... N mol O 16.00 g O = 2.060 mol N = 1 .030 mol O Divide each subscript by the smaller value, 1 .030 : C4.119 H 5.15 1 .030 1 .030 N 2.060 O1 .030 = C4H5N2O 1 .030 1 .030 This gives C4H5N2O as the empirical... number of moles  35.45 g Cl  Divide each mole value by the lowest value, 0. 0033 850: C 0.010248 H 0.0068495 Cl 0. 0033 850 = C3H2Cl 0. 0033 850 0. 0033 850 0. 0033 850 The empirical formula has the following... diatomic or polyatomic molecules Solution: “1 mol of chlorine” could be interpreted as a mole of chlorine atoms or a mole of chlorine molecules, Cl2 Specify which to avoid confusion The same problem