3 3 mathematical modeling of electrical systems

Mathematical Modeling of Biological Systems, Volume I pptx

Mathematical Modeling of Biological Systems, Volume I pptx

Ngày tải lên : 27/06/2014, 10:20
... kcat [Rec·PTEN]i [PIP3 ]i PTEN K M +[PIP3 ]i KM √D 3Ssite PIP2 (i)→PIP2 (j) √D 3Ssite PIP3 (i)→PIP3 (j) ′ ′ +[PIP2 ]i [PIP2 ]i − [PIP2 ] j + [PIP3 ]i − [PIP3 ] j + Table 3. 2 Physical and kinetic ... kdiss [Rec · PI3K]i V PIP2 Ns kass [PIP2 ]i [PTEN]cyto PIP2 Ns kdiss [PIP2 · PTEN]i PI3K·Rec(i)+PIP2 (i) → PI3K·Rec(i)+PIP3 (i) PI3K kcat [Rec·PI3K]i [PIP2 ]i PI3K PTEN·PIP2 (i)+PIP3 (i) → PTEN·PIP2 ... Acta, 11 83, 533 –5 43 (1994) Bendall, D.S., Manasse, R.S.: Cyclic photophosphorylation and electron transport Biochim Biophys Acta, 1229, 23 38 (1995) 10 Krendeleva, T.E., Kukarskih, G.P., Timofeev,...
  • 388
  • 246
  • 0
Modeling of Combustion Systems A Practical Approach 3 docx

Modeling of Combustion Systems A Practical Approach 3 docx

Ngày tải lên : 13/08/2014, 05:22
... g/cm3 = hp = 252.0 cal 1055 J 0.00890 cal/cm3 0. 037 3 MJ/m3 0.00 039 31 hp 0.2520 kcal/hr 0.2 931 W 0.2 93 MW 0.0 031 53 kW/m2 1. 730 W/m-K 5.67 W/m2-K 0.5556 cal/g 232 6 J/kg cal/g-°C 4187 J/kg-K 0.0 039 68 ... Btu 0. 239 cal W/sec 3. 968 Btu 1000 cal 4187 J 3. 968 Btu/hr 1.162 J/sec 0.1124 Btu/ft3 4187 J/m3 2.205 lb 0.00278 g/sec-cm 0.672 lb/hr-ft 0.062 43 lb/ft3 34 13 Btu/hr 1 .34 1 hp 660.6 kcal/hr 31 7.2 ... 62. 43 lb/ft3 0. 036 13 lb/in .3 33, 000 ft-lb/min 550 ft-lb/sec 641.4 kcal/hr 745.7 W in = 1J= kcal = kcal/hr = kcal/m3 = kg = kg/hr-m = kg/m3 = kW = 1 1 kW/m2 = kW/m2-°C = lb = lb/ft3 = 1 1 lbm/hr-ft...
  • 4
  • 303
  • 0
Mathematical modeling of transport phenomena in electrochemical energy storage systems

Mathematical modeling of transport phenomena in electrochemical energy storage systems

Ngày tải lên : 09/09/2015, 17:54
... à [ 23] [24] à àà à, [25, 26, 27, 28, 29, 30 , 31 , 32 ], [2, 3, 33 , 34 , 35 , 36 , 37 , 38 , 39 , 40, 41, 42, 43, 44, 45, 46, 47, 48], ... ( ) ; ; = , (3. 31) 3. 1 24  =  (1 ); (3. 32)  =  ; = (1 (3. 33) ) + ; = , , ( ) = ( ) (1 (3. 34) ) + ( ) ; = , , = ; (3. 35) (3. 36) ... (3. 18) (3. 19) 3. 1 22 = 0, = ; = ; = > > > > () <  = > > > >  () : (3. 20) (3. 21)  = 0 (,,) 3. 1.6 (3. 22) à, , = > > > > (, ) < > > > >0 : ; (3. 23) ...
  • 172
  • 347
  • 0
stochastic modeling of manufacturing systems advances in design, performance evaluation, and control issues - g. liberopoulos

stochastic modeling of manufacturing systems advances in design, performance evaluation, and control issues - g. liberopoulos

