Tài liệu Database Systems - Part 5 pptx

... COP 4710: Database Systems (Day 5) Page 1 Mark LlewellynCOP 4710: Database Systems Spring 2004Introduction to Data Modeling – Part 2 BÀI 5, 1 ngàyCOP 4710: Database Systems Spring 2004Introduction ... Database Systems (Day 5) Page 29 Mark Llewellyn Correspondence of E-R & UML Class DiagramsEntity sets and attributescustomercustomer-namecustomer-idcustomer-streetcustomer-cityE-R ... Diagramcustomer namecustomer-idcustomer-namecustomer-streetcustomer-cityCOP 4710: Database Systems (Day 5) Page 3 Mark Llewellyn •An entity set may include sub-groupings of entities that...

Tài liệu Database Systems - Part 3 & 4 pptx

... Example ERDcustomercustomer-idcustomer-name streetapartment-numphone-numdate-of-birthagefirst-namemiddle-namelast-nameaddresscitystatezipcodestreet-namestreet-num ... Strong Entity Sets (cont.)loanloan-num amountloan-paymentpaymentpayment-numpayment-dateamountCOP 4710: Database Systems (Day 4) Page 15 Mark Llewellyn E-R Model NotationEentity setEweak ... is an object-oriented approach to database design that is emerging as a standard for object-oriented database systems. Introduction to Data Modeling (cont.)COP 4710: Database Systems (Day...

Tài liệu Database Systems - Part 2 pdf

... COP 4710: Database Systems (Day 3) Page 1 Mark LlewellynCOP 4710: Database Systems Spring 2004Introduction to Database Systems – Part 2 BÀI 2, 1/2 ngàySchool of Electrical ... LevelCOP 4710: Database Systems (Day 3) Page 15 Mark Llewellyn •The overall description of the database is called the database schema.•There are three different types of schema in the database ... well-designed database produces, in an efficient way, a system that provides the correct information for the decision-making process to succeed. Database Design (cont.)COP 4710: Database Systems...

Tài liệu Database Systems - Part 10 ppt

... G}) -) %COP 4710: Database Systems (Day 10) Page 1 Mark LlewellynCOP 4710: Database Systems Spring 2004Introduction to Normalization BÀI 10, ½ ngàyCOP 4710: Database Systems Spring ... non-prime attribute which is partially dependent on any key of R. In other words, no non-prime attribute is dependent on only a portion of the key of R. 5 ) -) %COP ... ) -) %COP 4710: Database Systems (Day 10) Page 15 Mark Llewellyn •A relation scheme R is in 2NF with respect to a set of functional dependencies F if every non-prime attribute...

Tài liệu Database Systems - Part 11 doc

... Lossless Join - ExampleA B C D E(AD)a1b12b13a4b 15 (AB)a1a2b23b24b 25 (BE)b31a2b33b34a 5 (CDE)b41b42a3a4a 5 (AE)a1b 52 b 53 b 54 a 5 COP 4710: Database Systems ... D E(AD)a1b12b13a4b 15 (AB)a1a2b13b24b 25 (BE)b31a2b33b34a 5 (CDE)b41b42a3a4a 5 (AE)a1b 52 b13b 54 a 5 COP 4710: Database Systems (Day 11) Page 26 Mark ... D E(AD)a1b12b13a4b 15 (AB)a1a2b13b24b 25 (BE)b31a2b13b34a 5 (CDE)b41b42a3a4a 5 (AE)a1b 52 b13b 54 a 5 COP 4710: Database Systems (Day 11) Page 27 Mark...

Tài liệu Database Systems - Part 12 docx

... AF&G 56 8H9E $}A,B,C,D{DG=+COP 4710: Database Systems (Day 12) Page 1 Mark LlewellynCOP 4710: Database Systems Spring 2004Introduction to Normalization – Part ... time: equates a 5 , b 15 , b 25 )Decomposition has the lossless join property.;<=%>?A B C D E(CD)b11a2a3a4b 15 (ABC)a1a2a3a4b 15 (BE)b31a2a3a4a 5 COP ... property.;<=%>?A B C D E(CD)b11a2a3a4b 15 (ABC)a1a2a3a4b 15 (BE)b31a2a3a4a 5 COP 4710: Database Systems (Day 12) Page 7 Mark Llewellyn Let R = (A, B, C, D, E) F = {AB→CDE,...

Tài liệu Database Systems - Part 13 pdf

... VALUES (212 25, ‘Bryson, Inc.’, ‘Smithson’, ‘6 15 , ‘22 3-3 234’, ‘TN’, ‘Y’);INSERT INTO VENDOR VALUES (21226, ‘SuperLoo, Inc.’, ‘Flushing’, ‘904’, ‘21 5- 8 9 95 , ‘FL’, ‘N’);COP 4710: Database Systems ... today’s dateCOP 4710: Database Systems (Day 17) Page 19 Mark LlewellynThe INVOICE Table in Access (-) COP 4710: Database Systems (Day 17) Page 1 Mark LlewellynCOP 4710: Database Systems Spring 2004Introduction ... table:INSERT INTO PRODUCT VALUES (‘23114-AA’, ‘Sledge hammer, 12 lb.’, ’02-Jan-02’, 8, 5, 14.40, 0. 05, NULL);This code inserts this row into PRODUCTCOP 4710: Database Systems (Day 17) Page 2 Mark LlewellynHistory...

Tài liệu Database Systems - Part 14 pdf

... 5 @022026880 65 67COP 4710: Database Systems (Day 18) Page 23 Mark LlewellynRight Outer Joins (cont.) (+) 5  ;56 2.6:20 52 2 65 16 5 0;2#COP ... (cont.) 5 .629 65 29 65 0A67#.62101.0002<88072 65 2;0670 65. 88203200 65 .020.6#COP 4710: Database Systems (Day 18) Page 29 Mark LlewellynUnion ALL Operator 5 .629 65 29 65 0A67#.62101.0002<8860.8602612@0 65 92129#COP ... following query:26= 5 2>2.6?2026880 65 4.3#6183 65 96:202 ;56 :20 65 2.618#COP 4710: Database Systems (Day 18) Page 21...

Tài liệu Database Systems - Part 15 docx

... conjunction.COP 4710: Database Systems (Day 21) Page 1 Mark Llewellyn ©COP 4710: Database Systems Spring 2004Query Processing and OptimizationBÀI 15, 1 ,5 ngàyCOP 4710: Database Systems Spring 2004Query ... equi-join operation R *A=B S has the same effect as a natural join operation.COP 4710: Database Systems (Day 21) Page 22 Mark Llewellyn ©Algorithms for Two-way Join Operations•(J1-nested ... for each tuple generated from R) generates 15 tuples × 100 bytes = 150 0 bytes. Total = 153 0 bytes.–S * R: 1 pass through S generates 5 × 100 bytes = 50 0 bytes. Five passes through R (one for...

Tài liệu SQL Basic part 5 pptx

... SQL Tutorials - Phần I (bài 4) Câu lệnh INSERT INTO : Như đã nói ở trên câu lệnh INSERT INTO dùng để thêm ... INTO table_name VALUES (value1, value2, ) Hoặc cũng có thể chỉ rõ cột mà mình muốn insert dữ liệu : Trích: INSERT INTO table_name (column1, column2, ) VALUES (value1, value2, ) Insert...

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