... 0.48mg − 0.16ma ΣFx = Σ ( Fx )eff : FB = ma 0.48mg − 0.16ma = ma 0.48g = 1.16a a = ( ) 0.48 9.81 m/s = 4.0593 m/s 1 .16 or a = 4.06 m/s Vector Mechanics for Engineers: Statics and Dynamics, 8/e,... Online Solutions Manual Organization System Chapter 16, Solution 11 ΣM G = ⇒ FA = ΣF⊥ BG = ( mg )( sin 30° ) = ma a= g or a = 16. 1 ft/s ∑ F& BG = FB − (16 lb )( cos 30° ) = FB = 13.856 lb (a) a = 16. 10... 0.48mg − 0.16ma ΣFx = Σ ( Fx )eff : FB = ma 0.48mg − 0.16ma = ma 0.48 g = 1.16a a = ( ) 0.48 9.81 m/s = 4.0593 m/s 1 .16 or a = 4.06 m/s Vector Mechanics for Engineers: Statics and Dynamics, 8/e,