... c+ddeVD− ρ ∆ M: 1 = c+dL : -1 = a + b - 3c - d + e T : -2 = - a - dsuy ra: e = e ; d = d; c = 1 – d; b = -d - e; a = 2 - dVaọy max=KV2-d.D-d-e. 1-d. àd. e0maxrJ2 = Maởt ... MOODY 70,000 01 1 2 3 4 5 7 x10 3 1 2 3 4 5 7 x10 4 1 2 3 4 5 7 x10 5 1 2 3 4 5 7 x10 6 1 2 3 4 5 7 x10 7 1 x10 8 0,000 0 05 0,000 007 0,000 05 0,000 1 0,000 2 0,000 ... ∆pAB =50 0Kpa; Tìm Q1; Q2m97 .50 1000*81.91000 *50 0EEhhEEBA1d1dBA==−=⇒+=s/m502.081.9*26003.097 .50 g2LDhV1111d1==λ=⇒s/m 353 .0AVQ3111==⇒s/m307.1AVQ3222==⇒s/m534.7018.081.9*246047.097 .50 g2LDhV2221d2==λ=⇒...