... part of the book, it is not required.SupplementsSolutions Manual an Instructor’s Solutions Manual isavailable to instructors who adopt the text. It containscomplete solutions to all the end -of- chapter ... large variety ofelectric circuits. Kirchhoff’slawswerefirst introduced in 1847 by theGermanphysicistGustav RobertKirchhoff (1824–1887). These laws are formally known as Kirchhoff’scurrent ... in an electricalnetwork. Kirchhoff’s laws, along with Ohm’s law, form the basis of circuit theory.Born the son of a lawyer in Konigsberg, East Prussia, Kirchhoff enteredthe University of Konigsberg...
... subject to the Terms of Use as given at the website. FUNDAMENTALS OFELECTRIC SYSTEMS FUNDAMENTALS OF ELECTRIC SYSTEMSCAPACITORSFigure 1.1 illustrates a capacitor. It consists of two insulated ... Companies. All rights reserved.Any use is subject to the Terms of Use as given at the website. FUNDAMENTALS OFELECTRIC SYSTEMS FUNDAMENTALSOFELECTRIC SYSTEMS 1.9FIGURE 1.9 Iron filings around a wire ... subject to the Terms of Use as given at the website. FUNDAMENTALS OFELECTRIC SYSTEMS TABLE 2.1 Characteristics of Soft Magnetic MaterialsSaturation Amplitude Coercive Electrical CuriePrincipal...
... ẳ1Examples.Field of real numbers R.Field of complex numbers C.Field of rational functions with real coefficients R(s).Field of binary numbersThe set of integers Z with the standard notions of addition ... has at most one solution; otherwise more than one solution can occur, provided that at least one solution exists.When one thinks of a set of simultaneous equations as a ‘‘system’’ of equations, ... Circuits and Filters The Circuits and Filters HandbookThird Edition Fundamentals ofCircuits and FiltersFeedback, Nonlinear, and Distributed Circuits Analog and VLSI Circuits Computer Aided...
... solve for one variable in terms of the other(s).6 In the process of establishing the above analogy, we first establish the concepts of the firstand second derivatives of an integral (13) about a ... end-point values of y0(x)orη(x)). Form thefamily of arcsy0(x)+η(x) x1≤ x ≤ x2(16)x1[x2]y0Figure 9: Families of arcs y0+ ηThen for sufficiently small values of say −δ ≤ ... The third part of the problem, the determination of an arc satisfying thesufficient conditions, is frequently the most difficult of all, and is the part for which fewestmethods of a general character...
... dark because of the costs of compliance. The costs to comply with Sarbox can be several million dollars, which can be a large percentage of a small firms profits. A major cost of going dark ... $25 Solutions Manual Fundamentals of Corporate Finance 8th edition Ross, Westerfield, and Jordan Updated 03-05-2007 B-28 SOLUTIONS Market-to-book ratio ... costs of raising funds in the public market. 5. The treasurer’s office and the controller’s office are the two primary organizational groups that report directly to the chief financial officer....
... RETURN OF A 50-50 PORTFOLIO OF HIGH TECH AND COLLECTIONS? OF HIGH TECH AND U.S. RUBBER?ANSWER: [SHOW S5-45 AND S5-46 HERE.] NOTE THAT THE BETA OF A PORTFOLIO IS SIMPLY THE WEIGHTED AVERAGE OF ... FOLLOWS:∑==n1iiikPkˆ.HERE Pi IS THE PROBABILITY OF OCCURRENCE OF THE iTH STATE, ki IS THE ESTIMATED RATE OF RETURN FOR THAT STATE, AND n IS THE NUMBER OF STATES. HERE IS THE CALCULATION FOR HIGH ... “YES” JUST THINK OF THE PURCHASE OF A LIFE OR FIRE INSURANCE POLICY. THE FIRE INSURANCE POLICY HAS A NEGATIVE EXPECTED RETURN BECAUSE OF COMMISSIONS AND INSURANCE COMPANY PROFITS, BUT BUSINESSES...
