩm định kinhtế cần phản ảnh lợi ích kinhtế mà kinhtế phải từ bỏ để phát triển hoạt động đầu tư Chi phí kinhtế vốn phản ảnh tồn lợi ích kinhtế mà kinhtế ... tài có hiệu kinhtế âm gây thiệt hại cho tồn kinhtế khơng triển khai tốt Glenn P Jenkins & Arnold C Harberger 15 Hiệu đính: Q Tâm, 1/2005 ChươngtrìnhGiảngdạyKinhtếFulbright Niên khố 2004- 2005 ... 1/05 ChươngtrìnhGiảngdạyKinhtếFulbright Niên khố 2004- 2005 Thẩm định đầu tư phát triển Bài đọc Sách hướng dẫn Ch Thẩm định dự án đầu tư cơng cộng xây dựng biên dạng ngân lưu tài cho dự án Chương...
... McGraw- Hill Dictionary of Engineering Second Edition McGraw- Hill New York Chicago San Francisco Lisbon London Madrid Mexico City Milan New Delhi San ... Hoare, Special Sales, at george_hoare @mcgraw- hill. com or (212) 904-4069 TERMS OF USE This is a copyrighted work and The McGraw- Hill Companies, Inc (“McGrawHill”) and its licensors reserve all ... Copyright 2003 by The McGraw- Hill Companies, Inc Click Here for Terms of Use How to Use the Dictionary ALPHABETIZATION The terms in the McGraw- Hill Dictionary of Engineering, Second Edition, are alphabetized...
... Instructor’s Manual to accompany Electric Machinery Fundamentals, Fourth Edition Copyright 2004 McGraw- Hill, Inc All rights reserved Printed in the United States of America No part of ... the email address given below, or alternately via you McGraw- Hill representative Thank you Stephen J Chapman Melbourne, Australia January 4, 2004 Stephen J Chapman 278 Orrong Road Caulfield North, ... the wire is positive downward because the vector quantity v × B points downward eind = ( v × B) ⋅ l = vBl cos 45° = (5 m/s)( 0.25 T )( 0.50 m ) cos 45° = 0.442 V, positive down 1-11 Repeat Problem...
... the power factor of this load? (d) Calculate the reactive power consumed or supplied by this load Does the load consume reactive power from the source or supply it to the source? SOLUTION (a) The ... typical wall voltages in Europe are 220 to 240 V at 50 Hz Many travelers carry small step-up / step-down transformers so that they can use their appliances in the countries that they are visiting...
... function of load for power factors of 0.8 lagging, 1.0, and 0.8 leading These calculations are done using an equivalent circuit referred to the primary side % Define values for this transformer ... function of load for power factors of 0.85 lagging, 1.0, and 0.85 leading These calculations are done using an equivalent circuit referred to the primary side % Define values for this transformer ... function of load for power factors of 0.85 lagging, 1.0, and 0.85 leading These calculations are done using an equivalent circuit referred to the primary side % Define values for this transformer...
... at those conditions? (b) Sketch the transformer connections when it is used as a 600/480-V step-down autotransformer (c) What is the kilovoltampere rating of this transformer when it is used in ... transformer is VR = (b) 1.0 − 0.991 × 100% = 0.9% 0.991 The autotransformer connection for 600/480 V stepdown operation is 58 + NSE + 600 V NC (c) VC + 480 V - - When used as an autotransformer, the kVA ... which it is located The impedance of transformer T1 is already in perunit to the proper base, so we don’t have to anything to it: R1,pu = 0.010 X 1,pu = 0.040 The impedance of transformer T2 is already...
... input voltage is vin ( t ) = 10 sin 2πft V, and f = 50 Hz (b) What does the spectrum of the output voltage look like? What could be done to reduce the harmonic content of the output voltage? (c) ... the output voltage when the input voltage is vin ( t ) = 10 sin 2πft V, and f = 50 Hz (d) What does the spectrum of the output voltage in (c) look like? (e) What is the advantage of using a higher...
