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... negative-valued charge Thus, q1 is a positive-valued charge We write each charge as a multiple of some positive number ξ (not determined at this point) Since the problem states the absolute value of. .. 2πεo z3 Therefore, in the terminology of the problem, Enext = q d3/ 4πε0z5 21 Think of the quadrupole as composed of two dipoles, each with dipole moment of magnitude p = qd The moments point... charged quarter-circle produces a field of magnitude G |q| 1 2 |q| π/4 | E |= [sin θ ]− π / = r π / 4πε r 4πε π r That produced by the positive quarter-circle points at – 45°, and that of the negative