... yYayy t K 1 = Ker Y 1 s ừ K 1 P 1 Rổ tỹ s Y 1 õ t õ ởt t tỹ f 1 : P 1 K 1 t à 1 = j 1 f 1 tr õ j 1 : K 1 P0 útỹ tứ K 1 P0 t Im à 1 = Ker t K2= Ker à 1 tữỡ tỹ ... xδ(b 1) )Nn)\V (I) s❛♦ ❝❤♦ xδ(b)∈ p✳ ❱➻ t❤➳✱xδ (1) , . . . , xδ(b)∈ p ✈➔ xδ (1) /1, . . . , xδ(i 1) /1, xδ(i +1) /1, . . . , xδ(b) /1, xδ(i) /1 ❦❤æ♥❣ ❧➔ ❞➣② ❝❤➼♥❤ q✉② ù♥❣ ✈î✐ (Nn)p✳ ✣➦tJ0:= ... > s + 1 ❇ð✐ ❞➣② ❦❤î♣ ❞➔✐tr➯♥✱ t❛ ❝â ❞➣② ❦❤î♣HsI(JnM/Jn +1 M) −→HsI(M/Jn +1 M)−→ HsI(M/JnM) −→ Hs +1 I(JnM/Jn +1 M)tr♦♥❣ ✤â HsI(JnM/Jn +1 M = Hs +1 I(JnM/Jn +1 M) =...