... 1.51x10–3 M = x Thus, [H3O+] = [CH3 CH 2CH2 COO–] = 1.51x10–3 M [CH3 CH 2CH2 COOH] = (0.15 – x) = (0.15 – 1.51x10–3) M = 0.14849 M  H3O   CH3 CH CH COO      Ka =  CH3 CH CH COOH  Copyright © McGraw-Hill... for x; solve for Ka Solution: Butanoic acid dissociates according to the following equation: CH3 CH 2CH2 COOH(aq) + H2O(l)  H3O+(aq) + CH3 CH 2CH2 COO–(aq) Initial: 0.15 M 0 Change: –x +x +x Equilibrium:... A–) Solution: Calculating the percent dissociation of each diluted solution: Solution Percent dissociation = [4/(5+4)] X 100 = 44% Solution Percent dissociation = [2/(7 + 2)] X 100 = 22% Solution