... 2Ag 2Ag(NH3)2+ + Cu 10 - 13,16 C 5,0 .10 -4 [ ] 5,0 .10 -4 -x 2x 213,16 4 (2x) 10 (5, 0 .10 x)−−⇒ =− x = 5 .10 - 4 2x = 42 38161 34 10x 5101 010x5−−−−<=,,. 0,5 đ ... K = 10 -10, 07 0,5 đ C 5 .10 -3 5 .10 -2 0 ,48 5 [ ] (5 .10 -3-x) (5 .10 -2-x) x 0 ,48 5+3x 3 10, 073 2x(0, 48 5 3x) 10 (5 .10 x)(5 .10 x)−− −+⇒ =− − 0.5đ Với x << 5 .10 -3 ... 2Ag + Cu(NH3) 4 2+ ; 40 22KK ββ=− = 10 13,16 0,5 đ 1,0 .10 -3 5,0 .10 -4 TPGH: 23 4 Cu(NH )+: 5,0 .10 -4 M ; 33NH :1,0 2 .10 1,0M−− ≈ Cân bằng Cu(NH3) 4 2+ + 2Ag 2Ag(NH3)2+...