Ngày tải lên : 08/04/2014, 12:26
... Information Scheduling General Outsource Process Systems Control C11 I12 S 13 G14 O15 C21 I22 S 23 G24 O25 C31 I32 S 33 G34 O35 C41 I42 S 43 G44 I52 S 53 G45 Fig 10 Path through IBIS network In fact, ... University of Thessaly 38 334 Volos Greece E-mail: glib@mie.uth.gr J M Smith Department of Mechanical and Industrial Engineering University of Massachusetts Amherst, Massachusetts 010 03 USA E-mail: ... Okonomen 8: 39 039 6 16 Rittel H (1972b) Structure and usefulness of planning information systems Bedrifts Okonomen (8): 39 8401 17 Rittel H, Webber M (19 73) Dilemmas in a general theory of planning...
  • 364
  • 411
  • 0
Báo cáo hóa học: " Research Article A Variational Approach to the Modeling of MIMO Systems" docx

Báo cáo hóa học: " Research Article A Variational Approach to the Modeling of MIMO Systems" docx

Ngày tải lên : 22/06/2014, 19:20
... MIMO systems and a brief overview on the third generation (3G) of telecommunications In Section 3, we study the performances of MIMO systems dealing with 3G We first develop the modeling of MIMO ... conception of MIMO systems and the reduction of the cost of its implementation Notice by the way that great changes are envisaged to evaluate and migrate to third generation systems (3G) In the ... bits/sec/Hz [ 13] Figure A.1 shows the variation of capacity in terms of SNR for a SISO and SIMO systems For a MIMO channel, the capacity C of the system is given by the following general relation [ 13] :...
  • 10
  • 548
  • 0
Modeling of Combustion Systems A Practical Approach 1 pot

Modeling of Combustion Systems A Practical Approach 1 pot

Ngày tải lên : 13/08/2014, 05:22
... 131 63 12788 12757 12 935 12862 12771 12689 12821 12902 14198 15585 9 23 924 109 83 10956 865 862 132 57 132 58 9 73 971 984 968 957 958 958 957 952 948 864 957 1102 1201 33 06 33 08 32 84 33 17 33 51 33 51 33 42 ... 52. 13 72.24 31 .74 51.02 61.48 83. 09 105.66 104.96 1 03. 55 129.10 125.71 152.64 125.50 148.08 144.07 148 .33 152.06 171.75 167.61 170.48 1 73. 96 171. 83 198.09 199.07 35 .32 53. 02 32 .04 58. 43 34. 43 33. 65 ... 220.94 232 .84 261.74 31 . 23 45 .32 29.74 47.82 31 .84 29.90 29 .36 36 . 13 38.54 44 .34 48.45 66 .30 30 .28 46.72 50. 93 69.44 86 .34 89. 63 89.05 105.67 104.04 125.28 109. 23 125.48 120.51 124.92 129 .34 142.47...
  • 22
  • 402
  • 0
Modeling of Combustion Systems A Practical Approach 2 pptx

Modeling of Combustion Systems A Practical Approach 2 pptx

Ngày tải lên : 13/08/2014, 05:22
... 26.04 31 .5 36 .9 41.1 47.1 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 34 3. 25 3. 24 3. 21 3. 17 3. 14 3. 13 3.08 3. 04 2.978 2.897 2.814 2.749 2.651 19.56 24.20 33 .38 43. 77 49.56 53. 53 ... 1 03. 9 98 .3 10.80 13. 42 16.05 18.62 21.21 23. 73 24.98 26.26 28. 73 31.2 36 .1 38 .5 44 .3 50.1 55.6 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 67 3. 53 3.5 3. 47 3. 44 3. 4 ... 32 " 33 " 34 " 35 " 32 .0000 33 .0000 34 .0000 35 .0000 100. 53 1 03. 67 106.81 109.96 804 .3 855 .3 907.9 962.1 5.585 5.940 6 .30 5 6.681 36 " 37 " 38 " 39 " 36 .0000 37 .0000 38 .0000 39 .0000 1 13. 10 116.24 119 .38 ...
  • 17
  • 318
  • 0
Modeling of Combustion Systems A Practical Approach 4 doc

