Engineering and Scientific Computations Using MATLAB phần 5 pptx

Engineering and Scientific Computations Using MATLAB phần 5 pptx

Engineering and Scientific Computations Using MATLAB phần 5 pptx

... 2.8794 20.8627 57 .6 956 The three volumes are found to be 2.8794,20.8627, and 57 .6 956 . Chapter 3: MATLAB and Problem Solving 83 Example 3.6.7. Use linspace and apply the increment ... 5y - 72 = - 26 - 5x + 2y + 6z= 14 b. 12x-5y= 11 - 3x +4y + 7z= - 3 2 .5% + 5x3 + XI - 2x2=,4 6x+2y+3z=22 25x2 - 6.2~~ + 18% + 1 Oxl = 2.9 C....
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Engineering and Scientific Computations Using MATLAB phần 2 pot

Engineering and Scientific Computations Using MATLAB phần 2 pot

... and Commands Symbol MATLAB Statement + atbtc - a-b-c * and .* a*b*c and a. *b. *c / and ./ a/b anda./b \ and. \ b\a (equivalent to a/b) and b . \a A and .A aAb anda.”b ... now that MATLAB has demonstration programs. One should use Close MATLAB using the Exit MATLAB (Ctrl+Q) command in the MATLAB Command Window (File menu). MATLAB Menu...
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Engineering and Scientific Computations Using MATLAB phần 3 ppt

Engineering and Scientific Computations Using MATLAB phần 3 ppt

... double-clicking the MATLAB icon: MATLAB 6 .5. lnk The MATLAB Command and Workspace windows appear as shown in Figure 3.1. Figure 3.1. MATLAB Command and Workspace windows The line Thus, aa=2, and Figure ... 3: MATLAB and Problem Solving 57 Chapter 3: MATLAB and Problem Solving 42 Chapter 3 MATLAB and Problem Solving 3.1. Starting MATLAB As we saw...
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Engineering and Scientific Computations Using MATLAB phần 4 ppt

Engineering and Scientific Computations Using MATLAB phần 4 ppt

... R=ones (5) +O. l*rand (&apos ;5) R= 1. 058 3 1.0226 1.0209 1. 056 8 1.04 15 1.0423 1. 058 0 1.0380 1.0794 1.03 05 1. 051 6 1.0760 1.0783 1.0 059 1.0874 1.0334 1. 053 0 1.0681 1.0603 1.00 15 1.0433 ... 6.1922e-001 +5. 1377e-0011 6.1922e-001 -5. 1377e-001i -7. 158 7e-001 +2.1 656 e-O01i -7. 158 7e-001 -2.1 656 e-001i -4.6895e-001 +5. 5966e-O01i -4.6895e-001 -5. 5966e-001...
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Engineering and Scientific Computations Using MATLAB phần 6 ppt

Engineering and Scientific Computations Using MATLAB phần 6 ppt

... X Calculate functions f, (x) = - and f,(x) = if -55 x 55. 1 fX4 1 +sin x + x Solution. We have the folowing statement: >> x 5: 0. 25: 5; fl-x. =x, / (l+sin (x) +x. ^4) ... plot is documented in Figure 4.29. 0 5 10 15 20 25 30 35 40 Figure 4.29. Plots of functions x(n) = 25cos(m f5)e-O." Chapter 4: MATLAB Graphics 121 1 -r-j...
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Engineering and Scientific Computations Using MATLAB phần 7 pps

Engineering and Scientific Computations Using MATLAB phần 7 pps

... ; % converter parameters rs=0.0 25; rl=0. 05; rc=0. 05; ra=2 .5; C=O.O5; L=O.O 05; La=0. 05; % voltage applied, back emf and duty ratio Vd =50 ; Ea =5; D=0 .5; % three differential equations to ... 5. 3 and 5. 4. MATLAB script with a set of differential equations to be solved (c5-1-lb. m): Solution of Differential Equations xl, x2 and x3 I-, -~ 7 15 10 5...
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Engineering and Scientific Computations Using MATLAB phần 8 pps

Engineering and Scientific Computations Using MATLAB phần 8 pps

... - &-dm + 5 -wo * Chapter 5 MATLAB Applications - + L 167 kd c - 25 - 05 1 15 2 25 0 0&apos ;5 4 1&apos ;5 2 2&apos ;5 3 3&apos ;5 4 4&apos ;5 !5 OC . ' ... = -5 ' ) i pretty (x) 1/2 2 /5 %2 sin(%4) - 2 /5 $2 sin(%3) - 2 /5 Sil cos(%4) - 2 /55 %1 sin(%3) 11 1/2 1/2 1/2 1/2 + 2 /55 %1 sin(%4) 11 + 2...
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Engineering and Scientific Computations Using MATLAB phần 9 potx

Engineering and Scientific Computations Using MATLAB phần 9 potx

... One can learn and explore SIMIJLMK using the SIMULINK and MATLAB Demos. Users who do not have enough experience within SIMULINK will find a great deal of help using these MATLAB and SIMULINK ... Case 2: k= 100 and kl= 1; Case 3: k = 100 and kl= 0. Chapter 6: SIMULINK 1 85 6.2. Engineering and Scientific Computations Using SIMULINK with Examp...
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Engineering and Scientific Computations Using MATLAB phần 10 docx

Engineering and Scientific Computations Using MATLAB phần 10 docx

... Circuit, 144, 1 45, 154 - 157 , 159 -161, 167-1 65 Clear, 24 Color operation, 103,2 1 5 Command window, 5, 8,43-46 Commands, 32-4 I Conditions, 73-79 Control flow, 208 Converter, 1 45- 15 1 Debugging, ... -50 -100 - 150 1 -200L L ' 0 0. 05 0.1 0. 15 0.2 0. 25 0.3 0. 35 0.4 lime (seconds) Stator current ics. [A] 2w( I:, -2WlY , I_ I 1 0 0....
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