fill each blank with one sui ble word only
Strategies to deal with non - equivalence at word level in translation
Ngày tải lên :
10/04/2013, 10:37
... much younger than oneself That shows that one has less seniority than one' s “anh họ” or “chị họ” and more seniority than one' s “em họ” English, in comparison, only has the one word "cousin" to ... no Vietnamese general word correspond with the verb “wear” in all cases But depend on each, translator need to use a different Vietnamese word which is suitable and applicable in that context In ... accordance with Confucian There is no equivalent word in English In case one has 30 to translate it into English, he might have to use the word “gentleman” but it does not truly match with each other...
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Báo cáo khoa học: "Domain Adaptation with Active Learning for Word Sense Disambiguation" pdf
Ngày tải lên :
08/03/2014, 02:21
... line, money, need, number, order, part, power, society, term, use, value.2 For each noun, all the BC examples are used as out-of-domain training data One- third of the WSJ examples for each noun ... concern with and curiosity about someone or something” In the WSJ part of the DSO corpus, the noun interest has a different predominant sense with the meaning “a fixed charge for borrowing money”, ... Hence, we select the subset of DSO nouns that have at least one synset labeled with any of these domain labels: commerce, enterprise, money, finance, banking, and economy This gives a set of 21...
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Báo cáo khoa học: "An Algorithm for Unsupervised Transliteration Mining with an Application to Word Alignment" ppt
Ngày tải lên :
23/03/2014, 16:20
... mining from parallel corpora, and word alignment using a word aligner with a transliteration component On the WIL data sets, we compare our fully unsupervised system with the semi-supervised systems ... possible word pairs from the source and target words in the seed data and extract the ones which are not transliterations but have a common substring of some minimal length They use the phrase table ... extract a list of word pairs from a word- aligned parallel corpus using GIZA++ The extracted word pairs are either transliterations, other kinds of translations, or misalignments In each iteration,...
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Báo cáo hóa học: "Research Article A Fourth-Order Boundary Value Problem with One-Sided Nagumo Condition" ppt
Ngày tải lên :
21/06/2014, 05:20
... solution of problems 1.1 and 1.2 An Example The following example shows the applicability of Theorem 3.1 when f satisfies only the onesided Nagumo-type condition 12 Boundary Value Problems Example ... Then f satisfies condition 3.2 and the one- sided Nagumo-type condition with hE |x3 | in E 1, Therefore, by Theorem 3.1, there is at least one solution u t of Problem 4.1 and 4.2 such that, for every ... and location results for problems 1.1 and 1.2 can be obtained Boundary Value Problems Theorem 3.1 Suppose that there exist lower and upper functions α t and β t of problems 1.1 and 1.2 , respectively...
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báo cáo hóa học:" The asymptotics of eigenvalues and trace formula of operator associated with one singular problem" potx
Ngày tải lên :
21/06/2014, 17:20
... The asymptpotics of eigenvalues and trace formula of operator associated with one singular problem Nigar M Aslanova Institute of Mathematics and Mechanics of NAS of Azerbaijan, Baku, ... trace of this operator Introduction Let H be a separable Hilbert space with a scalar product (., ) and norm Consider in L2 ((0, ∞) , H) the problem l[y] ≡ −y (x) + xy(x) + Ay(x) + q(x)y(x) = λy(x) ... we will need further Lemma 1.1 Equation (1.6) has only real roots Proof Suppose that z = iα, α ∈ R, α = Then the operator associated with problem −yk (x) + xyk (x) = z yk (x) (1.7) yk (0) = (1.8)...
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báo cáo hóa học:" The asymptotics of eigenvalues and trace formula of operator associated with one singular problem" doc
Ngày tải lên :
21/06/2014, 20:20
... The asymptpotics of eigenvalues and trace formula of operator associated with one singular problem Nigar M Aslanova Institute of Mathematics and Mechanics of NAS of Azerbaijan, Baku, ... trace of this operator Introduction Let H be a separable Hilbert space with a scalar product (., ) and norm Consider in L2 ((0, ∞) , H) the problem l[y] ≡ −y (x) + xy(x) + Ay(x) + q(x)y(x) = λy(x) ... we will need further Lemma 1.1 Equation (1.6) has only real roots Proof Suppose that z = iα, α ∈ R, α = Then the operator associated with problem −yk (x) + xyk (x) = z yk (x) (1.7) yk (0) = (1.8)...
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fill in blank ( 3 )
Ngày tải lên :
10/07/2014, 14:00
... while And touch me with your smile And what can I say to make you mine To reach out for you in time Oh my pretty pretty boy I (9)………… youlove you Like I never ever loved no one( 10) …………… byou ... while And touch me with your smile And what can I say to make you mine To reach out for you in time Oh my pretty pretty boy I (9)………… youlove you Like I never ever loved no one( 10) ……………byou Pretty ... Right from my bedroom wall I lie awake at night See things in black and (1)……………lack and white I've only got you inside my mind You know you have made me blind I lie awake and pray That you will(2)...
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Báo cáo toán học: "Necklace bisection with one cut less than needed" pptx
Ngày tải lên :
07/08/2014, 15:22
... and only if i ∈ Dj That is, if we are short of just one cut and it is indeed not possible to make a fair division of the beads then the two thieves can agree on two arbitrary disjoint nonempty ... number of beads in each of k colors If there is no bisection using at most k − cuts and resulting in a fair bipartition of the beads, i.e., one that puts exactly half of the beads of each color into ... direction of the ith coordinate axis We consider these 2(h + 1) vertices to be in one- to -one correspondence with the sets ±Ai so that v j corresponds to Aj and −v j corresponds to −Aj The vertices...
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Markoff maps and SL(2,C) characters with one rational end invariant
Ngày tải lên :
16/10/2015, 15:35
... regions further down, we just concatenate left word with right word Inductively we will obtain the word assignment” of all regions This gives a one- one correspondence between all complementary ... we only concern about the angular motion, without loss of generality, we may assume the circumference of a unit disk We divide it into intervals of arc length /2 with a possible remainder with ... Z −1 W, ZW ) or e = (Z, W ; ZW −1 , ZW ) for certain suitable word assignment Z and W In fact, any two adjacent regions will have their word assignment as a pair of generators of π We will now...
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