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Solution manual mechanics of materials 8th edition hibbeler chapter 10 Solution manual mechanics of materials 8th edition hibbeler chapter 10 Solution manual mechanics of materials 8th edition hibbeler chapter 10 Solution manual mechanics of materials 8th edition hibbeler chapter 10 Solution manual mechanics of materials 8th edition hibbeler chapter 10 Solution manual mechanics of materials 8th edition hibbeler chapter 10 Solution manual mechanics of materials 8th edition hibbeler chapter 10
... ex = -100 (10 - 6), -100 + (-200) 100 -100 - (-200) -6 ; c d + a b r (10 ) A 2 A -150 ; 70.71 B (10 - 6) = e1 = -79.3 (10 - 6) tan 2uP = e2 = -221 (10 - 6) gxy 100 (10 - 6) C -100 - (-200) D (10 -... publisher *10 20 Solve Prob 10 10 using Mohr’s circle ex = 400 (10 - 6) A(400, 155) (10 - 6) ey = -250 (10 - 6) gxy = 310( 10 - 6) gxy = 155 (10 - 6) C(75, 0) (10 - 6) R = [2(400 - 75)2 + 1552 ] (10 - 6)... ex = 480 (10 - 6) ey = 720 (10 - 6) A(480, 325 )10 - C(600, 0 )10 - gxy = 650 (10 - 6) y A gxy = 325 (10 - 6) R = (2(600 - 480)2 + 3252 )10 - = 346.44 (10 - 6) a) e1 = (600 + 346.44 )10 - = 946 (10 - 6)