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... Chb012 (a) E = F e = 3.9 × 10−15 N −19 (a) By Eq 2 4-1 8, the change in potential is the negative of the “area” under the curve Thus, using the area -of- a-triangle formula, we have V − 10 = − x =2 z G... 3q1+ q1– q1 = 0, then their contribution to Eq 2 4-2 7 vanishes The net potential is due, then, to the two +4q2 particles, each of which is a distance of a/2 from the center In SI units, it is V= 4q2... total volume is twice the volume of an original drop, so the radius R' of the combined drop is given by (R')3 = 2R3 and R' = 21/3R The charge is twice the charge of original drop: q' = 2q Thus,