... 100∠20° - j2 = -5 5.45 − j286.2 - 0.5 100∠20° = -2 6.95 − j364.5 + j10 100∠20° ∆1 = 64.74 ∠ - 13.08° ∆ ∆2 V2 = = 81.17 ∠ - 6.35° ∆ V1 − V2 ∆ − ∆ - 28.5 + j78.31 = = Io = 2∆ 0.3333 − j I o = 9.25 -1 62.12°... version of the circuit is shown below 0.1 Vo 40 Ω V1 6∠15 o 20 Ω + Vo - Io V2 -j100 Ω j20 Ω PROPRIETARY MATERIAL © 2007 The McGraw-Hill Companies, Inc All rights reserved No part of this Manual. .. below 5A 2Ω jΩ V1 V2 I -j20 V + − -j2 Ω 2I 4Ω At node 1, V V − V2 - j20 − V1 = 5+ + - j2 j - − j10 = (0.5 − j0.5) V1 + j V2 (1) At node 2, V1 − V2 V2 , = j V where I = - j2 V2 = V1 0.25 − j +