... gim 0,05.m gam 100 0,05.m x = 100 (1) M 64 M + Pb(NO3)2 M(NO3)2 + Pb M (gam) mol 207, tng (207 M) gam x mol gam tng 7,1.m 100 7,1.m x = 100 (2) 207 M 0,05.m 7,1.m 100 = 100 T (1) v (2) ... 58,5 ì 36 100 58,5 ì 36 + 103 ì 53 = 27,84% (ỏp ỏn B) Vớ d 7: Trn 100 ml dung dch A (gm KHCO3 1M v K2CO3 1M) vo 100 ml dung dch B (gm NaHCO3 1M v Na2CO3 1M) thu c dung dch C Nh t t 100 ml dung ... C 5,75 gam D 7,55 gam Hng dn gii Theo phng phỏp KLPTTB: 23 m RCOOH = = 2,3 gam, 10 10 30 m RCH2COOH = = gam 10 10 2,3 + M= = 53 0,1 Axit nht cú KLPT < 53 l HCOOH (M = 46) v axit ng ng liờn tip...