Modeling of Combustion Systems A Practical Approach 4 doc

Ngày tải lên : 13/08/2014, 05:22
... 3. 1972 3. 1757 3. 1546 3. 133 7 3. 1 130 146.0 147.0 148.0 149.0 150.0 131 .3 132 .3 133 .3 134 .3 135 .3 356 .31 35 6.84 35 7 .38 35 7.91 35 8. 43 328.4 32 9.0 32 9.5 33 0.1 33 0.6 865.2 864.8 864 .3 8 63. 9 8 63. 4 11 93. 6 ... 0.01792 3. 69 83 3.6695 3. 6411 3. 6 132 3. 5857 126.0 127.0 128.0 129.0 130 .0 111 .3 112 .3 1 13. 3 114 .3 115 .3 344.95 34 5.55 34 6.15 34 6.74 34 7 .33 31 6.4 31 7.1 31 7.7 31 8 .3 319.0 874.8 874 .3 8 73. 8 8 73. 3 872.8 ... 127 .3 128 .3 129 .3 130 .3 3 53. 59 35 4.14 35 4.69 35 5. 23 355.77 32 5.5 32 6.1 32 6.7 32 7 .3 327.8 867.5 867.1 866.6 866.2 865.7 11 93. 1 11 93. 2 11 93. 3 11 93. 4 11 93. 5 0.018 03 0.01804 0.01805 0.01805 0.01806 3. 1972...
  • 23
  • 308
  • 0
Modeling of Combustion Systems A Practical Approach 5 docx

Modeling of Combustion Systems A Practical Approach 5 docx

Ngày tải lên : 13/08/2014, 05:22
... 1 .38 3 1 .37 2 1 .36 3 1 .35 6 1 .35 0 1 .34 5 1 .34 1 1 .33 7 1 .33 3 1 .33 0 1 .32 8 1 .32 5 1 .32 3 1 .32 1 1 .31 9 1 .31 8 1 .31 6 1 .31 5 1 .31 4 1 .31 3 1 .31 1 1 .31 0 1 .30 3 1.296 1.289 1.282 6 .31 4 2.920 2 .35 3 2. 132 2.015 1.9 43 1.895 ... 2.7 2.8 2.9 3. 0 3. 1 3. 2 3. 3 3. 4 3. 5 3. 6 3. 7 3. 8 3. 9 0000 039 3 07 93 1179 1554 1915 2258 2580 2881 31 59 34 13 36 43 3849 4 032 4192 433 2 4452 4554 4641 47 13 4772 4821 4861 48 93 4918 4 938 49 53 4965 4914 ... 11.6 12 .3 13. 1 13. 8 14.6 13. 2 14.0 14.8 15.7 16.5 16 .3 17.2 18.1 19.0 19.9 20 .3 21 .3 22 .3 23. 3 24 .3 24.9 26.0 27.1 28.2 29 .3 29.6 30 .8 32 .0 33 .2 34 .4 32 .7 33 .9 35 .2 36 .4 37 .7 35 .5 36 .8 38 .1 39 .4...
  • 8
  • 276
  • 0
Modeling of Combustion Systems A Practical Approach 6 pdf

Modeling of Combustion Systems A Practical Approach 6 pdf

Ngày tải lên : 13/08/2014, 05:22
... Representations TABLE F.4 Base Equivalents 10 10 11 12 13 14 15 16 Example 3. 1 16 A B C D E F 10 Base 10 11 12 13 14 15 16 17 20 2 10 11 12 13 20 21 22 23 30 31 32 33 100 10 11 100 101 110 111 1000 1001 1010 ... = 12, D = 13, E = 14, and F = 15 So a number like 234 .5 equals EA.816 using the process already shown But conversion of EA.816 to related bases is much simpler: EA.816 = 35 2.48 = 32 ,22.24 = 11,0010,1011.12 ... pattern: base = 22, so grouping 1110.112 in groups of two gives 11,10.112 = 32 .34 , since 112 = 34 and 10 = 24 For bases less than 10, we use a subset of the base 10 numerical symbols For bases greater...
  • 4
  • 370
  • 0
Modeling of Combustion Systems A Practical Approach 7 pot

Modeling of Combustion Systems A Practical Approach 7 pot

Ngày tải lên : 13/08/2014, 05:22
... 614 Modeling of Combustion Systems: A Practical Approach Usually, one defines a reaction coordinate known as the ... N k N k ,0 xk = (G.5) where Nk,0 is the starting number of moles of species k, and Nk is the concentration at some particular conversion of interest Thus, Nk,0 is a constant and Nk is a variable ... ∑N k ˆ V where ∑N k = P RT (G.12) are the total moles of the reaction This gives ˆ RT V= P We may also write ∑N k ∑N (G. 13) k as a function of conversion: ∑ N = ∑ (1 − x ) N k k k ,0 (G.14) Typically,...
  • 3
  • 271
  • 0
Modeling of Combustion Systems A Practical Approach 8 doc

