... divide 2 = 27 σ 2 3 − 4σ 3 2 by σ6 3 we obtain the relation(σ 3 3) 2 +4(σ 2 σ 2 3 ) 3 = − 27 σ4 3 .Thus if we setc4= −ω 2 σ 2 σ 2 3 ,c6=ω 3 2 3 3, ∆=−ω64σ4 3 =ω 2 4σ4 3 (3. 11)then ... C 3 :set = x 2 1x 2 + x 2 2x 3 + x 2 3 x1− x 2 2x1− x 2 1x 3 − x 2 3 x 2 . (3. 10)This might be called the “anti-symmetrization” (with respect to Σ 3 )ofx 2 1x 2 .Lemma 3. 4. There is ... is an isomorphismW[σ1,σ 2 ,σ 3 ,]/( 2 − f)∼=S(F )C 3 where f is determined by the relation 2 = 27 σ 2 3 − 4σ 3 2 − 4σ 3 σ 3 1+18σ1σ 2 σ 3 + σ 2 1σ 2 2.Furthermore, the actions...