... 1.8983FVIF@7% for 11 yrs = 2.1049Estimated n = 11 yrs.Answers and Solutions: 6 - 1Chapter 6Time Value of MoneySOLUTIONS TO END -OF- CHAPTER PROBLEMS10%7%6.5% 6-6 0 1 2 3 4 5| | | | | | 300 ... $100/0.14 = $714.29.When the interest rate is doubled, the PV of the perpetuity is halved.6-20 a. Begin with a time line:Answers and Solutions: 6 - 3i = ?7% following into your calculator: ... into your calculator: N = 5, I = 3, PV = 0, FV = 508.92,and solve for PMT = $93.07.Answers and Solutions: 6 - 5 6-1 0 1 2 3 4 5 | | | | | |PV = 10,000 FV5 = ?FV5= $10,000(1.10)5= $10,000(1.61051)...
... Chapter 9 uses the rate of return concepts covered in previous chapters, along with the concept of the weighted average cost of capital (WACC), to develop a corporate cost of capital for use in ... will be accepted since their rates of return exceed the WACC.Answers and Solutions: 9 - 10 $3.54 million (60%) of equity capital and $2.36 million (40%) of debt capital. In this scenario, ... projects whose returns exceed their risk-adjusted costs of capital. The appropriate costs of capital are summarized below: Required Rate of Cost of Project Investment Return Capital A $4 million...
... VALUE OF THE TERMINAL VALUE OF THE INFLOWS,COMPOUNDED AT THE COST OF CAPITAL, TO THE PRESENT VALUE OF THE COSTS.HERE IS THE SETUP FOR CALCULATING PROJECT L’S MODIFIED IRR: 0 1 2 3 | | | |PV OF ... THE SLOPE OF THE NPV PROFILE DEPENDSENTIRELY ON THE TIMING PATTERN OF THE CASH FLOWS LONG-TERM PROJECTSHAVE STEEPER NPV PROFILES THAN SHORT-TERM ONES. THUS, WE CONCLUDETHAT NPV PROFILES CAN ... LEVEL OF INTEREST RATES. THIS ISCALLED THE PROJECT COST OF CAPITAL IN CAPITAL BUDGETING.4. FIND (A) THE PV OF THE EXPECTED CASH FLOWS AND/OR (B) THE ASSET’SRATE OF RETURN.5. IF THE PV OF THE...
... and thermal conductivity of steel tubes. Temperature of steamflowing through the tubes. Thermal conductivity of insulation and emissivity of aluminum sheath.Temperature of ambient air and surroundings. ... C.=<COMMENTS: Use of the critical insulation thickness in lieu of a thin coating has the effect of reducing the maximum insulation temperature from 778.7°C to 318.2°C. Use of the critical insulationthickness ... larger than those of the transistor. PROBLEM 3.41KNOWN: Thin electrical heater fitted between two concentric cylinders, the outer surface of whichexperiences convection.FIND: (a) Electrical power...
... as well as the rate of heat transfer by convection to the surface.COMMENTS: (1) Using the matrix-inversion method, the exact solution to the system of equations (1,2, 3) of part (a) is T1 ... guesses.(2) Note that the rate of heat transfer by convection to the top surface of the rod must balance the rate of heat transfer by conduction to the sides and bottom of the rod.NOTE TO INSTRUCTOR: ... m5,9.+−==(2)The system of 9 finite-difference equations is first written in the form of Eqs. (1) or (2) and thenwritten in explicit form for use with the Gauss-Seidel iteration method of solution; see...
... steady-state temperature.(2) Both the FEHT and IHT methods ofsolution give identical results. Their steady-state solutionsagree with the result of an energy balance on a time interval basis yielding ... form of the FDEs for theinterior nodes. Use space and time increments of 37.5 mm and 1.2 s, respectively, for a 17-nodenetwork. For the surface node 00, use the FDE derived in Section 2 of the ... exactanalytical solution. This difference represents an error of -1% ( -1 °C / (120 – 20 ) °C x 100). At thex = 150 mm location, the difference is about -0.4 °C, representing an error of –1.5%....