Modeling of Combustion Systems A Practical Approach 8 doc

Ngày tải lên : 13/08/2014, 05:22
... 618 Modeling of Combustion Systems: A Practical Approach Please note that P and R (italicized) are the pressure ... temperature effects shown in Equation H .3 In particular, note that Ky is neither necessarily dimensionless nor independent of pressure, except in the case that the number of moles remains invariant © 2006 ... products and reactants, respectively For constant-pressure systems such as combustion, we may also incorporate the pressure dependence as part of the equilibrium constant, as ⎛ RT ⎞ Ky = Ky ⎜ ⎠ ⎝ P...
  • 2
  • 328
  • 0
Modeling of Combustion Systems A Practical Approach 9 pdf

Modeling of Combustion Systems A Practical Approach 9 pdf

Ngày tải lên : 13/08/2014, 05:22
... a31 a41 a12 a22 a32 a42 a12 + a31 a22 a42 a 13 a 23 a 33 a 43 a 13 a 23 a 43 a14 a22 a24 = a11 a32 a34 a42 a44 a12 a14 a24 − a41 a22 a44 a32 a 23 a 33 a 43 a 13 a 23 a 33 a24 a12 a34 − a21 a32 a44 a42 a 13 ... smaller steps: a11 a21 a31 a12 a22 a32 a 13 a a 23 = a11 22 a32 a 33 a 23 a − a21 12 a 33 a32 a 13 a + a31 12 a 33 a22 a 13 a 23 The cofactor is the determinant of each submatrix The cofactor is the determinant ... & Francis Group, LLC Introduction to Modeling a11 a21 a31 a12 a22 a32 47 a 13 a 23 = a11 a22 a 33 − a32 a 23 − a21 a12 a 33 − a32 a 13 + a31 a12 a 23 − a22 a 13 a 33 ( ) ( ) ( ) We can consider this by...
  • 100
  • 1.3K
  • 0
Modeling of Combustion Systems A Practical Approach 10 ppsx

Modeling of Combustion Systems A Practical Approach 10 ppsx

Ngày tải lên : 13/08/2014, 05:22
... of the flame stability of a burner design is the turndown ratio The turndown ratio is the © 2006 by Taylor & Francis Group, LLC 106 Modeling of Combustion Systems: A Practical Approach ratio of ... Francis Group, LLC 130 Modeling of Combustion Systems: A Practical Approach The bottom end of the heater (where the burners reside — not shown) corresponds to the closed end of a tube This would ... 0.00 0.24 7. 03 1.00 1.25 0.00 7.80 196.98 44.01 22. 53 Sum © 2006 by Taylor & Francis Group, LLC 14.54 32 .00 28.02 44.01 18.02 9.90 271 .32 9.52 271 .32 Introduction to Combustion 137 In addition,...
  • 89
  • 349
  • 0
Modeling of Combustion Systems A Practical Approach 11 doc

Modeling of Combustion Systems A Practical Approach 11 doc

Ngày tải lên : 13/08/2014, 05:22
... partitioned ANOVA of Table 3. 9 TABLE 3. 9 Partitioned ANOVA Term SS DF MS F(1, 4) P Model a1 a2 a3 91. 63 85 .31 13. 02 1 91.6 85 .3 13. 0 93. 3 86.8 13. 3 0.0006 0.0007 0.0220 R 3. 94 1.0 r2 98.0% T 1 93. 91 s 0.99 ... as shown in Table 3. 6 TABLE 3. 6 Partitioned ANOVA for Table 3. 4 Term SS DF MS F P Model a1 a2 a3 12. 63 0.89 3. 19 1 12. 63 0.89 3. 19 159.8 11 .3 40 .3 0.0002 0.02 83 0.0 031 R 0 .32 0.08 r2 98.1% T ... estimate of experimental error, e.g., ahjk xh xj xk ≈ e If so, Equation 3. 52 becomes y = a0 + a1x1 + a2 x2 + a3 x3 + a12 x1x2 + a 13 x1x3 + a 23 x2 x3 + e Example 3. 6 (3. 57) Interpretation of the...
  • 101
  • 421
  • 0
Modeling of Combustion Systems A Practical Approach 12 doc

