... 0 .34 ($10M) + 0 .35 ($5M) + 0 .38 ( $3. 333 M) = $6,416,667
Average tax rate = $6,416,667 / $18 ,33 3 ,33 4 = 35 %
The marginal tax rate on the next dollar of income is 35 percent. For corporate taxable ... Sales $5 ,39 0.00
COGS 1,658.00 COGS 1,961.00
Other expenses 39 4.00 Other expenses 34 3.00
Depreciation 692.00
Depreciation 7 23. 00
EBIT $2,078.00 EBIT $2 ,36 3.00
Interest 32 3.00
Interest 38 6.00
... [ .36 36(.28 13) ] / [1 – .36 36(.28 13) ]
Sustainable growth rate = .1 139 or 11 .39 %
If the company grows at the sustainable growth rate, the new level of total assets is:
New TA = 1.1 139 ($164,000)...
... 1 .39 (Continued)
where
()
2
A DL 0.07 m 0.15 m 0. 033 m .
s
== ì = Hence,
()() ( )
22 2824444
q 4W/m K 0. 033 m 20 C 0.8 0. 033 m 5.67 10 W/m K 31 3 2 93 K
= +ì ìì ⋅ −
q 2.64 W 3. 33 ... )
()
2
224444
ss
8
7 833 W 6 0 .30 m 200W / m K T 30 3K 0.8 5.67 10 W / m K T 30 3 K
=+ìì
A trial-and-error solution yields
s
T 37 3K 100 C≈=°
<
COMMENTS:
(1) For T
s
≈
37 3 K, q
conv
... m K 133 .3W m
dx L 0 .30 m
−−
−
′′
=− = = ⋅ =
. (1)
22
xx
q q A 133 .3W m 20m 2667W
=ì= ì =
. (2) <
Combining Eqs. (1) and (2), the heat rate q
x
can be determined for the range of ambient...
... that
()
()()
()
(
)
s,i s,o
44
3os,o ,o s,o sur
21 32
st ins
2T T
2r h T T T T
nr/r nr/r
kk
π
πεσ
∞
−
=−+−
+
()
()
()
()
()
2824444
3
3
284 832 3K
2 r 6 W / m K 32 3 30 0 K 0.20 5.67 10 W / m K 32 3 30 0 K
nr/0.18n ... lens:
()
t,wo
23
2 -3
331 11
Rm
4 0 .35 W/m K 10.2 12.7
10
12W/m K4 10.2 10 m
=+
ì
ì
()
2
2 -3
3
191.2 K/W+ 13. 2 K/W+246.7 K/W=451.1 K/W
6 W/m K4 12.7 10 m
+=
ì
With lens:
t,w
3
3111
R 191.2 K/W+ 13. 2 ... .
∞
=− −
(4)
From Eqs. (1) and (3) ,
3
1
i
Cqr/3k.=−
From Eqs. (1), (2) and (4)
33
ii
2
2
o
o
33
ii
2
2
o
o
qr qr
h
CT
k3rk
3kr
qr qr
CT.
3r k
3hr
∞
∞
−=− +−
=−+
Hence,...
... Contents
3A .3 Mass Balance 111
3A.4 Energetic Factors 116
3A.5 Settling and Resuspension 1 23
3B.1 Chemical Reactions 129
3B.2 Chemical Equilibrium 136
3B .3 Hydrolysis 140
3B.4 Redox 141
3B.5 ... Ecotoxicologicai Models 31 3
8.1 Classification and Application of Ecotoxicological Models 31 3
8.2 Environmental Risk Assessment 31 6
8 .3 Characteristics and Structure of Ecotoxicological Models 32 6
8.4 An ... Wetland Model 30 3
Problems 31 1
30
Chapter 2 Concepts of Modelling
From these considerations, recommendations can now be drawn up about the
feasibility of carrying out a calibration of a model...
... student using this Manual, you are using it without permission.
Page 12 - 3
PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual
may be displayed, ... are using it without permission.
Page 13 - 3
PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual
may be displayed, reproduced or distributed ... using it without permission.
Page 25 - 3
PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual
may be displayed, reproduced or distributed...
... a
rules -of- inference version.
Contents vii
A For Further Reading 37 3
B The SLLGEN Parsing System 37 9
B.1 Scanning 37 9
B.2 Parsing 38 2
B .3 Scanners and Parsers in SLLGEN 38 3
Bibliography 39 3
Index ... Types 292
8 .3 Module Procedures 31 1
9 Objects and Classes 32 5
9.1 Object-Oriented Programming 32 6
9.2 Inheritance 32 9
9 .3 The Language 33 4
9.4 The Interpreter 33 6
9.5 A Typed Language 35 2
9.6 The ... We know that 0
∈ S. Therefore 3 ∈ S,since (3 3) = 0and
0
∈ S. Similarly 6 ∈ S,since(6− 3) = 3and3∈ S. Continuing in this way, we
can conclude that all multiples of3 are in S.
What about other...