... can see that the frequencies of the first large sidelobes doubled from about 900 Hz to about 1800 Hz when the reference frequency was doubled This increase in sidelobe frequency has two major ... (b) (e) Calculate the mechanical power being consumed by the loop for the conditions in (b) How does this number compare to the amount of electric power being generated by the loop? ωm c N r d ... generator? (e) What is the new terminal voltage after the load has been added? (f) What must be done to restore the terminal voltage to its original value? SOLUTION (a) If the field current is...
... of them being exceeded? At what frequency does this limit occur? How much power does each generator supply at that point? (c) What would have to be done to get all three generators to supply ... constant, what is the maximum power possible out of this generator? How much reserve power or torque does this generator have at full load? (d) At the absolute maximum power possible, how much reactive ... of the total power supplied to all loads (you may use MATLAB to create this plot) At what load does one of the generators exceed its ratings? Which generator exceeds its ratings first? (c) Is...
... generators, but if the 20 MW generator goes down all 20 MW of generation would be lost at once If two 10 MW generators are chosen, one of them could go down for maintenance and some power could ... at 60 Hz Note that this is not quite true, if the armature resistance R A is included, since R A does not scale with frequency in the same fashion as the other terms 5-24 Two identical 600-kVA ... torque of this motor? Express the answer both in newton-meters and in pound-feet (b) What must be done to change the power factor to 0.8 leading? Explain your answer, using phasor diagrams (c) What...
... the same amount as E A , what is the maximum power the motor could supply at 300 r/min? (f) How does the power capability of a synchronous motor relate to its speed? SOLUTION (a) A speed of 300 ... 280∠0° V − j ( 0.4 Ω )( 95.7∠5.7° A ) = 286∠ − 7.6° V If we make Vφ the reference (as we usually do) , these voltages and currents become: E A, g = 280∠7.6° V Vφ = 286∠0° V E A,m = 327∠ − 18.3° ... armature current or the field current that limits the reactive power output? (d) How much power does the field circuit consume at the rated conditions? (e) What is the efficiency of this motor...
... is: 179 7-11 If the motor in Problem 7-7 is to be operated on a 50-Hz power system, what must be done to its supply voltage? Why? What will the equivalent circuit component values be at 50 Hz? ... is decreased to 50 Hz, then the applied voltage must be decreased by 5/6 also If this were not done, the flux in the motor would go into saturation, since φ= N ∫ v dt T and the period T would ... the mechanical and core losses as constant despite the change in speed This is not true, but we don’t have reason for a better guess Therefore, the output power of this motor is POUT = Pconv −...
... the motor be? What will the motor’s terminal voltage be on starting? (c) If an ideal 1.4:1 step-down autotransformer is connected between the transmission line and the motor, what will the current ... by about 30% during motor starting, which would be unacceptable 198 (c) If an ideal 1.4:1 step-down autotransformer is connected between the transmission line and the motor, the motor’s impedances ... the 30% sag with case of across-the-line starting 7-21 In this chapter, we learned that a step-down autotransformer could be used to reduce the starting current drawn by an induction motor While...
... 175 Ω If the armature reaction is 1200 A⋅turns at full load, what is the speed of the motor? How does it compare to the result for Problem 9-2? SOLUTION The field current is again 0.87 A, and the ... current of this machine if it is started by connecting it directly to the power supply VT ? How does this starting current compare to the full-load current of the motor? SOLUTION The starting ... operating at full load What will the new speed of the motor be if Radj is increased to 250 Ω? How does the new speed compared to the full-load speed calculated in Problem 9-10? SOLUTION If Radj...
... compounded dc generator is operating properly as a flat-compounded dc generator The machine is then shut down, and its shunt field connections are reversed (a) If this generator is turned in the same direction ... the ac machine? (b) The field current in the ac machine is now increased by percent What effect does this change have on the real power supplied by the motor-generator set? On the reactive power ... conditions in part (b), the field current in the dc machine is now decreased by percent What effect does this change have on the real power supplied by the motor-generator set? On the reactive power...