Tài liệu Physics exercises solution: Chapter 30 pptx

Tài liệu Project Management Professional-Chapter 4 pptx

... same subassembly in 30 minutes. On the assembly line the job of each of the workers was only 1.8 minutes each. By enlarging the job the size of the job went from 1.8 minutes to 30 minutes. Although ... discussion begins, the leader of the meeting can use the agenda to bring 9618$$ $CH4 09-06-02 14:59 :30 PS 130 Preparing for the Project Management Professional Certiﬁcation Exam thin...

Ngày tải lên : 24/12/2013, 12:16

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Tài liệu Project Management Professional-Chapter 5 pptx

... failures מ40,000 15% מ6,000 Additional orders 75,000 30% ם22,500 Penalty for late delivery מ50,000 5% מ2,500 Incentive for early 100,000 30% 30, 000 delivery Expected value of the 234,000 project ... the PMI Board of Directors held their quarterly board meeting in New Orleans. The chapter hosted the board for a chapter meeting, and for the program they invited a panel of disaster and em...

Ngày tải lên : 24/12/2013, 12:16

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Tài liệu VN Ag. Atlas - Chapter 3 pptx

Ngày tải lên : 20/01/2014, 22:20

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Tài liệu Thuật toán Algorithms (Phần 30) pptx

... left or right son of its father. For example, in the tree above we might have dad[O]= -30, count [30] =21, dad [30] =-28, and count[28]=37 ... 1):1); This program uses the bits procedure from Chapters 10 and 17 to access single bits. Our sample message is encoded in only 236 bits versus the 300 used for the straightforward encoding, a 21% ... the typical user than in the past. On the othe...

Ngày tải lên : 26/01/2014, 14:20

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Tài liệu Physics exercises_solution: Chapter 30 pptx

... terminal at . a 30. 8: a) H. 130. 0 m)120.0(2 )m1080.4()1800()500( 2/ 252 0 2 0m m     π μ πr ANμK K L b) Without the material, H.102.60H) 130. 0( 500 11 4 m m   K L K L 30. 64: (a) Initially ... A0354.0 360 V7.12 1 0    R i  30. 9: For a long, straight solenoid: .//and/ 2 00 lANμLlNiAμiNL BB  30. 10: a) Note that points a and b are reversed from that of figure...

Ngày tải lên : 17/01/2014, 04:20

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Tài liệu Physics exercises_solution: Chapter 09 pptx

... was 1082s)(2.00)srad (30. 0s)(2.00)srad0.24( 22  rad, so the total angle is rad.540rad432rad108  b) The angular velocity when the circuit breaker trips is       s,rad84s00.2srad0.30srad0.24 2  so ... m s.rad652c) J.51.8)21(b) 2K 2  I mv 9.68: a) s.rad300.0)00.6)(srad(0.05b) .srad050.0 22 m0.60 sm00.3 2 tan  sαtα r a c) .sm5.40m)(60.0s)rad300.0( 222 rad  ra d)...

Ngày tải lên : 21/12/2013, 03:15

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Tài liệu Physics exercises_solution: Chapter 12 pptx

... and the radii, kg.1012.3.)( 30 )kgmN10673.6()ds86,400d137( m)102.26m1078.6(4 22112 310102        MMMM Since 1034.2andkg,1080.7or kg,1012.34,3 302 930  βαααβααβ MMMMRRMM ... s.m1027.8 ))11.0m)(10((1.50kg)1099.185.0)(kgmN10673.6( 4 1 1302 211     rGmv b) weeks).(about twos1025.12 6 vr  12.34: From either Eq. (12.14) or Eq. (12.19), kg.1098.1 d))s...

Ngày tải lên : 21/12/2013, 03:15

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Tài liệu Physics exercises_solution: Chapter 19 pptx

... γ ii γ VPPV PdVWU    const     J. 105.1atmL50 L)(30atm)2.1( VPdVU 3 4.11 1.4-1 L )30( 1.4-1 L)10( 1.4 10L1 L30 1 1 V ii V VP 10L L30 i i            The internal energy ...   J0.30J0.60J0.90a)  WQU for any path between a and b. If W=15.0 J along path abd, then J.0.45J0.15J0 .30  WUQ b) Along the return path,     J;0.65J0.35J0.30andJ,...

Ngày tải lên : 21/12/2013, 03:16

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Tài liệu Physics exercises_solution: Chapter 20 pptx

... J.1043.6 5 )280.0( s)W)(1.0010180( 1 3   PtQ e b) J.104.63s)W)(1.0010180(J1043.6 535  PtQ 20.5: a) MW.970MW330MW 1300 b) %.2525.0 MW 1300 MW 330 e 20.6: Solving ,for (20.6)Eq. r or )1ln(ln)1( erγ  .8.13)350.0()1( 5.2 1 1   γ er If ... 20.1: a) %.8.33338.0b) J.6500J 4300 J2200 6500 2200  20.2: a) %.9.28289.0b) J.2600J6400J9000 J9000 J2600  20.3:...

Ngày tải lên : 21/12/2013, 03:16

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