... varied from -0 .4 to 1 .4 in increments of 0.1 and, since xB = − xA , the weight on asset is then varies from 1 .4 to -0 .4 This gives us 18 portfolios with weights (xA , xB ) = (−0 .4, 1 .4) , (−0.3, 1.3), ... investments in the two stocks The investor s problem is to decide how much wealth to put in asset A and how much to put in asset B Let xA denote the share of wealth invested in stock A and xB denote ... (0. 542 )(0.175) + (0 .45 8)(0.055) = 0.110, the variance of the tangency portfolio is σ2 = T ³ xT A ´2 ³ σ + xT A B ´2 σ + 2xT xT σ AB B A B = (0. 542 )2 (0.067) + (0 .45 8)2 (0.013) + 2(0. 542 )(0 .45 8)...
... the machine resistance, but increases conductor mass from 0.9 14 to 1. 64 kg and stator mass from 4. 12 to 6 .40 kg The increase in stator mass is in order to accommodate larger slots for the larger ... either mass or loss; 616 Introductionto the Design of Electric Machinery Pareto-Optimal Front 500 45 0 40 0 Loss, W 350 300 250 200 150 100 50 10 12 14 16 18 20 22 24 26 Mass, kg Figure 15.10-2. ... peak line -to- line voltage is essentially equal to the maximum value allowed for the dc voltage of 40 0 V It is also interesting to observe that the stator tooth, stator backiron, and rotor tangential...
... point (6 ,4) , P is P = ¥ 40 0 + ¥ 600 = 48 00 To plot the P = 48 00 contour, we plot the function 40 0x1 + 600x2 = 48 00 This contour is shown in Fig 3 -4 Step 6: Identification of Optimum Solution To locate ... pij x j ; i = to n (4. 16) j =1 Also, we can rewrite Eq (4. 14) as n Ê n ˆ  xi Á  pij x j ˜ ¯ i =1 Ë j =1 F (x ) = (4. 17) n  xi yi i =1 (4. 18) Substituting Eq (4. 16) into Eq (4. 17), F (x ) = ... cv3=[0 5]; const4=contour(x1,x2,g4,cv3,‘k’); clabel(const4) text(.25,20,‘g4’) const5=contour(x1,x2,g5,cv3,‘k’); clabel(const5) text(19,.5,‘g5’) text(1.5,7,’Feasible Region’) fv=[ 240 0, 48 00, 7200,...
... time Natural frequency 18.9 ksi 7.1 0 .43 8813 in.3 13.2 1515 Hz 10.5 ksi 14. 2 0. 548 8 in.3 13.2 1 840 Hz 44 .4 100 25.1 21.5 30 Chapter Figure 1.21: Physical prototypes of engine parts 1.2 and 1.3, ... employed in design modification to assign qualitative weighting factors to product performance and design changes e -Design employes a systematic and quantitative approach todesign modifications (for ... marketing ideas In addition, the prototypes can be given to potential customers for feedback, thus bringing customers into the design loop early in product development 1 .4. 2 CNC Machining The machining...
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... in ReactorDesign and Ideal Reactor Models 245 Selectivity and Optimization Considerations in the Design of Isothermal Reactors 317 10 Temperature and Energy Effects in Chemical Reactors 349 ... foundation for the practice of reactordesign The text is designed as a teaching instrument It can be used to introduce the novice to chemical kinetics and reactordesign and to guide him until he understands ... exposed to the concepts involved and has learned to use them in attacking reactordesign problems I believe that the subject of computer-aided design should be deferred to graduate courses in reactor...
... made in regard to graphical velocity analysis in Section 6.2 (p 244 ) apply as well to graphical acceleration analysis Historically, graphical methods were the only practical way to solve these ... asymptotes Centrodes of double-crank linkages will be closed curves Program FOURBARwill calculate and draw the fixed and moving centrodes for any linkage input to it Input the datafiles F06-l4.4br, ... centrode of link Read the diskfile F06-17bAbr into program FOURBARto animate that linkage with its coupler curve or centrodes Note in Figure 6- 14 (p 2 64) that choosing any location of instant center...