... order of difficulty 55 The success of the play was due toA < /b> the actors and how it was produced Bthe acting and the production Cthe actors and its production D how they acted and the production ... his artistic but his academic ability B for both his academic ability as well as his artistic C because of his academic and artistic ability D as resulting of his ability in the art and the academy ... meaning to _ A < /b> questioned B repeated C indicated D exaggerated Question 50 According tothe passage, what does a < /b> constricted and harsh voice indicate? A < /b> Lethargy B Depression C Boredom D Anger Mark...
... Whether C Despite D Much as "What happened?" A < /b> What did you today? B I had a < /b> bad day Mark the letter A,< /b> B, C, orD on your answer sheet toindicatetheword that differsfromtherest in the ... DCA < /b> DDBA < /b> ABCDDBBCA < /b> ABDA < /b> Mark the letter A,< /b> B, C, orD on your answer sheet toindicatetheword that differsfromtherest in the position of themainstress in each of the following ... America C Ceremonies and rituals of American Indians DThe way of life of American Indian tribes in early North America Question 72 According tothe passage, the Hopi and Zuni typically built their...
... reproduced B replaced C removed D remained Read the following passage and mark the letter A < /b> BCorD on your answer sheet toindicatethe correct answer Unconscious facial expressions and “body language” ... because the weather was so bad CThe bad weather was the reason that made our excursion to London have been fallen over D Our plans for an excursion have fallen away because the weather was bad ... sensory memory Cthe short-term memory Dthe long-term memory Read the following passage and mark the letter A < /b> B. CorD on your answer sheet toindicatethe correct word for each of the blanks The first...
... hard.” 21 A < /b> wealth B unhealthy C richness D wealthy 22 A < /b> journal B report C journalist DB decided C decisive D decision newspaperman 23 A < /b> decide 24 A < /b> luck unlucky B lucky C unluck D 25 A < /b> happy ... blank Emma Harte, in Barbara Taylor Bradford’s novel, was a < /b> poor lonely girl who became the … (21) owner of an international chain of stores Like the woman she writes about, Ms Bradford is beautiful ... please? A < /b> collect B take C obtain D fetch 10 he is just a < /b> nice,………… Person A < /b> usual B ordinary C typical D common 11 You………… marvellous in that dress A < /b> look B seem C appear D become 12 We had better…………...
... American C function C communication C hobby C hot C horses C floor C cake C month C soon C child C Italian C pay C Australia C China C American C function C communication C England C American C international ... D hat D abandon D train D reminisce D- disappear D near D lecturer D borrow D physicist D basic D medicine D American D return D second D sponsor D digestion D entered D battle binh bac72@gmail.com ... thought D cherry D button D reach D sentence D activity D professor D lead D food D decided D beer D far D lean D mild D truth D bus D hour D opened D perhaps D marshes D tropical D habitat D killed...
... Danh m c tài liệu Khoá h c A:< /b> Phát triển b n vững Nhận th c Môi trờng B i - Ccđc điểm đa < /b> lý, d n c sinh thái lu v c sông Mê C ng B i - Những hoạt động th c tiễn không b n vững lu v c sông ... QLTN&MTT c Hiệu B i - Chính sách c ng cB o vệ Môi trờng B i - Cc công c quản lý tài nguyên n c tổng hợp (IREM) th c tế Khoá h c D: Thủ t c Đánh giá T c động Môi trờng Quyết định B i - Giới ... triển b n vững Uỷ hội sông Mê C ng Khoá h c B: Giới thiệu Khoa h c Môi trờng lu v c sông Mê C ng B i - Định ngh a < /b> môi trờng lu v c sông Mê C ng B i - Giới thiệu khái niệm khoa h c hệ sinh thái B i...
