... that this agrees with the result of part (c) provides insight into the concept of work 12 (a) From Eq 7-6 , F = W/x = 3.00 N (this is the slope of the graph) (b) Eq 7-1 0 yields K = Ki + W = 3.00... [0.500 ∠ 30.0º]) = +1.31 J (b) Eq 7-1 0 (along with Eq 7-1 ) then leads to v = 2(1.31 J)/(3.00 kg) = 0.935 m/s 19 (a) We use F to denote the magnitude of the force of the cord on the block This force... factor of 1/2) are led to vson = 2vi = 4.8 m s 6 By the work-kinetic energy theorem, W = ∆K = ( ) 2 mv f − mvi = (2.0 kg) (6.0 m/s) − (4.0 m/s) = 20 J 2 & & We note that the directions of v f