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!&.&-/&01& B. 2&#3 C. 2-2 "#555D"#A+?'@=%)$EAFG A. !&.&-/&01& B. 2&#3 C. 2-2 "#5H@%)IJIK(ALM A. !&.&-/&01& B. 2&#3 C. 2-2 "# '!(E-ANF A. !&.&-/&01& B. 2&#3 C. 2-2 "#5&"#A+-AGO A. !&.&-/&01& B. 2&#3 C. 2-2  8P5 QR ST5Q UVWXYZ FUF5Q 45-6 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⇒O [3O&BO M  EH⇒ ⇒O [3O&BO M  EH⇒ ⇒O [3O&BO M  K [...]... 0,144176 0,3 0,3 0 0,409542 0,4 0,409935 Trang 18 Sai số : x ( 7) x Tj x ( 7) x (6 ) 1 Tj 0,111475 0,111442 0,625 = 0,144176 0,144559 1 0,625 0,409935 0,409542 0,000033 0,625 0,625 = 0,000383 = 0,000393 = 0,655.10 3 < 10 3 1 0,625 1 0,625 0,000393 Vậy nghiệm gần đúng của hệ ph ơng trình là: x1 0,111475 x = x (7) = 0,144176 2 x3 0,409935... 413125 Sai số : x (3) x Tj x (3) x (2 ) 1 Tj 0,1203125 0,15 0,625 = 0,1375 0,19375 1 0,625 0, 413125 0,325 x (4) 0,625 = 1 0,625 0,0296875 0,625 0,05625 = 0,088125 = 0,147 1 0,625 0,088125 = Tj x + C j (3) 0,25 0,25 0,120313 0,25 0,112344 0 0,375 = 0 0,25 0,1375 + 0 = 0,148398 0,3 0,3 0,413125 0,4 0,405156 0 Sai số : x ( 4) x Tj... 17 Sai số : x (5) x Tj x ( 5) x ( 4 ) 1 Tj 0,111612 0,112344 0,625 = 0,143418 0,148398 1 0,625 0,410816 0,405156 0,000732 0,625 0,625 = 0,00498 = 0,00566 = 0,00943 > 10 3 1 0,625 1 0,625 0,00566 x (6 ) = Tj x + C j ( 5) 0,25 0,25 0,111612 0,25 0,111442 0 = 0,375 0 0,25 0,143418 + 0 = 0,144559 0,3 0,3 0 0,410816 0,4 0,409542 Sai số : x... 0,375 0 0,25 0 + 0 = 0 0,3 0,3 0 0 0,4 0,4 Sai số : x x (1) Tj x x (1) 1 Tj (0) 0,625 = 1 0,625 0,25 0,625 0 = 0,4 = 0,667 > 10 3 1 0,625 0,4 x (2 ) = Tj x (1) + C j 0,25 0,25 0,25 0,25 0,15 0 = 0,375 0 0,25 0 + 0 = 0,19375 0,3 0,3 0 0,4 0, 4 0,325 Trang 16 Sai số : x (2) x Tj x (2 ) x (1) 1 Tj 0,15 0,25 0,625 = 0,19375 ... 0,9 = 0,1 0 0,2 0 + 0,7 = 0,7 0 0,2 0 0 0,6 0,6 Trang 19 Sai số : x (1) x Tj x (1) x (0) 1 Tj 0,9 0,3 0,3 = 0,7 = 0,9 = 0,3857 > 10 3 1 0,3 1 0,3 0,6 x (2 ) = Tj x (1) + C j 0 0,1 0 0,9 0,9 0,97 = 0,1 0 0,2 0,7 + 0,7 = 0,91 0 0,2 0 0,6 0,6 0,74 Sai số : x (2 ) x Tj 1 Tj 0,07 0,3 = 0,21 1 0,3 0,14 x (2 ) x (1) = 0,97 ... 0 0,2 0 0,74 0,6 0,782 Sai số : x x (3) Tj x x (3) 1 Tj 0,021 0,3 = 0,035 1 0,3 0,042 = (2 ) 0,991 0,97 0,3 = 0,945 0,91 1 0,3 0,782 0,74 0,3 0,042 = 0,018 > 10 3 1 0,3 Trang 20 x ( 4) = Tj x (3) + C j 0 0,1 0 0,991 0,9 0,9945 = 0,1 0 0,2 0,945 + 0,7 = 0,9555 0 0,2 0 0,782 0,6 0,789 Sai số : x ( 4) x Tj 1 Tj 0,0035 0,3 =... 0,6 0,7911 Sai số : x ( 5) x Tj x (5) x ( 4) 1 Tj 0,00105 0,3 = 0,00175 1 0,3 0,0021 x (6) = 0,99555 0,9945 0,3 = 0,95725 0,9555 1 0,3 0,7911 0,789 0,3 0,0021 = 0,9.10 3 < 103 1 0,3 = Tj x + C j (5) 0 0,1 0 0,99555 0,9 0,995725 = 0,1 0 0,2 0,95725 + 0,7 = 0,957775 0 0, 2 0 0,7911 0,6 0,79145 Trang 21 Sai số : x (6) x Tj x (6) ... 0 0,124023438 0,25 0,25 0 0,126953125 0,25 0,125976563 0 x (8) = 1 0,000976563 0,000976563 0,000976563 0,000976563 = 0,000976563 < 10 3 Trang 29 Vậy nghiệm gần đúng của hệ ph ơng trình là: x1 0,624023438 x 0,374023438 2 (8) =x = x3 0,124023438 0,125976563 x4 Trang 30 CHNG IV NI SUY VA XP X HAM A TểM TT Lí THUYT: 4.1 t bi toỏn: (4.1) Vi n l sụ t nhiờn... x 0 : N (1) ( x ) = y0 + f [ x0 , x1 ] ( x x0 ) + f [ x0 , x1 , x2 ] ( x x0 )( x x1 ) 2 Tính tỉ sai phân cấp 1 của f(x): [ x0 , x1 ] = [ 0,0;0,3] f [ x0 , x1 ] = y1 y0 1,132647 1 = = 0,442157 x1 x0 0,3 0 [ x1 , x2 ] = [ 0,3;0,6 ] f [ x1 , x2 ] = y2 y1 0,754338 1,132647 = = 6,28995 x2 x1 0,6 0,3 Tính tỉ sai phân cấp 2 của f(x): [ x0 , x1 , x2 ] = [ 0,0;0,3;0,6 ] f [ x0 , x1 , x2 ] = f... x ) = y0 + f [ x0 , x1 ] ( x x0 ) + f [ x0 , x1 , x2 ] ( x x0 )( x x1 ) 2 Trang 35 Tính tỉ sai phân cấp 1 của f(x): [ x0 , x1 ] = [ 2,2;2,4 ] f [ x0 , x1 ] = y1 y0 0,767844 0,709267 = = 0,292885 x1 x0 2,4 2,2 [ x1 , x2 ] = [ 2,4;2,6 ] f [ x1 , x2 ] = y2 y1 0,816609 0,767844 = = 0,243825 x2 x1 2,6 2,4 Tính tỉ sai phân cấp 2 của f(x): [ x0 , x1 , x2 ] = [ 2,2;2,4;2,6 ] f [ x0 , x1 , x 2