... benzen là: A. (1); (2) và (3). B. (2); (3) và (4). C. (1); (3) và (4). D. (1); (2) và (4). Câu 11: Chất cấu tạo như sau có tên gọi là gì ? CH3 CH3 A. o-xilen. B. m-xilen. C. p-xilen....
... Gò Vấp , tháng 11 năm 2 011 PHỤ LỤCTrang1. Tên chuyênđề 22. Tóm tắt 23. Giới thiệu3.1. Hiện trạng 23.2. Giải ... VẤP******BÁO CÁO CHUYÊN ĐỀTên chuyên đề:“Phương pháp giải nhanh một số bàitậpHóahọclớp11 bằng phươngtrình ion thu gọn và phương trình bảo toàn electron”Giáo viên: Hồ Quang Diệu Tổ: ... phương trình ion thu gọn :Tính tổng sổ mol H+ :2 42 4( ) ( )1. 2. 1.0,2.0,015 2.0,4.0,01 0, 011 HCl H SOH H HCl H H SOn n n n n mol+ + +Σ = + = + = + =1. 1.0,4.0,025 0,01KOHOHn n mol−=...
... CH2=CH-CH2-CH3. D. CH3-CH=CH-CH3. 56.09b Câu 38: Cho các hợp chất sau: (a) HOCH2-CH2OH. (b) HOCH2-CH2-CH2OH. (c) HOCH2-CH(OH)-CH2OH. (d) CH3-CH(OH)-CH2OH. (e) CH3-CH2OH. (f) ... 3. C. 4. D. 5.46.Cd07Câu 45: Cho các chất có công thức cấu tạo như sau: HOCH2-CH2OH (X); HOCH2-CH2-CH2OH (Y); HOCH2-CHOH-CH2OH (Z); CH3-CH2-O-CH2-CH3 (R); CH3-CHOH-CH2OH ... D. 4.30.Cd11Câu 20: Cho a lít dung dịch KOH có pH = 12,0 vào 8,00 lít dung dịch HCl có pH = 3,0 thu được dd Y có pH =11, 0. Giá trị của a là A.1,60. B. 0,80. C. 1,78. D. 0,12.31.Cd11Câu 35:...
... + HSO4-Câu 34. Cho phương trình hóahọc của phản ứng ở dạng ion thu gọn: http://kinhhoa.violet.vn 11 Câu 1. Phương trình ion rút gọn của phản ứng cho biết : A. Những ion nào tồn tại trong ... NH3 và 11, 2 lít khí CO2 .Tính % m của hỗn hợp muối ban đầu .(V các khí đo ở đkc)II.2.15.* Cho dd Ba(OH)2 đến dư vào 50 ml dd A có chứa các ion NH4+, SO42- ,NO3-.Có trong 11, 65g ... 4A 5B 6B 7A 8D 9A 10B11C 12C 13C 14D 15C 16D 17C 18C 19C 20C21C 22A 23C 24B 25C 26B 27A 28C 29C 30D31A 32D 33B 34A 35D 36B 37B 38A 39A 40B41D 42C 43A 44Dhttp://kinhhoa.violet.vn12 c) S2-...
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 ... i trên c AC sao cho NC = 2NA. G K là trung i MN. a) CMR : 11 46AK AB AC. b) D là trung i BC. CMR : 11 43KD AB AC 53) Cho tam giác ABC i I sao cho : 20IA ... A1B1+ A2B2+ + AnBn= 0 33) Cho ngũ giác đều ABCDE tâm O Chứng minh : OOEODOCOBOA 34) Cho lục giác đều ABCDEF có tâm là O . CMR : a) OA+OB+OC+OD+OE+OF=0...
... với dd HCl cho 112 ml khí CO2 (đktc). Xác định CTPT của muối cacbonat?Bài 11: Cho 9,85g muối cacbonat của kim loại hoá trị II tác dụng hết với dd H2SO4 loãng, dư thu được 11, 65g muối Sunfat. ... hoà tan hết 8,8g hh A ở trên?28 c. Tính nồng độ Mol của các chất có trong dd sau trung hoa ?Baøi 27: hoa tan 1,6g CuO trong 100g dd H2SO4 20%.a. Bao nhieâu gam oxit tham gia pư?b. Bao ... -> D + C + H2O. Tìm các chất ứng với các chữ cái A, B, C, D, E, X, Y, Z và viết các PTPƯBài 11: Viết ptpư cho những biến đổi hoáhọc sau:a. Na -> NaOH -> Na2SO4 -> NaOH ->...
