Bai giai tri tue nhan tao tut

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Bai giai tri tue nhan tao tut

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Tut1_Sol Question 1. get3rd([_, _, I | _], I). insertLast(H, L, R) :- append(L, [H], R). getN([H | _], 1, H) :- !. getN([_ | T], N, X) :- N1 is N - 1, getN(T, N1, X). append2l([], X, X). append2l([H | T], X, [H | T1]) :- append2l(T, X, T1). reverseL([], []). reverseL([H | T], L) :- reverseL(T, T1), append(T1, [H],L). Question 2. prefix([],[_|_]). prefix([X|T1],[X|T2]) :- prefix(T1,T2). postfix(L1,L2) :- reverseL(L1,T1),reverseL(L2,T2),prefix(T1,T2). Question 3. separate([],[],[]). separate([H|T],[H|L1], L2):-H mod 2 < 1,!, separate(T,L1,L2). separate([H|T],L1,[H|L2]):-separate(T,L1,L2). Question 4. check([]). check([_]). check([_, _]). check([E1, E2, E3]) :- E3 > E1 * E2. check([H1, H2, H3, H4 | T]) :- H3 > H1 * H2, H4 < H2 * H3, check([H3, H4 | T]). Question 5. remoDup([H], [H]) :- !. remoDup([H | [H | T]], [H | T1]) :- remoDup([H | T], [H | T1]), !. remoDup([H | [H1 | T]], [H | [H1 | T1]]) :- remoDup([H | T], [H | T1]). change([], []) :- !. change([H | T], [H | T1]) :- remoDup([H | T], [H | T2]), change(T2, T1). Question 6. Page 1 Tut1_Sol calculate(0, N, X) :- X is N + 1, !. calculate(M, 0, X) :- M1 is M - 1, calculate(M1, 1, X), !. calculate(M, N, X) :- M1 is M - 1, N1 is N - 1, calculate(M, N1, X1), calculate(M1, X1, X). Page 2 . Tut1_ Sol Question 1. get3rd([_, _, I | _], I). insertLast(H, L, R) :- append(L,. [H | T1]) :- remoDup([H | T], [H | T2]), change(T2, T1). Question 6. Page 1 Tut1_ Sol calculate(0, N, X) :- X is N + 1, !. calculate(M, 0, X) :- M1 is M

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