... =1nki=1nixi=1100· 1 175 , 5 = 11, 75 5s2=199(13820, 05 −100.11, 75 52) = 0, 02 07 ⇒ s =0, 02 07 = 0, 14411, 75 5 −0, 144√100· 1, 96; 11, 75 5 +0, 144√100· 1, 96= (11, 72 7; 11, 78 3)à 2X ... u0,025= 1, 96x =1100· 9 072 = 90, 72 s2=199(82 473 2 −100.90, 72 2) = 17, 375 4 ⇒ s = 4, 16890, 72 −4, 16810· 1, 96; 90, 72 +4, 16810Ã 1, 96= (89, 903; 91, 5 37) à σ2x= 32X −σ√nuα/2;X ... t(n−1)α/2= t(4)0,025= 2, 77 6àD= à2 à1d snt(n1)/2;d +snt(n1)/2=1, 8 4, 0255Ã 2, 77 6; 1, 8 +4, 025√5· 2, 77 6= (−3, 1 97; 6, 79 7)X1, X2à1 à21, 2à1...