... interest rate is 9% Cash flow Dates ($10000) January 12, 1 987 $2500 February 14, 1 988 $2000 March 3, 1 988 $3000 June 14, 1 988 $4000 December 1, 1 988 To calculate the net present value of this irregular ... irregular cash flow: cf = [−10000, 2500, 2000, 3000, 4000]; df = ['01/12/1 987 ' '02/14/1 988 ' '03/03/1 988 ' '06/14/1 988 ' '12/01/1 988 ']; pv = pvvar(cf, 0.09, df) returns pv = 142.16 See Also 2-210 fvfix, ... 729791 72 981 9 99 .85 4 99.344 98. 942 99 .85 5 99.349 98. 946 0.054391 0.055714 0.055 184 (Example output has been formatted for readability.) See Also 2-220 tr2bonds and other functions for Term Structure...