... mol CO2 sinh ra) thì khối lượng muốikhan thu được sẽ tăng (71 – 60) = 11 gam.Mà nCO2 = 0,03 mol => m = 10 + 0,03 .11 = 10,33 (gam).Bài 2 (Câu I.2/QGHN 98):Để m gam phoi bào sắt (A) ngoài ... tương tự như các cách đã trình bày trong bàitập 2 ta sẽ thu được 6 cách lớn với kết quảlà: m = 11, 2 gam. Sv. Lê Phạm Thành – K52 CLC HóaHọc ĐHSP Hà Nội, 2005Bài tậpchuyênđề “Bài tập nhiều...
... hợp? Đs:%CH3OH =11, 07; %C2H5OH=23,88Bài 5 :Đốt cháy 5,8g chất hu cơ Ata thu đợc 2,65g Na2CO3, 2,25g H2O và 12,1g CO2TRƯỜNG THPT TÂN CHÂU BÀITẬP TỰ LUẬN HÓA HỮU CƠ 11 GV: MAI VĂN ... NaOH 10% (D=1 ,11 g/ml). Xác định thành phần hỗn hợp Bài 14:a/Từ đá vôi và các chất vô cơ cần thiết hÃy điều chế phenol và axit picric b/Axit benzylic từ phenol và ngợc lại ANĐEHiT Bai 1:Cho 0,87(g) ... định CTPT của E Đs:C3H5CHO; m=90g; E:C3H5COOC2H5Bài 13: Cho 6,16g 1 andehit A là đồng đẳng của andehit fomic tác dụng hết với Cu(OH)2 trong dd NaOH thu đ-ợc 20,16g kết tủa đỏ gạch...
... KOH, thì thấy khối lượng bình 1 tăng lên 0 ,117 g, bình 2 tăng thêm 0,396 g. Ở thí nghiệm khác, khi nung 1,35 g hợp chất A với CuO thì thu được 112 ml (đktc) khí nitơ. Tính thành phần phần ... mỗi nguyên tố trong HCHC. Bài 2. Đốt cháy hoàn toàn 7,75 g vitamin C (chứa C, H, O) thu được 11, 62 g CO2 và 3,17 g H2O. Xác định % khối lượng mỗi nguyên tố trong phân tử vitamin C. Bài ... dầu chanh người ta tách được chất limonen thuộc loại hiđrocacbon có hàm lượng nguyên tố H là 11, 765%. Hãy tìm CTPT của limonen, biết tỉ khối hơi của limonen so với heli bằng 34. Bài 8. Đốt...
... Khi [Al(OH)4]- = 10-2M, Al(OH)3 tan hoàn toàn : 13,9 11, 9210[H ] 1010 tức pH = 11, 9 IV. Ảnh hưởng của phản ứng tạo phức lên độ tan 1. Ligand tạo phức khác ... L4 Vd2 : Tính độ tan MnS trong nước, biết TMnS = 10 -11 . Giải MnS + H2O ˆ ˆ ˆ†‡ ˆ ˆˆ Mn2+ + HS- + OH- 2 222 11 1412MnS w13a2[Mn ][S ][H ][OH ][HS ]K [Mn ][HS ][OH ... dịch chứa Cd2+ và Sn2+ với nồng độ đầu đều bằng 0,1M. Biết TZnS = 10-21, TMnS = 10 -11 , TCdS = 10-28, TSnS = 10-26. Giải Chemist2408 – DH KHTN TP.HCM – Hóa Phân Tích –...
... với dd HCl cho 112 ml khí CO2 (đktc). Xác định CTPT của muối cacbonat?Bài 11: Cho 9,85g muối cacbonat của kim loại hoá trị II tác dụng hết với dd H2SO4 loãng, dư thu được 11, 65g muối Sunfat. ... có chứa 60g NaOH. Tính khối lượng muối natri điều chế được?26 GV: Trương Thế ThảoBaøi 22: hoa tan hoa n toaøn 18g một kim loại M cần dùng 800ml dd HCl 2,5M. kim loại M là kim loại nào?Bài ... HCl rồi sau đó cô cạn dd thu được 59,4g muối khan. Tính thể tích khí H2 sinh ra?Baøi 44: Hoa tan hoa n toaøn 1,68g kim loại M có hoá trị II bằng 100ml dd H2SO4 0,4M. để trung hoà lượng...