Modeling of Combustion Systems A Practical Approach 12 doc

Ngày tải lên : 13/08/2014, 05:22
... ⎜ 24 M3 = ⎜ ⎜ 24 ⎜ ⎝ 24 ⎛ 436 ⎜ 115 M4 = ⎜ ⎜ 115 ⎜ ⎝ 115 1 0 1⎞ ⎛ 19 0⎟ ⎜ ⎟ =⎜ 0⎟ ⎜ ⎟ ⎜ 1⎠ ⎝ 1 24 6 24 115 31 30 30 115 30 31 30 24⎞ 6⎟ ⎟ 6⎟ ⎟ 7⎠ 115⎞ 30 ⎟ ⎟ 30 ⎟ ⎟ 31 ⎠ Now the traces of each ... 0.7 031 ⎜ ⎜ ⎜ H=⎜ ⎜ ⎜ ⎜ ⎝ ( © 2006 by Taylor & Francis Group, LLC x1, k x2 , k ) 0 .33 02 0. 235 0 sym −0.0586 0.2062 0.8 930 0.2126 0.1251 −0.1771 0 .33 73 0. 035 8 0.1120 0. 135 1 0.1999 0.2104 −0.2 232 ... 0.2401 −0.0695 −0.0814 −0.0485 0.27 23 0.2107 0.2468 0.1469 0.8 935 −0.1624 0. 734 5 0. 139 3 0 .31 38 0.2 431 sym 0. 038 5⎞ −0.1168⎟ ⎟ −0.0116⎟ ⎟ −0.05 13 0.2054⎟ ⎟ 0. 935 8⎠ • Quadratic model: ⅙ 2 y = a0...
  • 128
  • 1.2K
  • 0
Modeling of Combustion Systems A Practical Approach 13 potx

Modeling of Combustion Systems A Practical Approach 13 potx

Ngày tải lên : 13/08/2014, 05:22
... + ln + ζ T ⎥ ⎦ ( ) 436 Modeling of Combustion Systems: A Practical Approach FIGURE 5.1 An ECU simulator The figure is a picture of a state -of- the-art ECU simulator capable of firing up to MW using ... 0.21 (32 .00)/ [0.21 (32 .00) + 0.79 (28.02)] = 0. 233 ), ma is the mass flow of air into the windbox [M/θ], wO2,b is the mass fraction of oxygen exiting the windbox [ ], and mb is the mass flow out of ... LLC 432 Modeling of Combustion Systems: A Practical Approach 3% Therefore, we expect the actual flue gas analysis to be as follows Before: NOx = 42.2 ppm, O2 = 2% After: NOx = 46 ppm, O2 = 3% The...
  • 109
  • 319
  • 0
Modeling of Combustion Systems A Practical Approach 14 potx

Modeling of Combustion Systems A Practical Approach 14 potx

Ngày tải lên : 13/08/2014, 05:22
... 2.1 2.2 3. 1 3. 2 3. 3 3. 4 3. 5 3. 6 3. 7 3. 8 3. 9 3. 10 3. 11 3. 12 3. 13 3.14 3. 15 3. 16 3. 17 3. 18 3. 19 3. 20 3. 21 Table Table Table Table Table Table Table Table 3. 22 3. 23 3.24 3. 25 3. 26 3. 27 3. 28 3. 29 Qualitative ... Figure Figure 2.20 2.21 2.22 2. 23 2.24 2.25 2.26 2.27 2.28 2.29 2 .30 2 .31 2 .32 3. 1 3. 2 3. 3 3. 4 3. 5 3. 6 3. 7 3. 8 3. 9 3. 10 3. 11 3. 12 3. 13 3.14 3. 15 3. 16 3. 17 3. 18 4.1 4.2 4 .3 Figure Figure Figure Figure ... Group, LLC 3. 3.2 3. 3 .3 3 .3. 4 General Features of Factorial Designs .212 Construction Details of the Two-Level Factorial .2 13 Contrast of Factorial and Classical Experimentation 216 3. 3.4.1...
  • 37
  • 263
  • 0
Báo cáo y học: "Mathematical modeling of the socalled Allis test: a field study in orthopedic confusion" docx

Báo cáo y học: "Mathematical modeling of the socalled Allis test: a field study in orthopedic confusion" docx

Ngày tải lên : 13/08/2014, 14:20
... ↑ femur ↓ tibia ↑ hip cephalad 12 37 0.0 37 0.0 35 8.0 35 8.0 38 2.0 37 0.0 460.0 448.0 460.0 472.0 448.0 460.0 570.0 570.0 570.0 570.0 570.0 582.0 n/a -7 .3 -9 .3 -2 .3 1.8 -5.6 n/a 9.6 -7.7 -17.5 17.5 ... the purpose of mathematical modeling the Allis test, we assumed a left tibial length of 37 0 mm, a left femoral length of 460 mm, and a distance from hip to foot of the supine patient of 570 mm ... other health professionals continue to exhibit interest in the matter The oft-noted distinction of aLLI from fLLI [2 ,3] only adds to the complexity of the controversy A number of excellent reviews...
  • 7
  • 709
  • 0