... (2002), a < /b> brand is a < /b> distinguishable symbol of origin and an assurance of performance 21 Conclusively, a < /b> brand can be said to be a < /b> symbol of all facts associated with a < /b> product and service A < /b> brand commonly ... p.39) defined Brand loyalty as the attachment that a < /b> customer has toa < /b> brand” It can also be seen as consumer’s preference to purchase a < /b> particular brand in a < /b> product class and this could be as a < /b> ... brand can be defined as a < /b> name, logo, symbol and identity ora < /b> trademark Prasad and Dev (2000) also states that a < /b> brand can be seen to include all tangible and intangible attributes that a < /b> business...
... VĂN (b ng A,< /b> B, C, DB) Tỉnh N .A < /b> năm h c 08 - 09 MễN NG VN BNG BC u 1(6,0 im) S cu th bt c ngh gỡ cng l mt s bt lng (Nam Cao) Suy ngh ca anh, ch v ý kin trờn C u ( 6,0 im) Cm nhn ca anh, ch v ... VN BNG C Cõu 1(6,0 im) S cu th bt c ngh gỡ cng l mt s bt lng (Nam Cao) Suy ngh ca anh, ch v ý kin trờn C u ( 6,0 im) Cm nhn ca anh, ch v hỡnh nh ngn ốn ca ch Tý truyn Hai a < /b> tr (Thch Lam) C u ... khỏng chin, c ch mng v d n tc PHAN ANH C NG Đề - Đáp án thi HSG VĂN (b ng A,< /b> B, C, DB) Tỉnh N .A < /b> năm h c 08 - 09 - C i tụi th hin s gn b , ho nhp gia nhõn d n vi c ch mng, mang tm v c ln lao, cao p...
... delete the English words and asks Ss to write them again -Read them carefully WHILE READING: (15ms) TASK 1: GAP-FILLING -Read the passage quickly and stop at the lines that contain these words to ... and decide whether the statements provided are true or false -Before listening, T asks Ss to read all statements to understand and underline key words -Work individually - Speak aloud the new words ... ->were for all Subjects Practice : exercise 3(textbook) Put the verbs into the correct form PRODUCTION: Matching game -T asks Ss to read the If-clause in the left column and themain clause in the...
... SH ^ PD ị SH ^ ((PQCD) ị VS PQCD = SPQCD SH = 3 ãC th d ng c ng thc t s th tớch: ỡVS.PQC SP SQ 2 4 = = ị VS.PQC = VS ABC = a < /b> ù 27 10 ù VS ABC SA SB 3 ị VS PQCD = VS PQC + VS PCD = a < /b> 27 ... trỡnh chun C u VI .a:< /b> 1) C i xng vi A < /b> qua ng thng d ị C( 3; 1) B, D ẻ d AB = AD = ị B( 2; 1), D( 6; 5) ợ r r a < /b> ^ n r r r ộ 2) E ẻ (d2 ) ị E(3; 7; 6) rV rP ị aV = nP , ad ự = -4(1;1; -1) ị (D) : ỷ aV ... , D) = ù ộ a < /b> = 2, b = -1, c = -10 ộ D : x - y - 10 = Gi s (D) : ax + by + c = (c 0) T: ị a < /b> = 1, b = 2, c = -10 ị D : x + y - 10 = ở ùcos (d , D) = ợ uuu r uuu r 2) Ly B ẻ (d1 ), C ẻ (d2 ) T : AB...
... SD, Q = BM ầ AD ị P l trng tõm DSCM, Q l trung im ca MB ã VMDPQ VMCNB = MD MP MQ 1 = = ị VDPQCNB = VMCNB MC MN MB 6 ã Vỡ D l trung im ca MC nờn d ( M ,(CNB)) = 2d (D ,(CNB)) ị VMCNB = 2VDCNB ... = 2VDCNB = VDCSB = VS ABCD ị VDPQCNB = VSABNPQ 7 VS ABCD ị VSABNPQ = VS ABCD ị = 12 12 VDPQCNB C u V: T gi thit x + y + z2 = ị < x , y, z < ã p dng BT C si cho s dng: x ,1 - x - x ta c: Trn ... b2 + c 0) r r ã Vỡ d è (P) nờn ud ^ nP ị a < /b> - b + c = b = a < /b> + c (ã ) ãd , D = 450 a < /b> + b + 2c 2 a < /b> +b +c = (1) 2 (a < /b> + b + c )2 = 9 (a < /b> + b2 + c ) c = 1 4c2 + 30 ac = ở1 5a < /b> + 7c = ã Vi c = 0: chn...
... VKMCAND, V2 = VKBB C MAA D N ED.SD ADN = a3< /b> 7 29 EK EM EC a < /b> = = ị V1 = VKMCAND = VEAND = a3< /b> = a3< /b> , V2 = Vhlp V1 = 8 36 36 EA EN ED ã Vhlp = a3< /b> , ã VEKMC VEAND ị VEAND = V1 = V2 29 C u ... C u VII .a:< /b> PT -1 ờz = ởz = -1 ở( z + 1) = z = i + Theo chng trỡnh nõng cao C u VI .b: 1) V CH ^ AB, IK ^ AB AB = ị CH = 2SD ABC AB = ịIK = 1 Gi s I (a;< /b> 3a < /b> 8) ẻ d CH = a < /b> = Phng trỡnh AB: ... - ữdx = x + - ln x + x + ỷ ỗ ữ x +1 ứ ố x +1 = + ln ( + ) - ln ( + ) C u IV: Gi E = AK ầ DC, M = IE ầ CCÂ, N = IE ầ DDÂ Mt phng (AKI) chia hỡnh lp phng thnh hai a < /b> din: KMCAND v KBB C MAA D N...
... 1 1 Ta c : + ; + ; + a < /b> + bb + ca < /b> + 2b + cb + cc + a < /b> a + b + 2c c + a < /b> a + b 2a+< /b> b+ c 2 Mt kh c: = 2a < /b> + b + c + - 4a < /b> - 2b - 2c 2a < /b> + b + c 2a < /b> + b2 + c + a < /b> + 2 (a < /b> - 1) + (b - 1) + (c - 1) ... 2b + c + a < /b> b + 2c + a < /b> + bc + 1 4 T ú suy ra: + + + + a+< /b> bb +c c +a < /b> a +7 b +7 c +7 ng thc xy v ch a < /b> = b = c = II PHN T CHN Theo chng trỡnh chun C u VI .a:< /b> 1) Gi A1< /b> , A2< /b> ln lt l im i xng ca A < /b> qua ... thng d: y = -16 ùz = 32 ợ C u VII .a:< /b> Phn thc a < /b> = 88, phn o b = 59 Theo chng trỡnh nõng cao C u VI .b: 1) Chỳ ý: d1 ^ d2 v DABC vuụng c n ti A < /b> nờn A < /b> c ch u d1 , d2 ị A < /b> l giao im ca d v ng phõn giỏc...
... = ịV ÂÂ = 2VMAÂ BC = a.< /b> a = BA < /b> MCN 3 2 ã Gi j l g c gia hai mt phng (A< /b> MCN) v (ABCD), P l trung im ca CD ị NP ^ (ABCD) SDMCN = S a2< /b> a2< /b> 6 , SDMCP = ị cos j = D MCP = 4 SDMCN x y z 1 + + ... lim xđ0 (cos2 x - 1)sin x x sin x.cos x = lim xđ0 - sin x x cos x = -1 C u IV: A< /b> MCN l hỡnh thoi ị MN ^ A< /b> C, DBÂMN c n ti B ị MN ^ B O ị MN ^ (A< /b> B C) ãV MAÂ BC 1 a < /b> a3 a3< /b> = MO.SD A< /b> BC = ịV ... n 2 Theo chng trỡnh nõng cao C u VI .b: 1) Tỡm c M(3; 0) ị MI = ị AB = ị AD = 2 Phng trỡnh AD: x + y - = Gi s A(< /b> a; a)< /b> (vi a < /b> < 3) Ta c AM = a < /b> = ị A(< /b> 2; 1) T ú suy ra: D( 4; 1), B( 5; 4), C( 7;...
... P)) = a < /b> ữ AB = 9 ứ 3 ố 2 AB = d (A,< /b> (P)) 2a < /b> - a < /b> + = a < /b> a < /b> = ị A(< /b> 3; 0; 0) 3 C u VII .a:< /b> Gi s s tho l: a1< /b> a2 a3< /b> a4 a5< /b> ị B Trn S Tựng a+< /b> 3 ã Nu a1< /b> = thỡ c : A7< /b> = 840 (s) 3 ã Nu a2< /b> = thỡ c : C6 A6< /b> = ... zứ C u V: ã Chỳ ý: Vi a,< /b> b > 0, ta c : Du "=" xy x = y = z = 1005 Vy MinP = 670 II PHN T CHN Theo chng trỡnh chun C u VI .a:< /b> 1) Gi s: AB: x y + = , AC: x + y 21 = Suy ra: A(< /b> 0; 3) BO ^ AC ... ị BO: x - y = ị B( 4; 7) ị BC: y + = uuu r uuu r r 2) Gi s A(< /b> a; 0; 0) ẻ Ox, B( 1+t; 2t; 2+2t) ẻ d AB = (t + - a;< /b> 2t; -2 + 2t ) AB ^ ud t = ổ 12 + a < /b> 2 (a < /b> + 3) 2a < /b> - 12 2 ; ; 2a2< /b> - 6a < /b> + d ( A,< /b> (...
... SD.SB = 2c + a < /b> = ị sin ã = Mt kh c, cos SDB SDB SD.SB ac 3 b 2c + a < /b> 1 abc VSDBC = SC.SSDB = SC.SD.SB.sin ã = SDB 6 2c + a < /b> V a < /b> a2 bc AD a < /b> M ASDB = ị VASDB = VCSDB = = VCSDB DC 2c 2c 12 2c + a < /b> ... S ASD AS.SD.sin 30 a < /b> Ta c : ị DA = DC ị SD = = = = 2c 2c + a < /b> CD SCSD 2c CS.SD uur uur uuu uur ổ 2cSA + aSC uur r 2c uur uur 2c abc ị SD.SB = ỗ SA.SB = ab.cos 600 = ữ SB = 2c + a < /b> 2c + a < /b> 2c + a < /b> ... a < /b> ố 2c + a < /b> ứ Trn S Tựng p x x - ũ tan e x dx + ũ tan e x dx = e 2 0 v SD = uur uur 4c SA + a < /b> SC + 4caSA.SC 2 2 ( 2c + a)< /b> 2 = a2< /b> c + a2< /b> c - a2< /b> c ( 2c + a)< /b> 2 = 3a < /b> c ( 2c + a)< /b> 2 ị SD = ac 2c + a < /b> abc uuu...
... 117p C u IV: Gi N = BM ầ AC ị N l trng tõm ca DABD K NK // SA (K ẻ SC) K KI // SO (I ẻ AC) ị KI ^ (ABCD) Vy VK BCDM = KI SBCDM KI CK CK CN = (1), DKNC ~ DSAC ị = (2) SO CS CS CA KI CN CO + ON CO ... + CO 2 a < /b> T (1) v (2) ị = = = = ị KI = SO = SO CA 2CO 2CO 3 a < /b> 3 Ta c : DADC u ị CM ^ AD v CM = ị SBCDM = ( DM + BC ).CM = a < /b> 2 Ta c : DSOC ~ DKIC ị Trn S Tựng a3< /b> KI SBCDM = x 3x2 x x C u V: Ta c ... Theo chng trỡnh nõng cao C u VI .b: 1) Ta cA < /b> = AD ầ AM ị A(< /b> 9; 2) Gi C l im i xng ca C qua AD ị C ẻ AB x -9 y+2 = x + 7y + = - -1 + Vit phng trỡnh ng thng Cx // AB ị (Cx): x + y - 25 = Ta tỡm...